Question Number 7738 by 314159 last updated on 13/Sep/16 Commented by Rasheed Soomro last updated on 13/Sep/16 $$\frac{\mathrm{248}\left(\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\right)^{\mathrm{2}} +\mathrm{496}\left(\frac{\mathrm{1}}{\:\sqrt{\mathrm{4}}}\right)^{\mathrm{6}} +\mathrm{1984}\left(\frac{\mathrm{1}}{\:\sqrt{\mathrm{8}}}\right)^{\mathrm{8}} +…}{\mathrm{1}+\mathrm{5}+\mathrm{9}+…\mathrm{393}} \\ $$$$\frac{\mathrm{248}\left(\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{1}} +\mathrm{496}\left(\frac{\mathrm{1}}{\mathrm{4}}\right)^{\mathrm{3}} +\mathrm{1984}\left(\frac{\mathrm{1}}{\mathrm{8}}\right)^{\mathrm{4}}…
Question Number 7733 by Rohit 57 last updated on 13/Sep/16 $$\frac{\mathrm{6}.\mathrm{7}×\mathrm{10}^{−\mathrm{11}} ×\:\mathrm{6}×\mathrm{10}^{\mathrm{24}} ×\:\mathrm{7}.\mathrm{4}×\mathrm{10}^{\mathrm{22}} }{\left(\mathrm{3}.\mathrm{84}×\mathrm{10}^{\mathrm{8}} \right)^{\mathrm{2}} } \\ $$$${how}\:{to}\:{dived}\:{this}\:{number}….\:{plzzz}\:{ans} \\ $$$$\: \\ $$ Answered by FilupSmith…
Question Number 7732 by Rohit 57 last updated on 13/Sep/16 $$\frac{\mathrm{6}.\mathrm{7}×\mathrm{10}^{−\mathrm{11}} ×\:\mathrm{6}×\mathrm{10}^{\mathrm{24}} ×\:\mathrm{7}.\mathrm{4}×\mathrm{10}^{\mathrm{22}} }{\left(\mathrm{3}.\mathrm{84}×\mathrm{10}^{\mathrm{8}} \right)^{\mathrm{2}} } \\ $$$${how}\:{to}\:{dived}\:{this}\:{number}….\:{plzzz}\:{ans} \\ $$$$\: \\ $$ Answered by sandy_suhendra…
Question Number 7729 by Rohit 57 last updated on 13/Sep/16 $$ {used}\:{of}\:\:{proportional}\:\left({sine}\right)…{why} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 7708 by kamylla last updated on 10/Sep/16 $$\mathrm{5}×\mathrm{2} \\ $$ Commented by Rohit 57 last updated on 13/Sep/16 $${answer}\:{is}\:\mathrm{5}×\mathrm{2}=\mathrm{10}\: \\ $$ Terms of…
Question Number 7706 by Rohit 57 last updated on 10/Sep/16 $${what}\:{is}\:{spectrum}.\left({chemistry}\:{subject}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 138764 by otchereabdullai@gmail.com last updated on 17/Apr/21 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{impedence}\:\mathrm{of}\:\mathrm{an}\:\mathrm{RC}\:\mathrm{circuit} \\ $$$$\mathrm{with}\:\mathrm{R}=\:\mathrm{10}\Omega\:\mathrm{and}\:\mathrm{C}=\mathrm{10}\mu\mathrm{F}\:\mathrm{at}\:\mathrm{an}\: \\ $$$$\mathrm{angular}\:\mathrm{frequency}\:\mathrm{of}\:\mathrm{21800rads}^{−\mathrm{1}} \\ $$ Answered by ajfour last updated on 18/Apr/21 $${Z}=\sqrt{{R}^{\mathrm{2}} +\frac{\mathrm{1}}{\left(\omega{C}\right)^{\mathrm{2}}…
Question Number 7668 by 314159 last updated on 08/Sep/16 Commented by Yozzia last updated on 08/Sep/16 $${Suppose}\:{a}+{b}={c},\:{with}\:{a},{b},{c}>\mathrm{0}. \\ $$$${Let}\:{n}=\frac{{a}}{\mathrm{1}+{a}}+\frac{{b}}{\mathrm{1}+{b}}−\frac{{c}}{\mathrm{1}+{c}}. \\ $$$${n}=\frac{{a}}{\mathrm{1}+{a}}+\frac{{b}}{\mathrm{1}+{b}}−\frac{{a}+{b}}{\mathrm{1}+{a}+{b}} \\ $$$${n}=\frac{{a}}{\mathrm{1}+{a}}−\frac{{a}}{\mathrm{1}+{a}+{b}}+\frac{{b}}{\mathrm{1}+{b}}−\frac{{b}}{\mathrm{1}+{a}+{b}} \\ $$$${n}={a}\left(\frac{\mathrm{1}}{\mathrm{1}+{a}}−\frac{\mathrm{1}}{\mathrm{1}+{a}+{b}}\right)+{b}\left(\frac{\mathrm{1}}{\mathrm{1}+{b}}−\frac{\mathrm{1}}{\mathrm{1}+{a}+{b}}\right)…
Question Number 138730 by mohammad17 last updated on 17/Apr/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 73191 by Mr. K last updated on 07/Nov/19 $${find}\:{x}\:{and}\:{y}: \\ $$$$\begin{cases}{\mathrm{2}{x}^{{y}} −{x}^{−{y}} =\mathrm{1}}\\{{log}_{\mathrm{2}} {y}=\sqrt{{x}}}\end{cases} \\ $$ Answered by mind is power last updated…