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Question-136897

Question Number 136897 by mohammad17 last updated on 27/Mar/21 Answered by Olaf last updated on 27/Mar/21 $$ \\ $$$${f}\left({z}\right)\:=\:{e}^{{i}\frac{\pi}{\mathrm{4}}} {z}+\left(\mathrm{1}−\mathrm{2}{i}\right) \\ $$$${f}\left({z}\right)−{z}_{\mathrm{0}} \:=\:{e}^{{i}\frac{\pi}{\mathrm{4}}} \left({z}−{z}_{\mathrm{0}} \right)+\left({e}^{{i}\frac{\pi}{\mathrm{4}}}…

at-developers-can-we-please-have-capital-greek-symbols-It-would-make-things-so-much-better-when-writing-functions-lt-3-

Question Number 5780 by FilupSmith last updated on 27/May/16 $${at}\:{developers} \\ $$$${can}\:{we}\:{please}\:{have}\:{capital}\:{greek}\:{symbols}? \\ $$$$\mathrm{It}\:\mathrm{would}\:\mathrm{make}\:\mathrm{things}\:\mathrm{so}\:\mathrm{much}\:\mathrm{better} \\ $$$$\mathrm{when}\:\mathrm{writing}\:\mathrm{functions}\:<\mathrm{3} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Find-to-the-nearest-hundredth-the-positive-cube-root-of-29-

Question Number 5771 by Rasheed Soomro last updated on 27/May/16 $$\mathrm{Find}\:\mathrm{to}\:\mathrm{the}\:\mathrm{nearest}\:\mathrm{hundredth}\:\mathrm{the}\:\mathrm{positive} \\ $$$$\mathrm{cube}-\mathrm{root}\:\mathrm{of}\:\mathrm{29}\:. \\ $$ Commented by Yozzii last updated on 27/May/16 $$\left(\mathrm{29}\right)^{\mathrm{1}/\mathrm{3}} =\left(\mathrm{2}+\mathrm{27}\right)^{\mathrm{1}/\mathrm{3}} =\mathrm{3}\left(\mathrm{1}+\frac{\mathrm{2}}{\mathrm{27}}\right)^{\mathrm{1}/\mathrm{3}}…