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Question-196388

Question Number 196388 by sonukgindia last updated on 24/Aug/23 Answered by AST last updated on 24/Aug/23 $$\phi\left(\mathrm{20}\right)=\phi\left(\mathrm{4}\right)\phi\left(\mathrm{5}\right)=\left(\mathrm{2}^{\mathrm{2}} −\mathrm{2}\right)\left(\mathrm{5}−\mathrm{1}\right)=\mathrm{8} \\ $$ Answered by BaliramKumar last updated…

19-20-21-factorial-plz-hepl-me-so-soon-

Question Number 196347 by bbbbbbbb last updated on 23/Aug/23 $$\left(\mathrm{1}\overset{\left(\mathrm{2}\overset{\mathrm{21}} {\mathrm{0}}\right)} {\mathrm{9}}\right)\:\boldsymbol{\mathrm{factorial}}\:\boldsymbol{\mathrm{plz}}\:\boldsymbol{\mathrm{hepl}}\:\boldsymbol{\mathrm{me}}\:\boldsymbol{\mathrm{so}}\:\boldsymbol{\mathrm{soon}} \\ $$ Commented by mr W last updated on 23/Aug/23 $${so}\:{soon}\:{as}\:{the}\:{light}? \\ $$$${in}\:{each}\:{of}\:{your}\:{questions}\:{you}\:{request}…

Question-196303

Question Number 196303 by sonukgindia last updated on 22/Aug/23 Answered by sniper237 last updated on 22/Aug/23 $$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\:{Im}\left(\frac{{e}^{{i}\pi/\mathrm{4}} }{\mathrm{2}}\right)^{{n}} ={Im}\left(\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\left({e}^{{i}\pi/\mathrm{4}} /\mathrm{2}\right)^{{n}} \right)…