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Question-135253

Question Number 135253 by otchereabdullai@gmail.com last updated on 11/Mar/21 Commented by mr W last updated on 11/Mar/21 $$\angle{YXZ}=\mathrm{90}°\:\Rightarrow{YX}=\sqrt{\mathrm{5}^{\mathrm{2}} −\mathrm{3}^{\mathrm{2}} }=\mathrm{4} \\ $$$${area}\:{of}\:\Delta{XYZ}=\frac{{YX}×{XZ}}{\mathrm{2}}=\frac{{YZ}×{XN}}{\mathrm{2}} \\ $$$$\Rightarrow{XN}=\frac{\mathrm{4}×\mathrm{3}}{\mathrm{5}}=\frac{\mathrm{12}}{\mathrm{5}} \\…

Question-135254

Question Number 135254 by 0731619177 last updated on 11/Mar/21 Answered by Dwaipayan Shikari last updated on 11/Mar/21 $${I}\left({a}\right)=\int_{\mathrm{0}} ^{\infty} \left(\frac{{e}^{−{ax}^{\mathrm{2}} } −{e}^{−{bx}^{\mathrm{2}} } }{{x}}\right)^{\mathrm{2}} {dx}…

lim-x-3-x-2-9-x-3-

Question Number 135216 by mohammad17 last updated on 11/Mar/21 $${lim}_{{x}\rightarrow\mathrm{3}^{+} } \frac{\left[{x}\right]^{\mathrm{2}} −\mathrm{9}}{{x}−\mathrm{3}} \\ $$ Answered by Olaf last updated on 11/Mar/21 $$\underset{{x}\rightarrow\mathrm{3}^{+} } {\mathrm{lim}}\:\frac{\left[{x}\right]^{\mathrm{2}}…

if-the-function-f-is-analytic-function-inside-z-lt-5-and-f-z-10-z-on-the-circle-z-1-2-find-1-f-2-1-2-f-3-0-

Question Number 135194 by mohammad17 last updated on 11/Mar/21 $${if}\:{the}\:{function}\:{f}\:{is}\:{analytic}\:{function}\: \\ $$$${inside}\:\mid{z}\mid<\mathrm{5}\:{and}\:\mid{f}\left({z}\right)\mid\leqslant\mathrm{10}\:\forall{z}\:{on}\:{the} \\ $$$${circle}\:\mid{z}−\mathrm{1}\mid=\mathrm{2}\:{find}\: \\ $$$$ \\ $$$$\left(\mathrm{1}\right)\mid{f}^{\:\mathrm{2}} \left(\mathrm{1}\right)\mid \\ $$$$ \\ $$$$\left(\mathrm{2}\right)\mid{f}^{\:\mathrm{3}} \left(\mathrm{0}\right)\mid \\…

Question-69616

Question Number 69616 by azizullah last updated on 25/Sep/19 Commented by Prithwish sen last updated on 25/Sep/19 $$\mathrm{After}\:\mathrm{10}\:\mathrm{years}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{will}\:\mathrm{be}\:\mathrm{40}+\mathrm{20}=\mathrm{60}\:\mathrm{years} \\ $$$$\mathrm{After}\:\mathrm{10}\:\mathrm{years} \\ $$$$\:\:\:\mathrm{shabena}\:\mathrm{will}\:\mathrm{be}\:=\:\frac{\mathrm{1}}{\mathrm{3}}×\mathrm{60}\:=\:\mathrm{20}\:\mathrm{years} \\ $$$$\mathrm{maria}\:\mathrm{will}\:\mathrm{be}\:=\frac{\mathrm{2}}{\mathrm{3}}\:×\mathrm{60}\:=\:\mathrm{40}\:\mathrm{years} \\…