Question Number 8387 by arinto27 last updated on 09/Oct/16 Answered by ridwan balatif last updated on 10/Oct/16 $$\mathrm{1}.\mathrm{f}\left(\mathrm{x}\right)=\mathrm{5x}+\mathrm{1} \\ $$$$\:\:\:\:\:\:\mathrm{y}\:\:\:=\mathrm{5x}+\mathrm{1} \\ $$$$\:\:\:\:\:\:\mathrm{x}\:\:\:=\frac{\mathrm{y}−\mathrm{1}}{\mathrm{5}} \\ $$$$\mathrm{f}^{−\mathrm{1}} \left(\mathrm{x}\right)=\frac{\mathrm{x}−\mathrm{1}}{\mathrm{5}}\Leftrightarrow\mathrm{f}^{−\mathrm{1}}…
Question Number 139456 by SOMEDAVONG last updated on 27/Apr/21 $$\mathrm{E}=\mathrm{log}_{\mathrm{a}} \sqrt{\frac{\mathrm{c}}{\mathrm{b}^{\mathrm{log}_{\mathrm{ab}} \mathrm{c}} }}+\mathrm{log}_{\mathrm{b}} \sqrt{\frac{\mathrm{c}}{\mathrm{a}^{\mathrm{log}_{\mathrm{ab}} \mathrm{c}} }} \\ $$ Answered by bemath last updated on 27/Apr/21…
Question Number 73909 by Pk1167156@gmail.com last updated on 16/Nov/19 Commented by Pk1167156@gmail.com last updated on 16/Nov/19 $${slution}\:{plz}… \\ $$ Answered by arkanmath7@gmail.com last updated on…
Question Number 8367 by Nayon last updated on 09/Oct/16 Answered by Nayon last updated on 09/Oct/16 Answered by Nayon last updated on 09/Oct/16 Terms of…
Question Number 8368 by Nayon last updated on 09/Oct/16 $$ \\ $$$${prove} \\ $$$$\pi=\frac{\mathrm{6}}{\:\sqrt{\mathrm{3}}}×\underset{{x}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{{x}+\mathrm{1}} }{\left(\mathrm{2}{x}−\mathrm{1}\right)×\mathrm{3}^{{x}−\mathrm{1}} } \\ $$$$ \\ $$ Answered by Nayon…
Question Number 73901 by azizullah last updated on 16/Nov/19 Answered by $@ty@m123 last updated on 16/Nov/19 $$\mathrm{42}\:{m} \\ $$ Commented by azizullah last updated on…
Question Number 73896 by liki last updated on 16/Nov/19 Commented by liki last updated on 16/Nov/19 $$…{Anyone}\:{to}\:{assist}\:{me}.. \\ $$ Answered by mr W last updated…
Question Number 139424 by mohammad17 last updated on 26/Apr/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 139419 by mathocean1 last updated on 26/Apr/21 $${ABCD}\:{is}\:{a}\:{rectangle}\:{such}\:{that}\: \\ $$$${AD}=\mathrm{2}{AB}\:{and}\:{its}\:{center}\:{is}\:{O}.\: \\ $$$${H}\:{is}\:{the}\:{top}\:{of}\:{a}\:{pyramid}\:{which} \\ $$$${has}\:{ABCD}\:{as}\:{base}.\:{All}\:{lateral} \\ $$$${faces}\:{are}\:{isosceles}\:{triangles}.\:{planes} \\ $$$$\left({HAB}\right)\:{and}\:\left({HCD}\right)\:{are}\:\bot. \\ $$$${i}\:{have}\:{joined}\:{a}\:{graphic}. \\ $$$$\mathrm{1}.\:{show}\:{that}\:\left({OH}\right)\bot\left({ABC}\right). \\…
Question Number 139414 by mathdanisur last updated on 26/Apr/21 $$\underset{\:\mathrm{0}} {\overset{\:\pi/\mathrm{2}} {\int}}\frac{{cos}^{\mathrm{2}} {x}}{{cos}\left({x}−\pi/\mathrm{4}\right)}\:{dx} \\ $$ Commented by mr W last updated on 27/Apr/21 $$\frac{\mathrm{1}}{\mathrm{2}}\left[\mathrm{ln}\:\frac{\mathrm{1}+\mathrm{sin}\:\left({x}−\frac{\pi}{\mathrm{4}}\right)}{\mathrm{1}−\mathrm{sin}\:\left({x}−\frac{\pi}{\mathrm{4}}\right)}\right]_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}}…