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Use-De-Moivre-s-theorem-to-prove-that-r-0-cos-rx-1-2-and-find-a-value-or-expression-for-r-0-sin-rx-assume-that-this-two-series-were-convergent-

Question Number 136582 by physicstutes last updated on 23/Mar/21 $$\mathrm{Use}\:\mathrm{De}'\mathrm{Moivre}'\mathrm{s}\:\mathrm{theorem}\:\mathrm{to}\:\mathrm{prove}\:\mathrm{that} \\ $$$$\:\underset{{r}=\mathrm{0}} {\overset{\infty} {\sum}}\mathrm{cos}\:{rx}\:=\:\frac{\mathrm{1}}{\mathrm{2}}\:\mathrm{and}\:\mathrm{find}\:\mathrm{a}\:\mathrm{value}\left(\mathrm{or}\:\mathrm{expression}\right)\:\mathrm{for}\:\underset{{r}=\mathrm{0}} {\overset{\infty} {\sum}}\mathrm{sin}\:{rx} \\ $$$$\mathrm{assume}\:\mathrm{that}\:\mathrm{this}\:\mathrm{two}\:\mathrm{series}\:\mathrm{were}\:\mathrm{convergent}. \\ $$ Answered by Ar Brandon last…

Google-released-an-update-to-android-webview-which-is-causing-multiple-android-app-to-crash-Please-search-internet-for-workaround-for-your-device-This-problem-is-not-caused-by-Tinkutara-Equation-Edi

Question Number 136551 by Tinku Tara last updated on 23/Mar/21 $$\mathrm{Google}\:\mathrm{released}\:\mathrm{an}\:\mathrm{update}\:\mathrm{to}\:\mathrm{android} \\ $$$$\mathrm{webview}\:\mathrm{which}\:\mathrm{is}\:\mathrm{causing}\:\mathrm{multiple} \\ $$$$\mathrm{android}\:\mathrm{app}\:\mathrm{to}\:\mathrm{crash}.\:\mathrm{Please} \\ $$$$\mathrm{search}\:\mathrm{internet}\:\mathrm{for}\:\mathrm{workaround} \\ $$$$\mathrm{for}\:\mathrm{your}\:\mathrm{device}. \\ $$$$\boldsymbol{\mathrm{This}}\:\boldsymbol{\mathrm{problem}}\:\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{not}}\:\boldsymbol{\mathrm{caused}}\:\boldsymbol{\mathrm{by}}\:\boldsymbol{\mathrm{Tinkutara}} \\ $$$$\boldsymbol{\mathrm{Equation}}\:\boldsymbol{\mathrm{Editor}}. \\ $$$$\mathrm{Please}\:\mathrm{also}\:\mathrm{note}\:\mathrm{no}\:\mathrm{android}\:\mathrm{app}…

to-Tinku-Tara-sir-since-update-to-version-2-262-i-m-encountering-a-big-problem-after-some-time-of-use-the-app-crashes-then-i-can-t-start-the-app-any-more-that-means-after-displaying-the-welcome-

Question Number 136541 by mr W last updated on 23/Mar/21 $${to}\:{Tinku}\:\:{Tara}\:{sir}: \\ $$$${since}\:{update}\:{to}\:{version}\:\mathrm{2}.\mathrm{262}\:{i}'{m} \\ $$$${encountering}\:{a}\:{big}\:{problem}: \\ $$$${after}\:{some}\:{time}\:{of}\:{use}\:{the}\:{app}\: \\ $$$${crashes},\:{then}\:{i}\:{can}'{t}\:{start}\:{the}\:{app} \\ $$$${any}\:{more},\:{that}\:{means}\:{after}\:{displaying} \\ $$$${the}\:{welcome}\:{screen}\:{the}\:{app}\:{crashes}. \\ $$$${besides}\:{some}\:{other}\:{apps},\:{e}.{g}.\:{google},…

Question-136537

Question Number 136537 by Jamshidbek last updated on 23/Mar/21 Answered by Olaf last updated on 23/Mar/21 $${a}+\frac{\mathrm{1}}{{a}}\:=\:−\mathrm{1} \\ $$$${a}^{\mathrm{2}} +{a}+\mathrm{1}\:=\:\mathrm{0} \\ $$$${a}\:=\:\frac{−\mathrm{1}\pm{i}\sqrt{\mathrm{3}}}{\mathrm{2}}\:=\:{e}^{{i}\frac{\mathrm{2}\pi}{\mathrm{3}}} \mathrm{or}\:{e}^{{i}\frac{\mathrm{4}\pi}{\mathrm{3}}} \\ $$$$\mathrm{1}+\mathrm{2}+\mathrm{3}+\mathrm{4}+\mathrm{5}+\mathrm{6}+\mathrm{7}+\mathrm{8}+\mathrm{9}+\mathrm{1}+\mathrm{0}+\mathrm{1}+\mathrm{1}…

Where-f-x-4x-2-1-2x-1-defined-in-R-1-2-determine-lim-x-1-2-f-x-

Question Number 71000 by Maclaurin Stickker last updated on 10/Oct/19 $${Where}\:{f}\left({x}\right)=\frac{\mathrm{4}{x}^{\mathrm{2}} −\mathrm{1}}{\mathrm{2}{x}−\mathrm{1}}\:{defined}\:{in}\: \\ $$$$\mathbb{R}−\left\{\frac{\mathrm{1}}{\mathrm{2}}\right\},\:{determine}\:\underset{{x}\rightarrow\frac{\mathrm{1}}{\mathrm{2}}} {\mathrm{lim}}{f}\left({x}\right). \\ $$ Commented by mathmax by abdo last updated on…

Question-70996

Question Number 70996 by A8;15: last updated on 10/Oct/19 Commented by mathmax by abdo last updated on 10/Oct/19 $${let}\:{take}\:{a}\:{try}\:\left({e}\right)\:\Rightarrow\sqrt{{x}^{\mathrm{3}} +\mathrm{24}}−\sqrt{{x}^{\mathrm{3}} \:+\mathrm{12}}=\mathrm{3}{x}+\mathrm{8}\:\Rightarrow \\ $$$$\left(\sqrt{{x}^{\mathrm{3}} +\mathrm{24}}−\sqrt{{x}^{\mathrm{3}} +\mathrm{12}}\right)^{\mathrm{2}}…

L-lim-x-0-2-1-sinx-1-sinx-1-tanx-1-tanx-e-x-2-

Question Number 136531 by SOMEDAVONG last updated on 23/Mar/21 $$\mathrm{L}=\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{2}\left(\mathrm{1}+\mathrm{sinx}\right)^{\frac{\mathrm{1}}{\mathrm{sinx}}} −\left(\mathrm{1}+\mathrm{tanx}\right)^{\frac{\mathrm{1}}{\mathrm{tanx}}} −\mathrm{e}}{\mathrm{x}^{\mathrm{2}} } \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com