Question Number 135438 by 0731619177 last updated on 13/Mar/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 135433 by naka3546 last updated on 13/Mar/21 $${Prove}\:\:{a}\:+\:\frac{\mathrm{1}}{{a}}\:\geqslant\:\mathrm{2}\:\:{for}\:\:{a}\:>\:\mathrm{0}\:\:{algebraically}\:. \\ $$ Answered by mr W last updated on 13/Mar/21 $${a}+\frac{\mathrm{1}}{{a}}=\left(\sqrt{{a}}−\frac{\mathrm{1}}{\:\sqrt{{a}}}\right)^{\mathrm{2}} +\mathrm{2}\geqslant\mathrm{2} \\ $$ Commented…
Question Number 69874 by Tinku Tara last updated on 28/Sep/19 $$\mathrm{Hi} \\ $$$$ \\ $$$$\mathrm{We}\:\mathrm{are}\:\mathrm{still}\:\mathrm{working}\:\mathrm{on}\:\mathrm{solving} \\ $$$$\mathrm{android}\:\mathrm{api}\:\mathrm{update}\:\mathrm{and}\:\mathrm{notification} \\ $$$$\mathrm{related}\:\mathrm{issues}.\:\mathrm{The}\:\mathrm{solution}\:\mathrm{of}\:\mathrm{these} \\ $$$$\mathrm{problem}\:\mathrm{will}\:\mathrm{take}\:\mathrm{a}\:\mathrm{few}\:\mathrm{more}\:\mathrm{weeks}. \\ $$$$ \\ $$$$\mathrm{Sorry}\:\mathrm{about}\:\mathrm{the}\:\mathrm{inconvenience}…
Question Number 69873 by Masumsiddiqui399@gmail.com last updated on 28/Sep/19 Commented by mathmax by abdo last updated on 28/Sep/19 $${P}_{{n}−\mathrm{1}} =\prod_{{k}=\mathrm{1}} ^{{n}−\mathrm{1}} \left(\mathrm{1}−{z}_{{k}} \right)\:=\prod_{{k}=\mathrm{1}} ^{{n}−\mathrm{1}} \left(\mathrm{1}−{e}^{\frac{{i}\mathrm{2}{k}\pi}{{n}}}…
Question Number 135402 by mohammad17 last updated on 12/Mar/21 Answered by Ñï= last updated on 13/Mar/21 $${y}_{{p}} =\frac{\mathrm{1}}{{D}^{\mathrm{2}} −\mathrm{2}{D}+\mathrm{2}}\left(\mathrm{4}{xe}^{{x}} \mathrm{co}{s}\:{x}+{xe}^{−{x}} +{x}^{\mathrm{2}} +\mathrm{1}\right) \\ $$$$\mathrm{1}>>\frac{\mathrm{1}}{{D}^{\mathrm{2}} −\mathrm{2}{D}+\mathrm{2}}\mathrm{4}{xe}^{{x}}…
Question Number 135393 by Eric002 last updated on 12/Mar/21 $${f}\:'\left({x}\right)=\frac{\left({x}−\mathrm{3}\right)^{\mathrm{3}} \left({x}^{\mathrm{2}} −\mathrm{4}\right)}{\mathrm{16}} \\ $$$${g}\left({x}\right)={f}\left({x}^{\mathrm{2}} −\mathrm{1}\right) \\ $$$${find}\:{g}'\left(\mathrm{2}\right) \\ $$ Answered by MJS_new last updated on…
Question Number 135395 by 0731619177 last updated on 12/Mar/21 Answered by Dwaipayan Shikari last updated on 12/Mar/21 $${I}\left({b}\right)=\int_{\mathrm{0}} ^{\mathrm{1}} {sin}\left({log}\left(\frac{\mathrm{1}}{{x}}\right)\right)\frac{{x}^{{b}} −{x}^{{a}} }{{log}\left({x}\right)}{dx} \\ $$$${I}'\left({b}\right)=\int_{\mathrm{0}} ^{\mathrm{1}}…
Question Number 135385 by rs4089 last updated on 12/Mar/21 $$\mathrm{1}−\frac{\mathrm{1}}{\mathrm{2}}\:\frac{\mathrm{1}}{{x}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{2}}\frac{\mathrm{3}}{\mathrm{4}}\:\frac{\mathrm{1}}{{x}^{\mathrm{4}} }−\frac{\mathrm{1}}{\mathrm{2}}\frac{\mathrm{3}}{\mathrm{4}}\frac{\mathrm{5}}{\mathrm{6}}\:\frac{\mathrm{1}}{{x}^{\mathrm{6}} }+….=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 69809 by RAKESH MANDA last updated on 28/Sep/19 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:{x}\mathrm{sin}\:\frac{\pi}{{x}} \\ $$ Commented by mr W last updated on 28/Sep/19 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:{x}\mathrm{sin}\:\frac{\pi}{{x}} \\…
Question Number 135307 by 0731619177 last updated on 12/Mar/21 Terms of Service Privacy Policy Contact: info@tinkutara.com