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Question Number 138362 by mohammad17 last updated on 12/Apr/21 $${prove}\:{that}\: \\ $$$$ \\ $$$$\left(\mathrm{1}+{i}\right)^{{n}} +\left(\mathrm{1}−{i}\right)^{{n}} =\mathrm{2}^{\frac{{n}+\mathrm{1}}{\mathrm{2}}} \\ $$ Commented by Dwaipayan Shikari last updated on…

Question Number 138350 by abenarhodym last updated on 12/Apr/21 $$\sqrt{\mathrm{2}}\left(\sqrt{\mathrm{8}}−\frac{\mathrm{2}}{\:\sqrt{\mathrm{8}}}\right) \\ $$ Answered by Ñï= last updated on 12/Apr/21 $$\sqrt{\mathrm{2}}\left(\sqrt{\mathrm{8}}−\frac{\mathrm{2}}{\:\sqrt{\mathrm{8}}}\right)=\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{2}}} \left(\mathrm{2}^{\frac{\mathrm{3}}{\mathrm{2}}} −\mathrm{2}^{\mathrm{1}−\frac{\mathrm{3}}{\mathrm{2}}} \right)=\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{3}}{\mathrm{2}}} −\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{2}}−\frac{\mathrm{1}}{\mathrm{2}}} =\mathrm{2}^{\mathrm{2}}…

Question Number 138338 by mohammad17 last updated on 12/Apr/21 Commented by mohammad17 last updated on 12/Apr/21 $${help}\:{me}\:{sirlease} \\ $$ Answered by mr W last updated…

Question Number 72787 by Maclaurin Stickker last updated on 02/Nov/19 $${If}\:{z}_{\mathrm{1}} =\mathrm{6}\left(\mathrm{cos}\:\frac{\pi}{\mathrm{4}}+\mathrm{sin}\:\frac{\pi}{\mathrm{4}}\right)\:{and} \\ $$$${z}_{\mathrm{2}} =\mathrm{2}\left(\mathrm{cos}\:\frac{\pi}{\mathrm{5}}+\mathrm{i}×\mathrm{sin}\:\frac{\pi}{\mathrm{5}}\right)\:{calculate}\:\frac{{z}_{\mathrm{1}} }{{z}_{\mathrm{2}} }. \\ $$ Commented by MJS last updated on…

Question Number 72782 by Mr. K last updated on 02/Nov/19 Commented by Mr. K last updated on 02/Nov/19 $${Find}\:{a},\:{b}\:{and}\:{c} \\ $$ Answered by MJS last…