Question Number 8916 by kuldeep singh raj last updated on 05/Nov/16 Commented by Rasheed Soomro last updated on 05/Nov/16 $$\mathrm{Is}\:\mathrm{O}\:\mathrm{the}\:\mathrm{centre}\:\mathrm{of}\:\mathrm{the}\:\mathrm{circle}? \\ $$ Commented by kuldeep…
Question Number 74455 by Mr. K last updated on 24/Nov/19 $${if}\:{K}=\left({x}\in\mathbb{R}\:\mathrm{2}{x}−\mathrm{1}+\mid\mathrm{2}{x}−\mathrm{1}\mid=\mathrm{0}\:\right){and} \\ $$$${J}=\left({x}\in\mathbb{R}\:−{x}\left(\mathrm{2}{x}+\mathrm{1}\right)\leqslant−\mathrm{1}\right)\:{find}\:{J}−{K}. \\ $$ Answered by MJS last updated on 24/Nov/19 $${K}=\left\{{x}\in\mathbb{R}\mid{x}\leqslant\frac{\mathrm{1}}{\mathrm{2}}\right\} \\ $$$${J}=\left\{{x}\in\mathbb{R}\mid{x}\leqslant−\mathrm{1}\vee{x}\geqslant\frac{\mathrm{1}}{\mathrm{2}}\right\}…
Question Number 74431 by azizullah last updated on 24/Nov/19 Commented by azizullah last updated on 24/Nov/19 $$\:\:\:\:\:\:\:\:\mathrm{please}\:\mathrm{solve}\:\mathrm{Q}.\:\mathrm{6},\:\mathrm{8},\:\mathrm{10},\:\mathrm{11}, \\ $$ Commented by MJS last updated on…
Question Number 74429 by azizullah last updated on 24/Nov/19 Commented by MJS last updated on 24/Nov/19 $$\mathrm{perimeter}=\mathrm{4}×\sqrt{\mathrm{area}} \\ $$$$\mathrm{118m}^{\mathrm{2}} +\mathrm{81dm}^{\mathrm{2}} =\mathrm{11881dm}^{\mathrm{2}} \\ $$$${p}=\mathrm{4}×\sqrt{\mathrm{11881dm}^{\mathrm{2}} }=\mathrm{4}×\mathrm{109dm}=\mathrm{436dm}= \\…
Question Number 74371 by liki last updated on 23/Nov/19 Commented by liki last updated on 23/Nov/19 $$….{plz}\:{help}\:{me}\:\mathrm{16}{a}\:,,{emergerce} \\ $$ Answered by MJS last updated on…
Question Number 139897 by malwan last updated on 02/May/21 $$ \\ $$$$\mathrm{mrW}\:\mathrm{and}\:\mathrm{others}\:\mathrm{you}\:\mathrm{posted} \\ $$$$\mathrm{amzing}\:\mathrm{graphs}\:\mathrm{for}\:\mathrm{implicit} \\ $$$$\mathrm{funcions} \\ $$$$\mathrm{1}\:{What}\:{is}\:{the} \\ $$$$\mathrm{number}\:\mathrm{of}\:\mathrm{question}\:\mathrm{please}? \\ $$$$\mathrm{2}\:\mathrm{Canyou}\:\mathrm{send}\:\mathrm{me}\:\mathrm{the}\:\mathrm{links}\:\mathrm{to} \\ $$$$\mathrm{d}{own}\mathrm{load}\:\mathrm{these}\:\mathrm{graphers}\:\mathrm{thank} \\…
Question Number 74355 by Mr. K last updated on 22/Nov/19 $${let}\:{f}\left({x}\right),\:{g}\left({x}\right)\:{and}\:{h}\left({x}\right)\:{be}\:{functions} \\ $$$$\mathbb{R}\rightarrow\mathbb{R},\:{given}\:{by} \\ $$$${f}\left({x}\right)={x}^{\mathrm{2}} ,\:{if}\:{x}\geqslant\mathrm{0}\:{and}\:{x}+\mathrm{1}\:{if}\:{x}<\mathrm{0} \\ $$$${g}\left({x}\right)={x}^{\mathrm{2}} −\mathrm{4},\:{if}\:{x}\geqslant\mathrm{2}\:{and}\:\frac{\mathrm{1}}{\mathrm{2}−{x}}\:{if}\:{x}<\mathrm{2} \\ $$$${h}\left({x}\right)=\mathrm{3}^{−{x}} ,\:{if}\:{x}\leqslant\mathrm{0}\:{and}\:\mathrm{3}^{{x}} \:{if}\:{x}\geqslant\mathrm{0} \\ $$$${Calculate}\:\frac{{f}\left(\mathrm{2}\right)+{f}\left({g}\left(\mathrm{2}\right)\right)}{{f}\left({g}\left({h}\left(−\mathrm{1}\right)\right)\right)}.…
Question Number 8801 by arinto27 last updated on 28/Oct/16 $$\mathrm{tent}.\:\mathrm{persamaan}\:\mathrm{garis}\:\mathrm{singung}\:\mathrm{pada}\:\mathrm{lingkaran} \\ $$$$\mathrm{a}.\:\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} +\mathrm{4x}−\mathrm{6y}−\mathrm{7}=\mathrm{0}\:\mathrm{dititik}\:\mathrm{yg}\:\mathrm{berabsis}\:\mathrm{2}. \\ $$$$\mathrm{b}.\:\left(\:\mathrm{x}+\mathrm{2}\:\right)^{\mathrm{2}} \:\left(\mathrm{y}−\mathrm{3}\right)^{\mathrm{2}} \:=\mathrm{16}\:\mathrm{tegak}\:\mathrm{lurus}\:\mathrm{garis}\:\mathrm{x}−\mathrm{2y}+\mathrm{4}=\mathrm{0}. \\ $$ Answered by ridwan balatif last…
Question Number 74337 by Maclaurin Stickker last updated on 22/Nov/19 $${find}\:{the}\:{contracted}\:{form}\:{of}: \\ $$$$\begin{pmatrix}{{n}}\\{{p}}\end{pmatrix}+\mathrm{2}\begin{pmatrix}{\:\:\:{n}}\\{{p}+\mathrm{1}}\end{pmatrix}+\begin{pmatrix}{\:\:\:{n}}\\{{p}+\mathrm{2}}\end{pmatrix} \\ $$ Answered by MJS last updated on 23/Nov/19 $$\begin{pmatrix}{{n}}\\{{p}}\end{pmatrix}\:=\frac{{n}!}{{p}!\left({n}−{p}\right)!}=\frac{{n}!\left({p}+\mathrm{1}\right)\left({p}+\mathrm{2}\right)}{{p}!\left({n}−{p}\right)!\left({p}+\mathrm{1}\right)\left({p}+\mathrm{2}\right)} \\ $$$$\mathrm{2}\begin{pmatrix}{{n}}\\{{p}+\mathrm{1}}\end{pmatrix}\:=\frac{\mathrm{2}{n}!}{\left({p}+\mathrm{1}\right)!\left({n}−{p}−\mathrm{1}\right)!}=\frac{\mathrm{2}{n}!\left({n}−{p}\right)}{{p}!\left({n}−{p}\right)!\left({p}+\mathrm{1}\right)}=…
Question Number 139867 by Maclaurin Stickker last updated on 01/May/21 $${a}^{\mathrm{3}} +{b}^{\mathrm{3}} +{c}^{\mathrm{3}} =\mathrm{0} \\ $$$${a}^{\mathrm{12}} +{b}^{\mathrm{12}} +{c}^{\mathrm{12}} =\mathrm{8} \\ $$$${a}^{\mathrm{6}} +{b}^{\mathrm{6}} +{c}^{\mathrm{6}} =? \\…