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n-0-1-5n-

Question Number 72746 by aliesam last updated on 01/Nov/19 $$\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{\left(\mathrm{5}{n}\right)!} \\ $$ Answered by mind is power last updated on 01/Nov/19 $$\mathrm{1}+\mathrm{z}+\mathrm{z}^{\mathrm{2}} +\mathrm{z}^{\mathrm{3}}…

x-2-10x-6-x-2-gt-1-

Question Number 138250 by sahnaz last updated on 11/Apr/21 $$\left(\mathrm{x}^{\mathrm{2}} −\mathrm{10x}+\mathrm{6}\right)^{\mathrm{x}−\mathrm{2}} >\mathrm{1} \\ $$ Answered by bobhans last updated on 11/Apr/21 $$\left({x}^{\mathrm{2}} −\mathrm{10}{x}+\mathrm{6}\right)^{{x}−\mathrm{2}} \:>\:\left({x}^{\mathrm{2}} −\mathrm{10}{x}+\mathrm{6}\right)^{\mathrm{0}}…

Question-7164

Question Number 7164 by aftab ahmad last updated on 14/Aug/16 Answered by Yozzia last updated on 14/Aug/16 $${By}\:{Power}\:{of}\:{a}\:{Point}\:{theorem}, \\ $$$$\left({AB}\right)\left({AC}\right)=\left({AD}\right)\left({AD}\right)=\left({AD}\right)^{\mathrm{2}} \\ $$$$\Rightarrow{AC}=\frac{\left({AD}\right)^{\mathrm{2}} }{{AB}}=\frac{\mathrm{10}^{\mathrm{2}} }{\mathrm{5}}=\mathrm{20}{cm} \\…

log-2-x-1-2015-y-1-2015-1-e-2-ixy-2015-

Question Number 7159 by Master Moon last updated on 14/Aug/16 $$\boldsymbol{{log}}_{\mathrm{2}} \underset{\boldsymbol{{x}}=\mathrm{1}} {\overset{\mathrm{2015}} {\prod}}\:\underset{\boldsymbol{{y}}=\mathrm{1}} {\overset{\mathrm{2015}} {\prod}}\left(\mathrm{1}+\boldsymbol{{e}}^{\frac{\mathrm{2}\boldsymbol{\pi{ixy}}}{\mathrm{2015}}} \right)\:=\:? \\ $$ Commented by FilupSmith last updated on…