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Question Number 137203 by mathocean1 last updated on 31/Mar/21 $$\int\:\frac{{ln}\left(\mathrm{1}+{x}\right)}{{x}}=? \\ $$ Answered by Dwaipayan Shikari last updated on 31/Mar/21 $$\int\frac{{log}\left(\mathrm{1}+{x}\right)}{{x}}{dx} \\ $$$$=\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\left(−\mathrm{1}\right)^{{n}+\mathrm{1}}…

A-boy-leaves-a-0-4-kilogram-stone-from-the-top-of-a-25-meter-high-tower-Given-g-10-m-s-2-calvulate-the-total-work-done-by-the-force-of-the-weight-until-the-stone-hits-the-ground-

Question Number 71616 by Mr.K last updated on 18/Oct/19 $${A}\:{boy}\:{leaves}\:{a}\:\mathrm{0}.\mathrm{4}\:{kilogram}\:{stone}\: \\ $$$${from}\:{the}\:{top}\:{of}\:{a}\:\mathrm{25}\:{meter}−{high}\: \\ $$$${tower}.\:{Given}\:{g}=\mathrm{10}\:{m}/{s}^{\mathrm{2}} ,\:{calvulate} \\ $$$${the}\:{total}\:{work}\:{done}\:{by}\:{the}\:{force}\:{of}\:{the} \\ $$$${weight}\:{until}\:{the}\:{stone}\:{hits}\:{the}\:{ground} \\ $$ Terms of Service Privacy…

One-person-drags-a-10-kilogram-sandbag-at-a-distance-of-8-meters-employing-a-horizontal-force-of-90-N-Then-lift-the-sandbag-at-a-height-of-1-5-meters-calculate-the-total-work-done-by-the-person-

Question Number 71617 by Mr. K last updated on 18/Oct/19 $${One}\:{person}\:{drags}\:{a}\:\mathrm{10}\:{kilogram} \\ $$$${sandbag}\:{at}\:{a}\:{distance}\:{of}\:\mathrm{8}\:{meters} \\ $$$${employing}\:{a}\:{horizontal}\:{force}\:{of} \\ $$$$\mathrm{90}\:{N}.\:{Then}\:{lift}\:{the}\:{sandbag}\:{at}\:{a} \\ $$$${height}\:{of}\:\mathrm{1}.\mathrm{5}\:{meters},\:{calculate}\:{the} \\ $$$${total}\:{work}\:{done}\:{by}\:{the}\:{person}. \\ $$ Terms of…