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In-an-entrance-examination-each-question-has-four-possible-answers-A-candidate-answers-three-question-by-guessing-a-find-the-probability-that-all-three-questions-are-wrong-b-find-the-probabili

Question Number 139697 by otchereabdullai@gmail.com last updated on 30/Apr/21 $$\mathrm{In}\:\mathrm{an}\:\mathrm{entrance}\:\mathrm{examination}\:\mathrm{each}\: \\ $$$$\mathrm{question}\:\mathrm{has}\:\mathrm{four}\:\mathrm{possible}\:\mathrm{answers}. \\ $$$$\mathrm{A}\:\mathrm{candidate}\:\mathrm{answers}\:\mathrm{three}\:\mathrm{question} \\ $$$$\mathrm{by}\:\mathrm{guessing}\:. \\ $$$$\mathrm{a}.\:\mathrm{find}\:\mathrm{the}\:\mathrm{probability}\:\mathrm{that}\:\mathrm{all}\:\mathrm{three}\: \\ $$$$\mathrm{questions}\:\mathrm{are}\:\mathrm{wrong}. \\ $$$$\mathrm{b}.\:\mathrm{find}\:\mathrm{the}\:\mathrm{probability}\:\mathrm{that}\:\mathrm{all}\:\mathrm{the}\: \\ $$$$\mathrm{questions}\:\mathrm{are}\:\mathrm{correct}. \\…

2x-4x-find-x-

Question Number 139690 by hawa last updated on 30/Apr/21 $$\mathrm{2}{x}=\mathrm{4}{x}\:{find}\:{x} \\ $$ Commented by Rasheed.Sindhi last updated on 30/Apr/21 $$\mathrm{4}{x}−\mathrm{2}{x}=\mathrm{0} \\ $$$$\mathrm{2}{x}=\mathrm{0} \\ $$$${x}=\mathrm{0}/\mathrm{2}=\mathrm{0} \\…

Test-1-1-1-1-1-1-i-i-i-2-1-so-1-1-Find-the-error-

Question Number 8600 by Chantria last updated on 17/Oct/16 $$\:\boldsymbol{{Test}}\: \\ $$$$\:\mathrm{1}=\sqrt{\mathrm{1}}=\sqrt{\left(−\mathrm{1}\right)\left(−\mathrm{1}\right)}=\sqrt{−\mathrm{1}}\centerdot\sqrt{−\mathrm{1}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:={i}\centerdot{i}={i}^{\mathrm{2}} =−\mathrm{1} \\ $$$$\:\:{so}\:\mathrm{1}=−\mathrm{1} \\ $$$$\:{Find}\:{the}\:{error}. \\ $$ Commented by prakash jain…

Question-139655

Question Number 139655 by mohammad17 last updated on 30/Apr/21 Answered by qaz last updated on 30/Apr/21 $$\int_{\mathrm{0}} ^{\mathrm{1}} {x}\mathrm{tan}^{−\mathrm{1}} \left({x}\right){ln}\left({x}^{\mathrm{2}} +\mathrm{1}\right){dx} \\ $$$$=\frac{\mathrm{1}}{\mathrm{2}}\int_{\mathrm{0}} ^{\mathrm{1}} \mathrm{tan}^{−\mathrm{1}}…

Question-139645

Question Number 139645 by otchereabdullai@gmail.com last updated on 30/Apr/21 Commented by mr W last updated on 30/Apr/21 $${OD}={AO}×\mathrm{sin}\:\angle{OAB}=\mathrm{52}×\frac{\mathrm{5}}{\mathrm{13}}=\mathrm{20} \\ $$$${BD}=\sqrt{\mathrm{25}^{\mathrm{2}} −\mathrm{20}^{\mathrm{2}} }=\mathrm{15} \\ $$$${BC}=\mathrm{2}×{BD}=\mathrm{2}×\mathrm{15}=\mathrm{30} \\…