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if-i-had-a-grid-with-4-quadrants-and-i-shaded-a-quarter-of-it-and-chose-one-of-the-4-quadrants-to-form-a-new-grid-and-shaded-it-and-repeated-the-process-infinitly-what-is-the-amount-of-the-shaded-a

Question Number 4941 by madscientist last updated on 25/Mar/16 $${if}\:{i}\:{had}\:{a}\:{grid}\:{with}\:\mathrm{4}\:{quadrants}\:{and}\:{i}\:{shaded}\:{a}\:\: \\ $$$${quarter}\:{of}\:{it}\:{and}\:{chose}\:{one}\:{of}\:{the}\:\mathrm{4}\:{quadrants}\:{to}\:{form}\:{a}\:{new}\:{grid} \\ $$$${and}\:{shaded}\:{it}\:{and}\:{repeated}\:{the}\:{process}\:{infinitly}\:{what}\: \\ $$$${is}\:{the}\:{amount}\:{of}\:{the}\:{shaded}\:{area}? \\ $$$${and}\:{what}\:{formula}\:{will}\:{solve}\:{it}? \\ $$ Answered by FilupSmith last updated…

While-posting-photos-of-printed-material-please-use-app-like-camscanner-so-that-picture-will-look-clean-Also-please-crop-pictures-and-upload-in-correct-orientation-In-built-editor-support-near-a

Question Number 70473 by Tinku Tara last updated on 04/Oct/19 $$ \\ $$$$\mathrm{While}\:\mathrm{posting}\:\mathrm{photos}\:\mathrm{of}\:\mathrm{printed}\:\mathrm{material} \\ $$$$\mathrm{please}\:\mathrm{use}\:\mathrm{app}\:\left(\mathrm{like}\:\mathrm{camscanner}\right)\:\mathrm{so} \\ $$$$\mathrm{that}\:\mathrm{picture}\:\mathrm{will}\:\mathrm{look}\:\mathrm{clean}. \\ $$$$\mathrm{Also}\:\mathrm{please}\:\mathrm{crop}\:\mathrm{pictures}\:\mathrm{and}\:\mathrm{upload} \\ $$$$\mathrm{in}\:\mathrm{correct}\:\mathrm{orientation}. \\ $$$$ \\ $$$$\mathrm{In}\:\mathrm{built}\:\mathrm{editor}\:\mathrm{support}\:\mathrm{near}\:\mathrm{all}\:\mathrm{maths}…

find-the-lowest-number-between-200-and-500-which-leaves-a-remainder-of-3-in-each-case-which-will-divisible-by-8-10-12-and-30-

Question Number 135990 by zakirullah last updated on 17/Mar/21 $$\:\:\:\:\:\boldsymbol{{find}}\:\boldsymbol{{the}}\:\boldsymbol{{lowest}}\:\boldsymbol{{number}}\:\boldsymbol{{between}}\:\mathrm{200}\:\boldsymbol{{and}}\:\mathrm{500}\:\boldsymbol{{which}} \\ $$$$\:\:\:\:\:\boldsymbol{{leaves}}\:\boldsymbol{{a}}\:\boldsymbol{{remainder}}\:\boldsymbol{{of}}\:\mathrm{3}\:\boldsymbol{{in}}\:\boldsymbol{{each}}\:\boldsymbol{{case}} \\ $$$$\:\:\:\:\boldsymbol{{which}}\:\boldsymbol{{will}}\:\boldsymbol{{divisible}}\:\boldsymbol{{by}}\:\mathrm{8}\:,\:\mathrm{10},\:\mathrm{12}\:\boldsymbol{{and}}\:\mathrm{30}? \\ $$ Answered by Olaf last updated on 17/Mar/21 $$\mathrm{N}\:=\:\mathrm{8}{k}+\mathrm{3}\:=\:\mathrm{10}{l}+\mathrm{3}\:=\:\mathrm{12}{m}+\mathrm{3}\:=\:\mathrm{30}{n}+\mathrm{3} \\…

Hey-guys-A-new-graphing-app-is-out-called-Desmos-It-is-really-amazing-Just-thought-I-d-let-you-know-

Question Number 4918 by FilupSmith last updated on 21/Mar/16 $$\mathrm{Hey}\:\mathrm{guys}!\:{A}\:\mathrm{new}\:\mathrm{graphing}\:\mathrm{app}\:\mathrm{is}\:\mathrm{out} \\ $$$$\mathrm{called}\:{Desmos} \\ $$$$ \\ $$$$\mathrm{It}\:\mathrm{is}\:\mathrm{really}\:\mathrm{amazing}! \\ $$$$ \\ $$$$\mathrm{Just}\:\mathrm{thought}\:\mathrm{I}'{d}\:\mathrm{let}\:\mathrm{you}\:\mathrm{know}! \\ $$ Commented by Yozzii…

I-e-sinx-xcos-2-x-sinx-cos-2-x-dx-

Question Number 135986 by SOMEDAVONG last updated on 17/Mar/21 $$\mathrm{I}=\int\mathrm{e}^{\mathrm{sinx}} \left(\frac{\mathrm{xcos}^{\mathrm{2}} \mathrm{x}−\mathrm{sinx}}{\mathrm{cos}^{\mathrm{2}} \mathrm{x}}\right)\mathrm{dx} \\ $$ Answered by Olaf last updated on 17/Mar/21 $$\mathrm{I}\:=\:\int{xe}^{\mathrm{sin}{x}} {dx}−\int{e}^{\mathrm{sin}{x}} \left(\frac{\mathrm{sin}{x}}{\mathrm{cos}^{\mathrm{2}}…

Let-R-n-m-R-n-1-m-R-n-1-m-1-if-R-1-1-6-R-2-1-8-R-3-1-1-and-t-R-4-t-0-a-Find-R-1-21-b-Find-R-1-n-

Question Number 135971 by Raxreedoroid last updated on 17/Mar/21 $$ \\ $$$$\mathrm{Let}\:{R}\left({n},{m}\right)={R}\left({n}−\mathrm{1},{m}\right)+{R}\left({n}−\mathrm{1},{m}−\mathrm{1}\right) \\ $$$$\mathrm{if}\:{R}\left(\mathrm{1},\mathrm{1}\right)=−\mathrm{6},{R}\left(\mathrm{2},\mathrm{1}\right)=\mathrm{8},{R}\left(\mathrm{3},\mathrm{1}\right)=−\mathrm{1} \\ $$$$\mathrm{and}\:\forall{t}\:{R}\left(\mathrm{4},{t}\right)=\mathrm{0} \\ $$$$ \\ $$$$ \\ $$$$\left.{a}\right)\:\mathrm{Find}\:{R}\left(\mathrm{1},\mathrm{21}\right) \\ $$$$ \\…

We-have-released-an-update-with-following-enhancements-A-new-section-quizzes-is-added-You-can-also-request-a-solution-for-quiz-question-and-we-will-provide-a-solution-In-case-you-wan

Question Number 4855 by Tinku Tara last updated on 18/Mar/16 $$\mathrm{We}\:\mathrm{have}\:\mathrm{released}\:\mathrm{an}\:\mathrm{update}\:\mathrm{with}\:\mathrm{following} \\ $$$$\mathrm{enhancements}: \\ $$$$\bullet\:\mathrm{A}\:\mathrm{new}\:\mathrm{section}\:\mathrm{quizzes}\:\mathrm{is}\:\mathrm{added}.\: \\ $$$$\:\:\:\:\mathrm{You}\:\mathrm{can}\:\mathrm{also}\:\mathrm{request}\:\mathrm{a}\:\mathrm{solution}\:\mathrm{for}\:\mathrm{quiz} \\ $$$$\:\:\:\:\mathrm{question}\:\mathrm{and}\:\mathrm{we}\:\mathrm{will}\:\mathrm{provide}\:\mathrm{a}\:\mathrm{solution}. \\ $$$$\:\:\:\:\mathrm{In}\:\mathrm{case}\:\mathrm{you}\:\mathrm{want}\:\mathrm{to}\:\mathrm{start}\:\mathrm{a}\:\mathrm{discussion}\:\mathrm{you} \\ $$$$\:\:\:\:\mathrm{can}\:\mathrm{post}\:\mathrm{the}\:\mathrm{same}\:\mathrm{question}\:\mathrm{to}\:\mathrm{forum}\:\mathrm{directly} \\ $$$$\:\:\:\:\mathrm{from}\:\mathrm{quiz}.…