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2-8-2-8-

Question Number 138350 by abenarhodym last updated on 12/Apr/21 $$\sqrt{\mathrm{2}}\left(\sqrt{\mathrm{8}}−\frac{\mathrm{2}}{\:\sqrt{\mathrm{8}}}\right) \\ $$ Answered by Ñï= last updated on 12/Apr/21 $$\sqrt{\mathrm{2}}\left(\sqrt{\mathrm{8}}−\frac{\mathrm{2}}{\:\sqrt{\mathrm{8}}}\right)=\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{2}}} \left(\mathrm{2}^{\frac{\mathrm{3}}{\mathrm{2}}} −\mathrm{2}^{\mathrm{1}−\frac{\mathrm{3}}{\mathrm{2}}} \right)=\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{3}}{\mathrm{2}}} −\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{2}}−\frac{\mathrm{1}}{\mathrm{2}}} =\mathrm{2}^{\mathrm{2}}…

If-z-1-6-cos-pi-4-sin-pi-4-and-z-2-2-cos-pi-5-i-sin-pi-5-calculate-z-1-z-2-

Question Number 72787 by Maclaurin Stickker last updated on 02/Nov/19 $${If}\:{z}_{\mathrm{1}} =\mathrm{6}\left(\mathrm{cos}\:\frac{\pi}{\mathrm{4}}+\mathrm{sin}\:\frac{\pi}{\mathrm{4}}\right)\:{and} \\ $$$${z}_{\mathrm{2}} =\mathrm{2}\left(\mathrm{cos}\:\frac{\pi}{\mathrm{5}}+\mathrm{i}×\mathrm{sin}\:\frac{\pi}{\mathrm{5}}\right)\:{calculate}\:\frac{{z}_{\mathrm{1}} }{{z}_{\mathrm{2}} }. \\ $$ Commented by MJS last updated on…

f-x-1-1-x-1-1-a-ax-ax-8-x-0-a-0-show-1-lt-f-x-lt-2-

Question Number 138316 by Ñï= last updated on 12/Apr/21 $${f}\left({x}\right)=\frac{\mathrm{1}}{\:\sqrt{\mathrm{1}+{x}}}+\frac{\mathrm{1}}{\:\sqrt{\mathrm{1}+{a}}}+\sqrt{\frac{{ax}}{{ax}+\mathrm{8}}}\:\:\:\:\:\:\:\:,{x}\in\left(\mathrm{0},\infty\right) \\ $$$$\forall\:{a}\in\left(\mathrm{0},\infty\right),{show}\:\mathrm{1}<{f}\left({x}\right)<\mathrm{2}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com