Question Number 7884 by uchechukwu okorie favour last updated on 23/Sep/16 $${pls}\:{help}\:{me}\:{solve}\:{this}\:{chemistry} \\ $$$${question}: \\ $$$${Considering}\:{a}\:{general}\:{equilibrium} \\ $$$${equation}: \\ $$$${mA}_{\left({g}\right)} +{nB}_{\left({g}\right)} \leftrightharpoons{xC}_{\left({g}\right)\:\:} +{yD}_{\left({g}\right)} \\ $$$${where}\:{m},{n},{x}\:{and}\:{y}\:{are}\:{the}\:…
Question Number 138947 by mohammad17 last updated on 20/Apr/21 Commented by mohammad17 last updated on 20/Apr/21 $${how}\:{can}\:{it}\:{solve}\:{this} \\ $$ Commented by mohammad17 last updated on…
Question Number 138948 by mohammad17 last updated on 20/Apr/21 Commented by mohammad17 last updated on 20/Apr/21 $${hwo}\:{can}\:{help}\:{me}\: \\ $$ Commented by mohammad17 last updated on…
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Question Number 7855 by 314159 last updated on 21/Sep/16 Commented by 123456 last updated on 21/Sep/16 $${a}_{\mathrm{1}} ,{a}_{\mathrm{2}} ,{a}_{\mathrm{3}} \Rightarrow{a}_{\mathrm{3}} −{a}_{\mathrm{2}} ={a}_{\mathrm{2}} −{a}_{\mathrm{1}} ,{a}_{\mathrm{1}} \neq{a}_{\mathrm{2}}…
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Question Number 7847 by madscientist last updated on 20/Sep/16 $${is}\:{there}\:{a}\:{proof}\:{of}\:{a}\:{relationship}\:\: \\ $$$${between}\:\varphi,\pi,{e}\:{where}\:\pi=\mathrm{3}.\mathrm{14},\varphi=\mathrm{1}.\mathrm{618}\: \\ $$$${and}\:{e}=\mathrm{2}.\mathrm{718}\:{such}\:{that}\:\varepsilon\:{is}\:{some} \\ $$$${oporator},\varepsilon=−+×\boldsymbol{\div} \\ $$$$\varphi\varepsilon\pi\varepsilon{e}=\mathrm{0}\:{or}\:\pi\varepsilon{e}\varepsilon\varphi=\mathrm{0}\:{or}\:{e}\varepsilon\varphi\varepsilon\pi=\mathrm{0} \\ $$ Commented by FilupSmith last updated…
Question Number 7846 by Tinku Tara last updated on 20/Sep/16 $$\mathrm{There}\:\mathrm{is}\:\mathrm{new}\:\mathrm{update}\:\mathrm{available}. \\ $$$$\mathrm{The}\:\mathrm{following}\:\mathrm{enhacements}\:\mathrm{are}\:\mathrm{made}\:\mathrm{in} \\ $$$$\mathrm{this}\:\mathrm{update} \\ $$$$\bullet\:\mathrm{You}\:\mathrm{can}\:\mathrm{now}\:\mathrm{zoom}\:\mathrm{on}\:\mathrm{images}\:\mathrm{posted}\:\mathrm{on} \\ $$$$\:\:\:\:\mathrm{the}\:\mathrm{forum}. \\ $$$$\bullet\:\mathrm{Preview}\:\mathrm{of}\:\mathrm{the}\:\mathrm{image}\:\mathrm{is}\:\mathrm{available}\:\mathrm{while} \\ $$$$\:\:\:\:\mathrm{answering}\:\mathrm{or}\:\mathrm{commenting}.\:\mathrm{You}\:\mathrm{can} \\ $$$$\:\:\:\:\mathrm{zoom}\:\mathrm{within}\:\mathrm{the}\:\mathrm{preview}\:\mathrm{as}\:\mathrm{well}.…
Question Number 7840 by Chantria last updated on 19/Sep/16 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{first}\:\mathrm{digit}\:\mathrm{after}\:\mathrm{the} \\ $$$$\mathrm{decimal}\:\mathrm{point}\:\mathrm{of}\:\mathrm{the}\:\mathrm{number}\:\frac{\mathrm{1}}{\mathrm{1009}}+\frac{\mathrm{1}}{\mathrm{1010}}+…+\frac{\mathrm{1}}{\mathrm{2016}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 7831 by Chantria last updated on 18/Sep/16 Commented by prakash jain last updated on 18/Sep/16 $${S}_{{n}} =\frac{{n}+\mathrm{2}}{{n}!}+\frac{\mathrm{2}}{{k}!}+\frac{\mathrm{7}}{{k}!}+….+\frac{{n}^{\mathrm{2}} −\mathrm{2}}{{k}!}=\frac{{n}+\mathrm{2}}{{n}!}+\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\frac{{k}^{\mathrm{2}} −\mathrm{2}}{{k}!} \\ $$$${n}^{\mathrm{2}}…