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Divide-10-into-two-parts-so-that-twice-the-square-of-the-first-part-plus-thrice-the-square-of-the-other-part-is-the-least-

Question Number 6179 by 314159 last updated on 17/Jun/16 $${Divide}\:\mathrm{10}\:{into}\:{two}\:{parts}\:{so}\:{that}\:{twice}\:{the} \\ $$$${square}\:{of}\:{the}\:{first}\:{part}\:{plus}\:{thrice}\:{the} \\ $$$${square}\:{of}\:{the}\:{other}\:{part}\:{is}\:{the}\:{least}. \\ $$ Commented by prakash jain last updated on 17/Jun/16 $${one}\:{part}\:{x},\:{second}\:{part}\:\left(\mathrm{10}−{x}\right)…

prove-the-identity-D-nds-D-2-dA-

Question Number 6174 by madscientist last updated on 17/Jun/16 $${prove}\:{the}\:{identity} \\ $$$$\int_{\partial{D}} \phi\bigtriangledown\phi\centerdot{nds}=\int\int_{{D}} \left(\phi\bigtriangledown^{\mathrm{2}\:} \phi+\bigtriangledown\phi\centerdot\bigtriangledown\phi\right){dA} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

f-x-xf-x-f-x-

Question Number 6177 by FilupSmith last updated on 17/Jun/16 $${f}\:'\left({x}\right)={xf}\left({x}\right) \\ $$$${f}\left({x}\right)=?? \\ $$ Answered by Yozzii last updated on 17/Jun/16 $$\frac{{df}}{{dx}}={xf} \\ $$$$\Rightarrow\int\frac{{df}}{{f}}=\int{xdx} \\…

ln-1-x-x-

Question Number 137203 by mathocean1 last updated on 31/Mar/21 $$\int\:\frac{{ln}\left(\mathrm{1}+{x}\right)}{{x}}=? \\ $$ Answered by Dwaipayan Shikari last updated on 31/Mar/21 $$\int\frac{{log}\left(\mathrm{1}+{x}\right)}{{x}}{dx} \\ $$$$=\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\left(−\mathrm{1}\right)^{{n}+\mathrm{1}}…

A-boy-leaves-a-0-4-kilogram-stone-from-the-top-of-a-25-meter-high-tower-Given-g-10-m-s-2-calvulate-the-total-work-done-by-the-force-of-the-weight-until-the-stone-hits-the-ground-

Question Number 71616 by Mr.K last updated on 18/Oct/19 $${A}\:{boy}\:{leaves}\:{a}\:\mathrm{0}.\mathrm{4}\:{kilogram}\:{stone}\: \\ $$$${from}\:{the}\:{top}\:{of}\:{a}\:\mathrm{25}\:{meter}−{high}\: \\ $$$${tower}.\:{Given}\:{g}=\mathrm{10}\:{m}/{s}^{\mathrm{2}} ,\:{calvulate} \\ $$$${the}\:{total}\:{work}\:{done}\:{by}\:{the}\:{force}\:{of}\:{the} \\ $$$${weight}\:{until}\:{the}\:{stone}\:{hits}\:{the}\:{ground} \\ $$ Terms of Service Privacy…

One-person-drags-a-10-kilogram-sandbag-at-a-distance-of-8-meters-employing-a-horizontal-force-of-90-N-Then-lift-the-sandbag-at-a-height-of-1-5-meters-calculate-the-total-work-done-by-the-person-

Question Number 71617 by Mr. K last updated on 18/Oct/19 $${One}\:{person}\:{drags}\:{a}\:\mathrm{10}\:{kilogram} \\ $$$${sandbag}\:{at}\:{a}\:{distance}\:{of}\:\mathrm{8}\:{meters} \\ $$$${employing}\:{a}\:{horizontal}\:{force}\:{of} \\ $$$$\mathrm{90}\:{N}.\:{Then}\:{lift}\:{the}\:{sandbag}\:{at}\:{a} \\ $$$${height}\:{of}\:\mathrm{1}.\mathrm{5}\:{meters},\:{calculate}\:{the} \\ $$$${total}\:{work}\:{done}\:{by}\:{the}\:{person}. \\ $$ Terms of…