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f-x-1-1-x-1-1-a-ax-ax-8-x-0-a-0-show-1-lt-f-x-lt-2-

Question Number 138316 by Ñï= last updated on 12/Apr/21 $${f}\left({x}\right)=\frac{\mathrm{1}}{\:\sqrt{\mathrm{1}+{x}}}+\frac{\mathrm{1}}{\:\sqrt{\mathrm{1}+{a}}}+\sqrt{\frac{{ax}}{{ax}+\mathrm{8}}}\:\:\:\:\:\:\:\:,{x}\in\left(\mathrm{0},\infty\right) \\ $$$$\forall\:{a}\in\left(\mathrm{0},\infty\right),{show}\:\mathrm{1}<{f}\left({x}\right)<\mathrm{2}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

n-0-1-5n-

Question Number 72746 by aliesam last updated on 01/Nov/19 $$\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{\left(\mathrm{5}{n}\right)!} \\ $$ Answered by mind is power last updated on 01/Nov/19 $$\mathrm{1}+\mathrm{z}+\mathrm{z}^{\mathrm{2}} +\mathrm{z}^{\mathrm{3}}…

x-2-10x-6-x-2-gt-1-

Question Number 138250 by sahnaz last updated on 11/Apr/21 $$\left(\mathrm{x}^{\mathrm{2}} −\mathrm{10x}+\mathrm{6}\right)^{\mathrm{x}−\mathrm{2}} >\mathrm{1} \\ $$ Answered by bobhans last updated on 11/Apr/21 $$\left({x}^{\mathrm{2}} −\mathrm{10}{x}+\mathrm{6}\right)^{{x}−\mathrm{2}} \:>\:\left({x}^{\mathrm{2}} −\mathrm{10}{x}+\mathrm{6}\right)^{\mathrm{0}}…