Question Number 137133 by yutytfjh67ihd last updated on 30/Mar/21 $${Q}\mathrm{137026} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 6058 by FilupSmith last updated on 11/Jun/16 $$\mathrm{sin}\left({a}\right)=\mathrm{sin}\left(−{a}\right) \\ $$$$\mathrm{For}\:\mathrm{what}\:\mathrm{values}\:\mathrm{of}\:{a}\:\mathrm{is}\:\mathrm{the}\:\mathrm{statement}\:\mathrm{true}? \\ $$ Commented by Rasheed Soomro last updated on 11/Jun/16 $${a}=\pi{n}\:\forall{n}\in\mathbb{Z} \\ $$$$…
Question Number 137116 by yutytfjh67ihd last updated on 29/Mar/21 $${Q}\mathrm{136697} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 137115 by yutytfjh67ihd last updated on 29/Mar/21 $${Q}\mathrm{136739} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 137112 by Algoritm last updated on 29/Mar/21 Answered by Ñï= last updated on 03/Apr/21 $$\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{1}}{\mathrm{3}}\right)+\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{2}}{\mathrm{9}}\right)+\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{4}}{\mathrm{23}}\right)+… \\ $$$$={arg}\left(\mathrm{3}+{i}\right)+{arg}\left(\mathrm{9}+\mathrm{2}{i}\right)+{arg}\left(\mathrm{23}+\mathrm{4}{i}\right)+… \\ $$$$={arg}\left[\left(\mathrm{3}+{i}\right)\left(\mathrm{9}+\mathrm{2}{i}\right)\left(\mathrm{23}+\mathrm{4}{i}\right)\centerdot…\right] \\…
Question Number 137106 by mohammad17 last updated on 29/Mar/21 Commented by radians last updated on 30/Mar/21 $${lazy}\:{man} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 6011 by 314159 last updated on 09/Jun/16 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 137069 by 0731619177 last updated on 29/Mar/21 Answered by Ñï= last updated on 29/Mar/21 $$\left(\mathrm{1}\right){y}_{{p}} =\frac{\mathrm{1}}{{D}^{\mathrm{2}} +\mathrm{2}{D}+\mathrm{5}}\left(\mathrm{6sin}\:\mathrm{2}{x}+\mathrm{7cos}\:\mathrm{2}{x}\right) \\ $$$$=\frac{\mathrm{1}}{\mathrm{2}{D}+\mathrm{1}}\left(\mathrm{6sin}\:\mathrm{2}{x}+\mathrm{7cos}\:\mathrm{2}{x}\right)=\frac{\left(\mathrm{1}+\mathrm{2}{D}\right)}{\mathrm{9}}\left(\mathrm{6sin}\:\mathrm{2}\boldsymbol{{x}}+\mathrm{7cos}\:\mathrm{2}{x}\right) \\ $$$$=\frac{\mathrm{1}}{\mathrm{9}}\left(\mathrm{31cos}\:\mathrm{2}{x}−\mathrm{22sin}\:\mathrm{2}{x}\right) \\ $$$${y}={e}^{−{x}}…
Question Number 137056 by Ar Brandon last updated on 29/Mar/21 $$\:\:\:\:\mathrm{On}\:\mathrm{this}\:\mathrm{same}\:\mathrm{day}\:\mathrm{last}\:\mathrm{year}\:\mathrm{I}\:\mathrm{made}\:\mathrm{my}\:\mathrm{first}\:\mathrm{on}\:\mathrm{this}\:\mathrm{forum}\:\left(\mathrm{Q86484}\right) \\ $$$$\mathrm{and}\:\mathrm{I}\:\mathrm{was}\:\mathrm{very}\:\mathrm{astonished}\:\mathrm{by}\:\mathrm{the}\:\mathrm{answers}\:\mathrm{which}\:\mathrm{I}\:\mathrm{received}. \\ $$$$\mathrm{I}\:\mathrm{underestimated}\:\mathrm{the}\:\mathrm{place}\:\mathrm{at}\:\mathrm{first}\:\mathrm{before}\:\mathrm{getting}\:\mathrm{to}\:\mathrm{know}\:\mathrm{it} \\ $$$$\mathrm{better}.\:\mathrm{And}\:\mathrm{I}\:\mathrm{realised}\:\mathrm{I}\:\mathrm{knew}\:\mathrm{nothing}.\: \\ $$$$\:\:\:\:\mathrm{I}'\mathrm{m}\:\mathrm{grateful}\:\mathrm{with}\:\mathrm{all}\:\mathrm{the}\:\mathrm{teachings}\:\mathrm{which}\:\mathrm{I}'\mathrm{ve}\:\mathrm{acquired}\:\mathrm{from}\: \\ $$$$\mathrm{you}\:\mathrm{all}.\:\mathrm{You}\:\mathrm{guys}\:\mathrm{are}\:\mathrm{just}\:\mathrm{so}\:\mathrm{amazing}.\:\mathrm{Thank}\:\mathrm{you}\:\mathrm{once}\:\mathrm{more}. \\ $$$$\mathrm{Special}\:\mathrm{thanks}\:\mathrm{to}\:\mathrm{you}\:\mathrm{too}\:\mathrm{Mr}\:\mathrm{Tinku}-\mathrm{Tara}.\: \\ $$😉…
Question Number 137047 by mohammad17 last updated on 29/Mar/21 Commented by mohammad17 last updated on 29/Mar/21 $$????? \\ $$ Terms of Service Privacy Policy Contact:…