Question Number 131110 by mohammad17 last updated on 01/Feb/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 131107 by ZiYangLee last updated on 01/Feb/21 $$\mathrm{Solve}\:\mathrm{sin}^{−\mathrm{1}} {x}+\mathrm{sin}^{−\mathrm{1}} \frac{{x}}{\mathrm{2}}=\frac{\mathrm{2}\pi}{\mathrm{3}} \\ $$ Answered by mr W last updated on 01/Feb/21 $${let}\:{t}=\frac{{x}}{\mathrm{2}}>\mathrm{0} \\ $$$$\mathrm{sin}^{−\mathrm{1}}…
Question Number 131099 by mohammad17 last updated on 01/Feb/21 Commented by mohammad17 last updated on 01/Feb/21 $${how}\:{can}\:{solve}\:{this} \\ $$$$ \\ $$ Answered by mr W…
Question Number 13012 by tawa tawa last updated on 10/May/17 $${Sir}.\:{MRV}\:\:{please}\:\mathrm{i}\:\mathrm{need}\:{the}\:\mathrm{cubic}\:\mathrm{equation}\:\mathrm{formular}.\:\:\mathrm{my}\:\mathrm{phone}\:\mathrm{has}\:\mathrm{fault} \\ $$$$\mathrm{and}\:\mathrm{i}\:\mathrm{just}\:\mathrm{restore}\:\mathrm{it}.\:\mathrm{please}\:\mathrm{help}\:\mathrm{me}\:\mathrm{re}\:\mathrm{send}\:\mathrm{it}.\:\mathrm{i}\:\mathrm{really}\:\mathrm{appreciate}\:\mathrm{your}\:\mathrm{effort} \\ $$$$\mathrm{sir}.\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$ Commented by mrW1 last updated on 10/May/17 Commented…
Question Number 13011 by sandy_suhendra last updated on 10/May/17 $$\mathrm{li}\underset{\mathrm{x}\rightarrow\infty} {\mathrm{m}}\left[\mathrm{5}^{\mathrm{x}} \:+\:\mathrm{5}^{\mathrm{3x}} \right]^{\frac{\mathrm{1}}{\mathrm{x}}} \:=\:? \\ $$$$\mathrm{please}\:\mathrm{help} \\ $$ Answered by sma3l2996 last updated on 10/May/17…
Question Number 144069 by SOMEDAVONG last updated on 21/Jun/21 $$\mathrm{I}=\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \frac{\mathrm{2304cosx}}{\left(\mathrm{cos4x}−\mathrm{8cos2x}+\mathrm{15}\right)^{\mathrm{2}} }\mathrm{dx}=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 144068 by SOMEDAVONG last updated on 21/Jun/21 $$\mathrm{S}_{\mathrm{2019}} =\mathrm{1}+\:\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{2}} }\:+\:\frac{\mathrm{1}}{\mathrm{3}^{\mathrm{2}} }\:+\:…+\:\frac{\mathrm{1}}{\mathrm{2019}^{\mathrm{2}} }\:=? \\ $$ Answered by Olaf_Thorendsen last updated on 21/Jun/21 $$\mathrm{S}_{\mathrm{2019}} \:=\:\underset{{n}=\mathrm{1}}…
Question Number 144061 by Khalmohmmad last updated on 21/Jun/21 Answered by TheHoneyCat last updated on 21/Jun/21 $$\mathrm{I}\:\mathrm{am}\:\mathrm{quite}\:\mathrm{sorry}\:\mathrm{to}\:\mathrm{tell}\:\mathrm{you}\:\mathrm{this},\:\mathrm{but}\:\mathrm{your}\:\mathrm{question}\:\mathrm{is}\:\mathrm{either} \\ $$$$\mathrm{incomplete}\:\left(\mathrm{some}\:\mathrm{hypothesis}\:\mathrm{is}\:\mathrm{missing}\right) \\ $$$$\mathrm{or}\:\mathrm{unsolvable}. \\ $$$$ \\ $$$$\mathrm{Consider}:…
Question Number 144067 by SOMEDAVONG last updated on 21/Jun/21 $$\mathrm{L}=\underset{\mathrm{n}\rightarrow+\propto} {\mathrm{lim}}\left(\frac{\mathrm{1}^{\mathrm{2}} }{\mathrm{n}^{\mathrm{3}} +\mathrm{1}^{\mathrm{3}} }\:+\:\frac{\mathrm{2}^{\mathrm{3}} }{\mathrm{n}^{\mathrm{3}} +\mathrm{2}^{\mathrm{3}} }\:+\:…+\:\frac{\mathrm{n}^{\mathrm{3}} }{\mathrm{n}^{\mathrm{3}} +\mathrm{n}^{\mathrm{3}} }\right)=? \\ $$ Answered by Dwaipayan…
Question Number 144060 by Khalmohmmad last updated on 21/Jun/21 $${p}\left({x}\right)=\left({x}−\mathrm{1}\right)^{\mathrm{2}} {Q}\left({x}\right)+\mathrm{3}{x}+\mathrm{8} \\ $$$${p}\left({x}\right)=\left({x}−\mathrm{2}\right){Q}\left({x}\right)+{R} \\ $$$${R}=? \\ $$ Commented by Rasheed.Sindhi last updated on 21/Jun/21 $${Q}\left({x}\right)\:{is}\:{same}\:{in}\:{both}\:{cases}!!!?…