Question Number 72447 by Maclaurin Stickker last updated on 28/Oct/19 $${Find}\:{the}\:{value}\:{of}: \\ $$$$\frac{\mathrm{1}}{{sin}\:\mathrm{2}°}+\frac{\mathrm{1}}{{sin}\:\mathrm{4}°}+\frac{\mathrm{1}}{{sin}\:\mathrm{8}°}+\frac{\mathrm{1}}{{sin}\:\mathrm{16}°}+… \\ $$$$+\frac{\mathrm{1}}{{sin}\:\left(\mathrm{2}^{\mathrm{1029}} \right)^{°} } \\ $$ Answered by Tanmay chaudhury last updated…
Question Number 72439 by Maclaurin Stickker last updated on 28/Oct/19 Commented by Maclaurin Stickker last updated on 28/Oct/19 $${Prove}\:{that}\:{the}\:{radius}\:{of}\:{the}\: \\ $$$${circumferences}\:{is}: \\ $$$$\frac{\mathrm{2}}{\mathrm{1}−{cos}\:\mathrm{2}\alpha}\:{and}\:\frac{\mathrm{2}}{\mathrm{1}−{sin}\:\mathrm{2}\alpha}\:. \\ $$$${and}\:{find}\:{tan}\left(\alpha\right)…
Question Number 6891 by hanandmishra026@gmail.com last updated on 01/Aug/16 $${What}\:{is}\:{AREA}\:\mathrm{52}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 137963 by floor(10²Eta[1]) last updated on 08/Apr/21 $$\mathrm{find}\:\mathrm{all}\:\mathrm{positive}\:\mathrm{integers}\:\mathrm{x}\:\mathrm{and}\:\mathrm{y}\:\mathrm{such}\:\mathrm{that} \\ $$$$\mathrm{3}^{\mathrm{x}} −\mathrm{2}^{\mathrm{y}} =\mathrm{7} \\ $$ Commented by PRITHWISH SEN 2 last updated on 08/Apr/21…
Question Number 6878 by sarathon last updated on 01/Aug/16 $${why}\:{log}\mathrm{0}.\mathrm{9}=\mathrm{2}{log}\mathrm{3}−\mathrm{1}\:?? \\ $$$$ \\ $$$$ \\ $$$$ \\ $$$$ \\ $$$$ \\ $$ Answered by Tawakalitu.…
Question Number 137946 by otchereabdullai@gmail.com last updated on 08/Apr/21 $$\mathrm{From}\:\mathrm{a}\:\mathrm{poin}\:\mathrm{P}\:\mathrm{outside}\:\mathrm{a}\:\mathrm{circle}\:\mathrm{a} \\ $$$$\mathrm{tangent}\:\mathrm{is}\:\mathrm{drawn}\:\mathrm{to}\:\mathrm{a}\:\mathrm{circle}\:\mathrm{at}\:\mathrm{T}. \\ $$$$\mathrm{from}\:\mathrm{P}\:\mathrm{a}\:\mathrm{line}\:\mathrm{is}\:\mathrm{drawn}\:\mathrm{to}\:\mathrm{circle}\:\mathrm{at} \\ $$$$\mathrm{A}\:\mathrm{and}\:\mathrm{B}\:.\:\mathrm{Find}\:\mathrm{lenth}\:\mathrm{PT}\:\mathrm{giving}\:\mathrm{that} \\ $$$$\mathrm{i}.\:\mathrm{PA}\:=\mathrm{6} \\ $$$$\:\:\:\:\mathrm{AB}=\mathrm{8} \\ $$$$\mathrm{ii}.\:\mathrm{PB}=\mathrm{18} \\ $$$$\:\:\:\:\:\mathrm{PT}=\mathrm{12} \\…
Question Number 137941 by Ñï= last updated on 08/Apr/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\int_{\mathrm{0}} ^{\infty} \frac{{x}−\mathrm{1}}{\:\sqrt{\mathrm{2}^{{x}} −\mathrm{1}}{ln}\:\left(\mathrm{2}^{{x}} −\mathrm{1}\right)}{dx}=\frac{\pi}{\mathrm{2}{ln}^{\mathrm{2}} \mathrm{2}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 137936 by Ñï= last updated on 08/Apr/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\begin{pmatrix}{\mathrm{4}{n}}\\{\mathrm{2}{n}}\end{pmatrix}^{−\mathrm{1}} =\frac{\mathrm{16}}{\mathrm{15}}+\frac{\sqrt{\mathrm{3}}}{\mathrm{27}}\pi−\frac{\mathrm{2}\sqrt{\mathrm{5}}}{\mathrm{25}}{ln}\left(\mathrm{1}+\frac{\sqrt{\mathrm{5}}}{\mathrm{2}}\right) \\ $$ Commented by Dwaipayan Shikari last updated on 08/Apr/21 $$\underset{{n}=\mathrm{0}} {\overset{\infty}…
Question Number 137939 by Ñï= last updated on 08/Apr/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\int_{\mathrm{0}} ^{\mathrm{1}} \int_{\mathrm{0}} ^{\mathrm{1}} {ln}\Gamma\left(\mathrm{1}+{x}+{y}\right){dxdy}=\frac{\mathrm{5}}{\mathrm{2}}{ln}\mathrm{2}+\frac{\mathrm{1}}{\mathrm{2}}{ln}\pi−\frac{\mathrm{9}}{\mathrm{4}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 137938 by Ñï= last updated on 09/Apr/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\int\frac{\mathrm{2}{x}^{\mathrm{4}} +\mathrm{5}{x}^{\mathrm{3}} +\mathrm{6}{x}^{\mathrm{2}} +\mathrm{6}{x}+\mathrm{12}}{\left({x}^{\mathrm{2}} +\mathrm{2}{x}+\mathrm{2}\right)^{\mathrm{3}/\mathrm{2}} }{dx}=? \\ $$$${A}\:{very}\:{nice}\:{solution}:: \\ $$$$\int\frac{\mathrm{2}{x}^{\mathrm{4}} +\mathrm{5}{x}^{\mathrm{3}} +\mathrm{6}{x}^{\mathrm{2}} +\mathrm{6}{x}+\mathrm{12}}{\left({x}^{\mathrm{2}} +\mathrm{2}{x}+\mathrm{2}\right)^{\mathrm{3}/\mathrm{2}} }{dx}=\frac{{f}\left({x}\right)}{\:\sqrt{{x}^{\mathrm{2}} +\mathrm{2}{x}+\mathrm{2}}}+{C}…