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Question-197104

Question Number 197104 by MrGHK last updated on 07/Sep/23 Commented by TheHoneyCat last updated on 08/Sep/23 $$\mathrm{Are}\:\mathrm{you}\:\mathrm{looking}\:\mathrm{for}\:\mathrm{a}\:\mathrm{functional}\:\mathrm{answere}? \\ $$$$\mathrm{because}\:\mathrm{if}\:\mathrm{you}\:\mathrm{are}\:\mathrm{expecting}\:\mathrm{a}\:\mathrm{solution}: \\ $$$${x}\left({t}\right)=… \\ $$$$\mathrm{then}\:\mathrm{there}\:\mathrm{is}\:\mathrm{an}\:\mathrm{issue}:\:{y}\:\mathrm{is}\:\mathrm{not}\:\mathrm{defined}! \\ $$…

Question-197094

Question Number 197094 by MrGHK last updated on 07/Sep/23 Answered by sniper237 last updated on 07/Sep/23 $$\overset{{schwarz}\:{theo}} {\Rightarrow}\:\partial_{{x}} \left(\:{t}\partial_{{t}} {u}+\mathrm{2}{u}\right)={x}^{\mathrm{2}} \\ $$$$\overset{\int{dx}} {\Rightarrow}{t}\partial_{{t}} {u}+\mathrm{2}{u}\:=\frac{{x}^{\mathrm{3}} }{\mathrm{3}}+{f}\left({t}\right)…

Question-197050

Question Number 197050 by Skabetix last updated on 06/Sep/23 Commented by TheHoneyCat last updated on 07/Sep/23 $$\mathrm{Maintenant},\:\mathrm{2b} \\ $$$${Y}_{{k}} =\frac{\left(\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}{x}^{{k}} \right)−{n}}{{x}−\mathrm{1}} \\ $$$$=\frac{\left(\underset{{k}=\mathrm{1}}…

sinx-b-cosx-a-k-find-k-a-b-plz-i-need-dears-

Question Number 197042 by bbbbbbbb last updated on 07/Sep/23 $$\frac{\mathrm{sinx}}{\mathrm{b}}+\frac{\mathrm{cosx}}{\mathrm{a}}=\boldsymbol{\mathrm{k}} \\ $$$$\boldsymbol{\mathrm{find}}\:\:\:\boldsymbol{\mathrm{k}}\left(\boldsymbol{\mathrm{a}}+\boldsymbol{\mathrm{b}}\right)? \\ $$$$\boldsymbol{\mathrm{plz}}\:\boldsymbol{\mathrm{i}}\:\boldsymbol{\mathrm{need}}\:\boldsymbol{\mathrm{dears}} \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question-197010

Question Number 197010 by sonukgindia last updated on 06/Sep/23 Answered by nikif99 last updated on 06/Sep/23 $${Triangle}\:{inequalitues}: \\ $$$$\mathrm{3}{x}−{x}<\mathrm{10}\:\Rightarrow\mathrm{2}{x}<\mathrm{10}\:\Rightarrow{x}<\mathrm{5}\:\left(\mathrm{1}\right) \\ $$$${x}+\mathrm{3}{x}>\mathrm{10}\:\Rightarrow\mathrm{4}{x}>\mathrm{10}\:\Rightarrow{x}>\frac{\mathrm{5}}{\mathrm{2}}\:\Rightarrow{x}\geqslant\mathrm{3}\:\left(\mathrm{2}\right) \\ $$$$\left(\mathrm{1}\right)\left(\mathrm{2}\right)\:\Rightarrow{max}\:{x}=\mathrm{4} \\ $$$${max}\:{perim}.={x}+\mathrm{3}{x}+\mathrm{10}=\mathrm{26}…