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Prove-that-for-any-acute-angle-sec-cosec-tan-cot-4-

Question Number 8105 by 314159 last updated on 30/Sep/16 $${Prove}\:{that}\:,{for}\:{any}\:{acute}\:{angle}\:\alpha\: \\ $$$${sec}\alpha\:{cosec}\alpha\:+{tan}\alpha\:+{cot}\alpha\:\geqslant\mathrm{4}. \\ $$ Commented by Yozzia last updated on 30/Sep/16 $${f}\left({x}\right)=\frac{\mathrm{1}}{{cosxsinx}}+\frac{{sinx}}{{cosx}}+\frac{{cosx}}{{sinx}} \\ $$$${f}\left({x}\right)=\frac{\mathrm{1}}{{cosxsinx}}+\frac{\mathrm{1}}{{sinxcosx}} \\…

App-has-been-updated-ver-1-48-Customizable-key-screen-long-press-on-any-key-on-that-screen-to-change-the-symbol-on-that-location-Choose-default-font-size-and-style-option-menu-for-

Question Number 8093 by Tinku Tara last updated on 30/Sep/16 $$\mathrm{App}\:\mathrm{has}\:\mathrm{been}\:\mathrm{updated}\:\left(\mathrm{ver}\:\mathrm{1}.\mathrm{48}\right) \\ $$$$\bullet\:\mathrm{Customizable}\:\mathrm{key}\:\mathrm{screen}\:\bigstar \\ $$$$\:\:\:\:\mathrm{long}\:\mathrm{press}\:\mathrm{on}\:\mathrm{any}\:\mathrm{key}\:\mathrm{on}\:\mathrm{that}\:\mathrm{screen} \\ $$$$\:\:\:\:\mathrm{to}\:\mathrm{change}\:\mathrm{the}\:\mathrm{symbol}\:\mathrm{on}\:\mathrm{that}\:\mathrm{location} \\ $$$$\bullet\:\:\mathrm{Choose}\:\mathrm{default}\:\mathrm{font}\:\mathrm{size}\:\mathrm{and}\:\mathrm{style} \\ $$$$\bullet\:\:\mathrm{option}\:\mathrm{menu}\:\mathrm{for}\:\mathrm{quicker}\:\mathrm{access}\:\mathrm{to}\:\mathrm{long} \\ $$$$\:\:\:\:\:\mathrm{press}\:\mathrm{menu} \\ $$$$\bullet\:\:\:\mathrm{new}\:\mathrm{symbols}\:\mathrm{and}\:\mathrm{right}\:\mathrm{curly}\:\mathrm{brace}\:\mathrm{matrix}…

Question-8073

Question Number 8073 by 314159 last updated on 29/Sep/16 Commented by 123456 last updated on 30/Sep/16 $$\mathrm{cosh}\left({x}\right)=\frac{{e}^{{x}} +{e}^{−{x}} }{\mathrm{2}} \\ $$$${x}^{\mathrm{4}} +{x}^{−\mathrm{4}} =\mathrm{47} \\ $$$${x}={e}^{{t}}…

x-2-x-2-x-36-find-x-

Question Number 139124 by 7770 last updated on 22/Apr/21 $${x}^{\mathrm{2}} +{x}−\mathrm{2}\sqrt{{x}}=\mathrm{36} \\ $$$$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{x}} \\ $$ Answered by MJS_new last updated on 22/Apr/21 $$\mathrm{you}\:\mathrm{can}\:\mathrm{only}\:\mathrm{approximate}.\:\mathrm{I}\:\mathrm{get} \\ $$$${x}\approx\mathrm{5}.\mathrm{91193369}…

i-ask-all-of-you-not-to-answer-any-question-from-www-amirley-or-something-like-this-best-azodbek-or-something-like-this-this-guy-is-not-to-help-he-misuses-your-help-and-deletes-his-posts-

Question Number 73595 by mr W last updated on 13/Nov/19 $${i}\:{ask}\:{all}\:{of}\:{you}\:{not}\:{to}\:{answer}\:{any} \\ $$$${question}\:{from}\:{www} \\ $$$$\left(\:=\:{amirley}\:{or}\:{something}\:{like}\:{this}\right) \\ $$$$\left(=\:{best}\right) \\ $$$$\left(={azodbek}\:{or}\:{something}\:{like}\:{this}\right) \\ $$$${this}\:{guy}\:{is}\:{not}\:{to}\:{help}!\:{he}\:{misuses} \\ $$$${your}\:{help}\:{and}\:{deletes}\:{his}\:{posts}\:{as} \\ $$$${soon}\:{as}\:{you}\:{have}\:{answered}\:{them}.…

give-a-b-c-gt-0-if-a-b-and-b-c-prove-a-c-

Question Number 73553 by 01 last updated on 13/Nov/19 $$\mathrm{give}:\:\mathrm{a},\mathrm{b},\mathrm{c}>\mathrm{0} \\ $$$$\mathrm{if}\:\mathrm{a}\mid\mathrm{b}\:\mathrm{and}\:\mathrm{b}\mid\mathrm{c} \\ $$$$\mathrm{prove}\::\:\mathrm{a}\mid\mathrm{c} \\ $$ Answered by Rio Michael last updated on 13/Nov/19 $${a}\mid{b}\:\Leftrightarrow\:\exists\:{k}\in\mathbb{Z}\::\:\:{b}\:=\:{ka}\:……\left({i}\right)…

Feedback-request-Any-symbols-that-needs-to-be-added-We-are-aware-of-the-following-which-will-be-added-in-next-update-vertical-dots-contour-integral-is-congurant-to-Pleas

Question Number 7988 by Tinku Tara last updated on 26/Sep/16 $$\boldsymbol{\mathrm{Feedback}}\:\boldsymbol{\mathrm{request}} \\ $$$$\bullet\:\mathrm{Any}\:\mathrm{symbols}\:\mathrm{that}\:\mathrm{needs}\:\mathrm{to}\:\mathrm{be} \\ $$$$\:\:\:\:\mathrm{added}.\:\mathrm{We}\:\mathrm{are}\:\mathrm{aware}\:\mathrm{of}\:\mathrm{the}\:\mathrm{following} \\ $$$$\:\:\:\:\mathrm{which}\:\mathrm{will}\:\mathrm{be}\:\mathrm{added}\:\mathrm{in}\:\mathrm{next}\:\mathrm{update}: \\ $$$$\:\:\:\:-\:\mathrm{vertical}\:\mathrm{dots}\: \\ $$$$\:\:\:\:-\:\mathrm{contour}\:\mathrm{integral} \\ $$$$\:\:\:\:-\:\mathrm{is}\:\mathrm{congurant}\:\mathrm{to} \\ $$$$\mathrm{Please}\:\mathrm{let}\:\mathrm{us}\:\mathrm{know}\:\mathrm{any}\:\mathrm{symbols}…