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Question Number 3536 by Syaka last updated on 14/Dec/15 $${prove} \\ $$$$\frac{\mathrm{1}\:+\:{cos}\:{x}\:−\:{cos}\:{y}\:+\:{cos}\:{z}}{\mathrm{1}\:+\:{cos}\:{x}\:+\:{cos}\:{y}\:−\:{cos}\:{z}}\:=\:{cot}\:\frac{\mathrm{1}}{\mathrm{2}}{z}\:.\:{tan}\:\frac{\mathrm{1}}{\mathrm{2}}{y} \\ $$$$ \\ $$ Commented by Yozzii last updated on 14/Dec/15 $${x}={y}=\mathrm{0}\:,\:{z}=\pi/\mathrm{2} \\…

Question Number 134605 by Khalmohmmad last updated on 05/Mar/21 Answered by Ñï= last updated on 05/Mar/21 $${f}\left(\mathrm{2}\right)=\underset{{k}=\mathrm{1}} {\overset{\mathrm{2}} {\sum}}{k}!=\mathrm{1}!+\mathrm{2}!=\mathrm{3} \\ $$$${g}\left({f}\left(\mathrm{2}\right)\right)={g}\left(\mathrm{3}\right)=\underset{{k}=\mathrm{1}} {\overset{\mathrm{3}} {\sum}}\left({k}+\mathrm{1}\right)=\mathrm{2}+\mathrm{3}+\mathrm{4}=\mathrm{9} \\ $$…

Question Number 134599 by mohammad17 last updated on 05/Mar/21 Answered by Olaf last updated on 05/Mar/21 $$\left.{a}\right) \\ $$$$\int_{\mathrm{C}} \mid{z}\mid^{\mathrm{2}} {dz}\:=\:\int_{\mathrm{0}} ^{\sqrt{\mathrm{2}}} \mid{re}^{{i}\frac{\pi}{\mathrm{4}}} \mid^{\mathrm{2}} {dr}\:=\:\left[\frac{{r}^{\mathrm{3}}…

Question Number 3517 by Tinku Tara last updated on 14/Dec/15 $$\mathrm{App}\:\mathrm{has}\:\mathrm{been}\:\mathrm{updated}\:\mathrm{today}\:\mathrm{to}\:\mathrm{fix} \\ $$$$\mathrm{intermittent}\:\mathrm{scrolling}\:\mathrm{problem}\:\mathrm{while} \\ $$$$\mathrm{answering}\:\mathrm{or}\:\mathrm{commenting}. \\ $$$$\mathrm{Filup},\:\mathrm{please}\:\mathrm{let}\:\mathrm{us}\:\mathrm{know}\:\mathrm{if}\:\mathrm{this}\:\mathrm{addresses} \\ $$$$\mathrm{your}\:\mathrm{concerns}. \\ $$ Commented by Filup last…

Question Number 134567 by LUFFY last updated on 05/Mar/21 $${how}\:{to}\:{export}\:{image}\:{without}\:{watermark} \\ $$ Commented by mr W last updated on 05/Mar/21 $${pay}\:{a}\:{small}\:{fee}\:{and}\:{become}\:{a} \\ $$$${premium}\:{user}! \\ $$…