Question Number 8234 by sandy_suhendra last updated on 03/Oct/16 $$\mathrm{Question}\::\:\mathrm{figure}\:\mathrm{x}\:\mathrm{for} \\ $$$$\sqrt{\mathrm{x}−\mathrm{4}}\:>\:\mathrm{6}−\mathrm{x} \\ $$$$\mathrm{my}\:\mathrm{answer}\:: \\ $$$$\left(\mathrm{1}\right)\:\:\:\mathrm{x}−\mathrm{4}\:>\:\left(\mathrm{6}−\mathrm{x}\right)^{\mathrm{2}} \\ $$$$\:\:\:\:\:\:\left(\mathrm{x}−\mathrm{5}\right)\left(\mathrm{x}−\mathrm{8}\right)\:<\:\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{5}<\mathrm{x}<\mathrm{8} \\ $$$$ \\ $$$$\left(\mathrm{2}\right)\:\:\:\mathrm{x}−\mathrm{4}\:\geqslant\:\mathrm{0} \\…
Question Number 139296 by mohammad17 last updated on 25/Apr/21 $$\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{\sqrt{{x}}}{\:\sqrt{\mathrm{1}−{x}}+\sqrt{{x}}}{dx} \\ $$ Answered by qaz last updated on 25/Apr/21 $$\int_{\mathrm{0}} ^{\mathrm{1}} \frac{\sqrt{{x}}}{\:\sqrt{\mathrm{1}−{x}}+\sqrt{{x}}}{dx}=\int_{\mathrm{0}} ^{\mathrm{1}}…
Question Number 73757 by Maclaurin Stickker last updated on 15/Nov/19 $$\mathrm{cos}\:\mathrm{70}°+\mathrm{sin}\:\mathrm{200}°=? \\ $$ Commented by mathmax by abdo last updated on 15/Nov/19 $$\mathrm{70}^{{o}} =\frac{\mathrm{70}\pi}{\mathrm{180}}\:=\frac{\mathrm{7}\pi}{\mathrm{18}}\:\:\:{and}\:\mathrm{200}^{{o}} =\frac{\mathrm{200}\pi}{\mathrm{180}}\:=\frac{\mathrm{20}\pi}{\mathrm{18}}\:\Rightarrow…
Question Number 139288 by 7770 last updated on 25/Apr/21 $$\boldsymbol{{IF}}\:\frac{\boldsymbol{{x}}^{\mathrm{3}} +\mathrm{1}}{\boldsymbol{{x}}^{\mathrm{2}} −\mathrm{1}}=\boldsymbol{{x}}+\sqrt{\frac{\mathrm{6}}{\boldsymbol{{x}}}} \\ $$$$\mathrm{6}\boldsymbol{{x}}^{\mathrm{2}} −\mathrm{5}\boldsymbol{{x}}+\mathrm{4}=?? \\ $$ Answered by MJS_new last updated on 25/Apr/21 $$\frac{\left({x}+\mathrm{1}\right)\left({x}^{\mathrm{2}}…
Question Number 139285 by mohammad17 last updated on 25/Apr/21 $$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} {sin}^{\mathrm{2}} \left({x}\right){cos}^{\mathrm{6}} \left({x}\right){dx} \\ $$ Answered by qaz last updated on 25/Apr/21 $$\int_{\mathrm{0}} ^{\pi/\mathrm{2}}…
Question Number 73722 by azizullah last updated on 15/Nov/19 Commented by TawaTawa last updated on 15/Nov/19 $$\mathrm{Kamal}\:\:=\:\:\mathrm{x} \\ $$$$\mathrm{Ali}\:\:=\:\:\mathrm{x}\:+\:\mathrm{50} \\ $$$$\mathrm{Total}\:\:=\:\:\mathrm{150} \\ $$$$\therefore\:\:\:\:\:\mathrm{x}\:+\:\mathrm{x}\:+\:\mathrm{50}\:\:=\:\:\mathrm{150} \\ $$$$\therefore\:\:\:\:\:\mathrm{2x}\:+\:\mathrm{50}\:\:=\:\:\mathrm{150}…
Question Number 139257 by bobhans last updated on 25/Apr/21 $$\:\:\:\:\underset{\mathrm{k}=\mathrm{1}} {\overset{\infty} {\sum}}\:\frac{\left(−\mathrm{1}\right)^{\mathrm{k}} \left(\mathrm{2k}−\mathrm{1}\right)}{\mathrm{k}^{\mathrm{2}} }\:=? \\ $$ Answered by john_santu last updated on 25/Apr/21 $$\:\:\:\:\underset{{k}=\mathrm{1}} {\overset{\infty}…
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Question Number 8151 by trapti rathaur@ gmail.com last updated on 02/Oct/16 $${what}\:{is}\:\:{rectangular}\:\:\:{paralleopiped}? \\ $$ Answered by sandy_suhendra last updated on 02/Oct/16 Commented by sandy_suhendra last…
Question Number 139198 by otchereabdullai@gmail.com last updated on 24/Apr/21 Terms of Service Privacy Policy Contact: info@tinkutara.com