Question Number 73722 by azizullah last updated on 15/Nov/19 Commented by TawaTawa last updated on 15/Nov/19 $$\mathrm{Kamal}\:\:=\:\:\mathrm{x} \\ $$$$\mathrm{Ali}\:\:=\:\:\mathrm{x}\:+\:\mathrm{50} \\ $$$$\mathrm{Total}\:\:=\:\:\mathrm{150} \\ $$$$\therefore\:\:\:\:\:\mathrm{x}\:+\:\mathrm{x}\:+\:\mathrm{50}\:\:=\:\:\mathrm{150} \\ $$$$\therefore\:\:\:\:\:\mathrm{2x}\:+\:\mathrm{50}\:\:=\:\:\mathrm{150}…
Question Number 139257 by bobhans last updated on 25/Apr/21 $$\:\:\:\:\underset{\mathrm{k}=\mathrm{1}} {\overset{\infty} {\sum}}\:\frac{\left(−\mathrm{1}\right)^{\mathrm{k}} \left(\mathrm{2k}−\mathrm{1}\right)}{\mathrm{k}^{\mathrm{2}} }\:=? \\ $$ Answered by john_santu last updated on 25/Apr/21 $$\:\:\:\:\underset{{k}=\mathrm{1}} {\overset{\infty}…
Question Number 73721 by azizullah last updated on 15/Nov/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 8151 by trapti rathaur@ gmail.com last updated on 02/Oct/16 $${what}\:{is}\:\:{rectangular}\:\:\:{paralleopiped}? \\ $$ Answered by sandy_suhendra last updated on 02/Oct/16 Commented by sandy_suhendra last…
Question Number 139198 by otchereabdullai@gmail.com last updated on 24/Apr/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 8105 by 314159 last updated on 30/Sep/16 $${Prove}\:{that}\:,{for}\:{any}\:{acute}\:{angle}\:\alpha\: \\ $$$${sec}\alpha\:{cosec}\alpha\:+{tan}\alpha\:+{cot}\alpha\:\geqslant\mathrm{4}. \\ $$ Commented by Yozzia last updated on 30/Sep/16 $${f}\left({x}\right)=\frac{\mathrm{1}}{{cosxsinx}}+\frac{{sinx}}{{cosx}}+\frac{{cosx}}{{sinx}} \\ $$$${f}\left({x}\right)=\frac{\mathrm{1}}{{cosxsinx}}+\frac{\mathrm{1}}{{sinxcosx}} \\…
Question Number 8093 by Tinku Tara last updated on 30/Sep/16 $$\mathrm{App}\:\mathrm{has}\:\mathrm{been}\:\mathrm{updated}\:\left(\mathrm{ver}\:\mathrm{1}.\mathrm{48}\right) \\ $$$$\bullet\:\mathrm{Customizable}\:\mathrm{key}\:\mathrm{screen}\:\bigstar \\ $$$$\:\:\:\:\mathrm{long}\:\mathrm{press}\:\mathrm{on}\:\mathrm{any}\:\mathrm{key}\:\mathrm{on}\:\mathrm{that}\:\mathrm{screen} \\ $$$$\:\:\:\:\mathrm{to}\:\mathrm{change}\:\mathrm{the}\:\mathrm{symbol}\:\mathrm{on}\:\mathrm{that}\:\mathrm{location} \\ $$$$\bullet\:\:\mathrm{Choose}\:\mathrm{default}\:\mathrm{font}\:\mathrm{size}\:\mathrm{and}\:\mathrm{style} \\ $$$$\bullet\:\:\mathrm{option}\:\mathrm{menu}\:\mathrm{for}\:\mathrm{quicker}\:\mathrm{access}\:\mathrm{to}\:\mathrm{long} \\ $$$$\:\:\:\:\:\mathrm{press}\:\mathrm{menu} \\ $$$$\bullet\:\:\:\mathrm{new}\:\mathrm{symbols}\:\mathrm{and}\:\mathrm{right}\:\mathrm{curly}\:\mathrm{brace}\:\mathrm{matrix}…
Question Number 8073 by 314159 last updated on 29/Sep/16 Commented by 123456 last updated on 30/Sep/16 $$\mathrm{cosh}\left({x}\right)=\frac{{e}^{{x}} +{e}^{−{x}} }{\mathrm{2}} \\ $$$${x}^{\mathrm{4}} +{x}^{−\mathrm{4}} =\mathrm{47} \\ $$$${x}={e}^{{t}}…
Question Number 8066 by Chantria last updated on 29/Sep/16 $${calculate}\: \\ $$$$\:\underset{{n}\rightarrow\infty} {{lim}}\frac{{n}}{\mathrm{2}^{\sqrt{{n}}} } \\ $$$$ \\ $$ Answered by prakash jain last updated on…
Question Number 139124 by 7770 last updated on 22/Apr/21 $${x}^{\mathrm{2}} +{x}−\mathrm{2}\sqrt{{x}}=\mathrm{36} \\ $$$$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{x}} \\ $$ Answered by MJS_new last updated on 22/Apr/21 $$\mathrm{you}\:\mathrm{can}\:\mathrm{only}\:\mathrm{approximate}.\:\mathrm{I}\:\mathrm{get} \\ $$$${x}\approx\mathrm{5}.\mathrm{91193369}…