Question Number 134546 by mohammad17 last updated on 05/Mar/21 $$\int_{\mathrm{0}} ^{\:\infty} \frac{{dx}}{\mathrm{1}+{e}^{{x}^{\mathrm{2}} } }\:\:{by}\:{two}\:{method} \\ $$ Answered by Dwaipayan Shikari last updated on 05/Mar/21 $$\int_{\mathrm{0}}…
Question Number 134526 by mohammad17 last updated on 04/Mar/21 Answered by mr W last updated on 05/Mar/21 $$\frac{\mathrm{1}}{\mathrm{1}+{x}}=\mathrm{1}−{x}+{x}^{\mathrm{2}} −{x}^{\mathrm{3}} +… \\ $$$$\int\frac{\mathrm{1}}{\mathrm{1}+{x}}{dx}=\int\left(\mathrm{1}−{x}+{x}^{\mathrm{2}} −{x}^{\mathrm{3}} +…\right){dx} \\…
Question Number 134519 by sachin1221 last updated on 04/Mar/21 $${why}\:{sinx}\:{is}\:{not}\:{differentiable}\:{at}\:{x}={n}\pi \\ $$ Commented by JDamian last updated on 04/Mar/21 seriously? Answered by physicstutes last updated…
Question Number 134523 by mohammad17 last updated on 04/Mar/21 $${let}\:{a},{b}\:{be}\:{any}\:{two}\:{elements}\:{in}\:{group}\:{G} \\ $$$${such}\:{that}\:\mid{a}\mid=\mathrm{4}\:,\mid{b}\mid=\mathrm{2}\:{and}\:{a}^{\mathrm{3}} {b}={ab} \\ $$$${find}\:\mid{ab}\mid\:? \\ $$$${help}\:{me}\:{sir}\:{please} \\ $$ Commented by kaivan.ahmadi last updated on…
Question Number 134511 by mohammad17 last updated on 04/Mar/21 Commented by mohammad17 last updated on 04/Mar/21 $${how}\:{can}\:{solve}\:{this} \\ $$ Commented by mohammad17 last updated on…
Question Number 134509 by mohammad17 last updated on 04/Mar/21 Commented by mr W last updated on 04/Mar/21 $${a}\:{book}\:{full}\:{of}\:{misprint}… \\ $$ Commented by mohammad17 last updated…
Question Number 134505 by Ñï= last updated on 04/Mar/21 $${Prove}::\frac{{Li}_{\mathrm{3}} \left(\mathrm{1}\right)}{\mathrm{10}}=\int_{\mathrm{0}} ^{{ln}\frac{\sqrt{\mathrm{5}}+\mathrm{1}}{\mathrm{2}}} {x}^{\mathrm{2}} {coth}\left({x}\right){dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 68952 by aliesam last updated on 17/Sep/19 Answered by mind is power last updated on 17/Sep/19 $$\Rightarrow{x}−\mathrm{1}>\mathrm{0}\Rightarrow{x}>\mathrm{1} \\ $$$$\Leftrightarrow\frac{{x}−\mathrm{1}}{{x}+\mathrm{1}}\leqslant\frac{{x}+\mathrm{1}+\mathrm{3}}{{x}−\mathrm{1}}\Rightarrow\left({x}−\mathrm{1}\right)^{\mathrm{2}} \leqslant\left({x}+\mathrm{4}\right)\left({x}+\mathrm{1}\right) \\ $$$$\Leftrightarrow{x}^{\mathrm{2}} −\mathrm{2}{x}+\mathrm{1}\leqslant{x}^{\mathrm{2}}…
Question Number 134484 by mohammad17 last updated on 04/Mar/21 Commented by Dwaipayan Shikari last updated on 04/Mar/21 $${General}\:{term}=\frac{{n}}{{n}^{\mathrm{2}} −\left({n}−\mathrm{1}\right)^{\mathrm{2}} }=\frac{{n}}{\mathrm{2}{n}−\mathrm{1}} \\ $$$$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\frac{{n}}{\mathrm{2}{n}−\mathrm{1}}=\frac{\mathrm{1}}{\mathrm{2}}\:\:\:\left({Sequence}\:{converges}\:{to}\:\frac{\mathrm{1}}{\mathrm{2}}\right) \\ $$$${And}\:{the}\:{series}\:{is}\:{Divergent}\:\underset{{n}=\mathrm{1}}…
Question Number 134480 by mohammad17 last updated on 04/Mar/21 Terms of Service Privacy Policy Contact: info@tinkutara.com