Question Number 135851 by Ñï= last updated on 16/Mar/21 $$\int_{\mathrm{0}} ^{\pi/\mathrm{2}} \left(\mathrm{cos}\:^{\mathrm{2}} {x}\right){ln}\left(\mathrm{1}+\mathrm{tan}\:^{\mathrm{4}} {x}\right){dx}=? \\ $$ Answered by mathmax by abdo last updated on 16/Mar/21…
Question Number 4773 by madscientist last updated on 08/Mar/16 $${lim}_{{x}\rightarrow\mathrm{0}\:} \:\frac{{sin}\left({x}\right)}{{x}}=\:\mathrm{1} \\ $$$${how}\:{is}\:{this}\:{so}? \\ $$$$ \\ $$ Commented by Yozzii last updated on 13/Mar/16 $${For}\:{x}\:{near}\:{zero},\:{the}\:{function}\:{sinx}…
Question Number 135841 by abdurehime last updated on 17/Mar/21 Answered by dhgt last updated on 04/May/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 70298 by naka3546 last updated on 03/Oct/19 Answered by mr W last updated on 03/Oct/19 Commented by mr W last updated on 03/Oct/19…
Question Number 135838 by abdurehime last updated on 16/Mar/21 Answered by liberty last updated on 16/Mar/21 $${f}\left({x}\right)=\:\frac{{x}}{{x}^{\mathrm{2}} +{k}}\:\Rightarrow\mathrm{ln}\:{y}\:=\:\mathrm{ln}\:{x}−\mathrm{ln}\:\left({x}^{\mathrm{2}} +{k}\right) \\ $$$$\:\frac{{y}'}{{y}}\:=\:\frac{\mathrm{1}}{{x}}−\frac{\mathrm{2}{x}}{{x}^{\mathrm{2}} +{k}} \\ $$$$\frac{{y}'}{{y}}\:=\:\frac{{k}−{x}^{\mathrm{2}} }{{x}\left({x}^{\mathrm{2}}…
Question Number 135840 by abdurehime last updated on 16/Mar/21 Answered by liberty last updated on 16/Mar/21 $${from}\:{p}\Rightarrow\:\backsim{q}\:{False}\:{we}\:{get}\:\begin{cases}{{p}\::\:{T}}\\{{q}\::\:{T}}\end{cases} \\ $$$${so}\:{the}\:{following}\:{statements}\:{is} \\ $$$${True}\::\:\left({p} \sim{q}\right)\Leftrightarrow\left(\sim{r} {r}\right) \\ $$$${answer}\::\:{C}…
Question Number 70296 by 7890542135678 last updated on 03/Oct/19 Commented by 7890542135678 last updated on 03/Oct/19 $${Find}\:\angle{BAC} \\ $$ Answered by mr W last updated…
Question Number 135827 by otchereabdullai@gmail.com last updated on 16/Mar/21 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{a}\:\mathrm{circle}\:\mathrm{leaving}\:\mathrm{the}\: \\ $$$$\mathrm{answer}\:\mathrm{in}\:\pi. \\ $$$$\left.\mathrm{i}\right)\:\mathrm{if}\:\mathrm{it}\:\mathrm{area}\:\mathrm{is}\:\mathrm{doubled}\:\mathrm{it}\:\mathrm{circumference} \\ $$$$ \\ $$$$\left.\mathrm{ii}\right)\:\mathrm{if}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{it}\:\mathrm{cermi}-\mathrm{circle}\:\mathrm{is}\: \\ $$$$\mathrm{numerically}\:\mathrm{equal}\:\mathrm{to}\:\mathrm{the}\:\mathrm{arc}\:\mathrm{length}\:\mathrm{of} \\ $$$$\mathrm{a}\:\mathrm{quater}\:\mathrm{circle} \\ $$$$ \\…
Question Number 135824 by Khakie last updated on 16/Mar/21 $$\int_{\mathrm{0}} ^{{a}} \:\frac{{x}^{\mathrm{4}} \:\:{e}^{{x}} }{\left({e}^{{x}} \:−\mathrm{1}\right)^{\mathrm{2}} }\:{dt} \\ $$$$ \\ $$$${please}\:{solve}\:{this}… \\ $$ Commented by mathmax…
Question Number 4758 by madscientist last updated on 05/Mar/16 $$\int_{−\infty} ^{\infty} {e}^{−{x}^{\mathrm{2}\:} } \:{dx}\:=\:\sqrt{\pi\:} \\ $$$${is}\:{this}\:{true},\:{if}\:{so}\:{how}? \\ $$ Answered by Yozzii last updated on 05/Mar/16…