Question Number 7164 by aftab ahmad last updated on 14/Aug/16 Answered by Yozzia last updated on 14/Aug/16 $${By}\:{Power}\:{of}\:{a}\:{Point}\:{theorem}, \\ $$$$\left({AB}\right)\left({AC}\right)=\left({AD}\right)\left({AD}\right)=\left({AD}\right)^{\mathrm{2}} \\ $$$$\Rightarrow{AC}=\frac{\left({AD}\right)^{\mathrm{2}} }{{AB}}=\frac{\mathrm{10}^{\mathrm{2}} }{\mathrm{5}}=\mathrm{20}{cm} \\…
Question Number 7159 by Master Moon last updated on 14/Aug/16 $$\boldsymbol{{log}}_{\mathrm{2}} \underset{\boldsymbol{{x}}=\mathrm{1}} {\overset{\mathrm{2015}} {\prod}}\:\underset{\boldsymbol{{y}}=\mathrm{1}} {\overset{\mathrm{2015}} {\prod}}\left(\mathrm{1}+\boldsymbol{{e}}^{\frac{\mathrm{2}\boldsymbol{\pi{ixy}}}{\mathrm{2015}}} \right)\:=\:? \\ $$ Commented by FilupSmith last updated on…
Question Number 138217 by otchereabdullai@gmail.com last updated on 11/Apr/21 $$\mathrm{A}\:\mathrm{rectangular}\:\mathrm{water}\:\mathrm{tank}\:\mathrm{is}\:\mathrm{being}\:\mathrm{filed} \\ $$$$\mathrm{at}\:\mathrm{the}\:\mathrm{constant}\:\mathrm{rate}\:\mathrm{of}\:\mathrm{70lt}/\mathrm{s}.\:\mathrm{The}\: \\ $$$$\mathrm{base}\:\:\mathrm{of}\:\mathrm{the}\:\mathrm{tank}\:\mathrm{has}\:\mathrm{width}\:\mathrm{w}=\mathrm{9m} \\ $$$$\mathrm{and}\:\mathrm{length}\:\mathrm{length}\:\mathrm{l}=\mathrm{16m}\:\mathrm{if}\:\mathrm{the}\:\mathrm{volume} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{tank}\:\mathrm{is}\:\mathrm{v}=\mathrm{w}×\mathrm{l}×\mathrm{h}\:\mathrm{where}\:\mathrm{h}\:\mathrm{is}\: \\ $$$$\mathrm{the}\:\mathrm{hight}\:\mathrm{of}\:\mathrm{the}\:\mathrm{tank}.\:\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{rate} \\ $$$$\mathrm{of}\:\mathrm{change}\:\mathrm{of}\:\mathrm{the}\:\mathrm{hight}\:\mathrm{of}\:\mathrm{water}\:\mathrm{in}\:\mathrm{the} \\ $$$$\mathrm{tank} \\…
Question Number 7149 by Master Moon last updated on 13/Aug/16 $$\mathrm{Find}\:\mathrm{last}\:\mathrm{digit}\:\mathrm{P} \\ $$$$\:\mathrm{P}=\left(\mathrm{2017}^{\boldsymbol{\mathrm{k}}} +\mathrm{2016}\right)\left(\mathrm{2016}^{\boldsymbol{\mathrm{m}}} +\mathrm{2015}\right)\left(\mathrm{2015}^{\boldsymbol{\mathrm{n}}} +\mathrm{2014}\right) \\ $$$$\mathrm{where}\:\boldsymbol{\mathrm{k}},\boldsymbol{\mathrm{m}},\boldsymbol{\mathrm{n}}\in{N} \\ $$$$\:\:\:\: \\ $$$$\:\:\:\:{Help}\:{me}!!! \\ $$ Terms…
Question Number 7145 by 314159 last updated on 13/Aug/16 Commented by Rasheed Soomro last updated on 13/Aug/16 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 138219 by otchereabdullai@gmail.com last updated on 11/Apr/21 $$\:\mathrm{Consider}\:\mathrm{the}\:\mathrm{function}\:\mathrm{y}=\frac{\mathrm{x}^{\mathrm{2}} +\mathrm{3x}+\mathrm{6}}{\mathrm{3x}−\mathrm{1}} \\ $$$$\left.\mathrm{1}\right)\:\mathrm{Determine}\:\mathrm{the}\:\mathrm{intercept}\:\mathrm{of}\:\mathrm{the}\:\mathrm{function} \\ $$$$\left.\mathrm{2}\right)\:\mathrm{Find}\:\mathrm{the}\:\mathrm{asymptotes}\:\mathrm{if}\:\mathrm{they}\:\mathrm{exist} \\ $$$$\left.\mathrm{3}\right)\:\mathrm{find}\:\mathrm{the}\:\mathrm{turning}\:\mathrm{point}\:\mathrm{and}\: \\ $$$$\mathrm{determine}\:\mathrm{the}\:\mathrm{type}\:\mathrm{of}\:\mathrm{turnin}\:\mathrm{point}\:\mathrm{they} \\ $$$$\mathrm{are}. \\ $$$$\left.\mathrm{4}\right)\:\mathrm{sketch}\:\mathrm{the}\:\mathrm{graph}\:\mathrm{of}\:\mathrm{the}\:\mathrm{function}. \\ $$…
Question Number 7135 by Master Moon last updated on 12/Aug/16 $$\boldsymbol{\mathrm{Prove}}\:\boldsymbol{\mathrm{that}} \\ $$$$\:\frac{\mathrm{3}}{\:\sqrt[{\mathrm{5}}]{\mathrm{2}}+\sqrt[{\mathrm{5}}]{\mathrm{3}}+\sqrt[{\mathrm{5}}]{\mathrm{5}}}\:>\:\frac{\sqrt[{\mathrm{4}}]{\mathrm{2}}+\sqrt[{\mathrm{4}}]{\mathrm{3}}+\sqrt[{\mathrm{4}}]{\mathrm{5}}}{\left(\sqrt{\mathrm{2}}+\sqrt{\mathrm{3}}+\sqrt{\mathrm{5}}\right)\left(\sqrt[{\mathrm{3}}]{\mathrm{2}}+\sqrt[{\mathrm{3}}]{\mathrm{3}}+\sqrt[{\mathrm{3}}]{\mathrm{5}}\right)} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: \\ $$$$\:\:\:{How}\:{to}\:{prove}\:{it}\:? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 72640 by azizullah last updated on 31/Oct/19 Answered by ajfour last updated on 31/Oct/19 $$\mathrm{1}+\mathrm{0}=\mathrm{1} \\ $$ Answered by MJS last updated on…
Question Number 7122 by 314159 last updated on 11/Aug/16 Answered by uchechukwu okorie favour last updated on 11/Aug/16 $${let}\:{the}\:{probability}\:{that}\:{a}\:{student} \\ $$$${picked}\:{at}\:{random}\:{be}\:{taller}\:{than} \\ $$$$\mathrm{1}.\mathrm{8}\:{metres}\:{be}\:{Pr}\left({T}\right) \\ $$$${Also};\:{let}\:{the}\:{probability}\:{that}\:{a}…
Question Number 138167 by physicstutes last updated on 10/Apr/21 $$\mathrm{let}\:{f}\left({x}\right)\:=\:\begin{vmatrix}{{x}}&{{x}^{\mathrm{2}} }&{{x}^{\mathrm{3}} }\\{\mathrm{0}}&{\mathrm{2}{x}\:}&{\mathrm{3}{x}^{\mathrm{2}} }\\{\mathrm{1}}&{\mathrm{0}}&{{x}}\end{vmatrix}\:\mathrm{find} \\ $$$$\:{f}\:'\left({x}\right)\: \\ $$ Answered by Dwaipayan Shikari last updated on 10/Apr/21…