Question Number 139123 by dayladau1234 last updated on 22/Apr/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 73553 by 01 last updated on 13/Nov/19 $$\mathrm{give}:\:\mathrm{a},\mathrm{b},\mathrm{c}>\mathrm{0} \\ $$$$\mathrm{if}\:\mathrm{a}\mid\mathrm{b}\:\mathrm{and}\:\mathrm{b}\mid\mathrm{c} \\ $$$$\mathrm{prove}\::\:\mathrm{a}\mid\mathrm{c} \\ $$ Answered by Rio Michael last updated on 13/Nov/19 $${a}\mid{b}\:\Leftrightarrow\:\exists\:{k}\in\mathbb{Z}\::\:\:{b}\:=\:{ka}\:……\left({i}\right)…
Question Number 7988 by Tinku Tara last updated on 26/Sep/16 $$\boldsymbol{\mathrm{Feedback}}\:\boldsymbol{\mathrm{request}} \\ $$$$\bullet\:\mathrm{Any}\:\mathrm{symbols}\:\mathrm{that}\:\mathrm{needs}\:\mathrm{to}\:\mathrm{be} \\ $$$$\:\:\:\:\mathrm{added}.\:\mathrm{We}\:\mathrm{are}\:\mathrm{aware}\:\mathrm{of}\:\mathrm{the}\:\mathrm{following} \\ $$$$\:\:\:\:\mathrm{which}\:\mathrm{will}\:\mathrm{be}\:\mathrm{added}\:\mathrm{in}\:\mathrm{next}\:\mathrm{update}: \\ $$$$\:\:\:\:-\:\mathrm{vertical}\:\mathrm{dots}\: \\ $$$$\:\:\:\:-\:\mathrm{contour}\:\mathrm{integral} \\ $$$$\:\:\:\:-\:\mathrm{is}\:\mathrm{congurant}\:\mathrm{to} \\ $$$$\mathrm{Please}\:\mathrm{let}\:\mathrm{us}\:\mathrm{know}\:\mathrm{any}\:\mathrm{symbols}…
Question Number 139056 by sahnaz last updated on 21/Apr/21 $$\left(\mathrm{x}^{\mathrm{2}} −\mathrm{10}×+\mathrm{6}\right)^{\mathrm{x}−\mathrm{2}} >\mathrm{1} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 139053 by mathocean1 last updated on 21/Apr/21 Commented by mathocean1 last updated on 21/Apr/21 $${Determinate}\:{R} \\ $$ Answered by mr W last updated…
Question Number 73523 by 01 last updated on 13/Nov/19 $$\mathrm{prove}\:\mathrm{that}\::\: \\ $$$$\:\mathrm{2}^{\pi} >\mathrm{8} \\ $$ Answered by MJS last updated on 13/Nov/19 $$\mathrm{3}<\pi\:\Rightarrow\:\pi=\mathrm{3}+{p};\:{p}>\mathrm{0} \\ $$$$\mathrm{2}^{\mathrm{3}+{p}}…
Question Number 139027 by mohammad17 last updated on 21/Apr/21 $${find}\:{Re}\left({z}\right)\:{and}\:{Im}\left({z}\right)\:{of}\:\left[\left({e}^{{i}\left(\mathrm{1}+\mathrm{2}{k}\right)\pi} \right)^{\frac{\mathrm{1}}{\mathrm{10}}} +\mathrm{1}\right]^{−\mathrm{1}} \\ $$$$ \\ $$ Commented by mohammad17 last updated on 21/Apr/21 $$???? \\…
Question Number 139023 by mohammad17 last updated on 21/Apr/21 $${find}\:{Re}\left({z}\right)\:{and}\:{Im}\left({z}\right)\:{of}\:{z}=\left(−\mathrm{2}{i}\right)^{−\frac{\mathrm{3}}{\mathrm{2}}} \\ $$ Answered by MJS_new last updated on 21/Apr/21 $$−\mathrm{2i}=\mathrm{2e}^{−\frac{\pi}{\mathrm{2}}\mathrm{i}} \\ $$$$\left(\mathrm{2e}^{−\frac{\pi}{\mathrm{2}}\mathrm{i}} \right)^{−\frac{\mathrm{3}}{\mathrm{2}}} =\mathrm{2}^{−\frac{\mathrm{3}}{\mathrm{2}}} \mathrm{e}^{\frac{\mathrm{3}\pi}{\mathrm{4}}\mathrm{i}}…
Question Number 73474 by revublik last updated on 13/Nov/19 $$\rceil\mathrm{888}>>>>>>> \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 138998 by ZiYangLee last updated on 21/Apr/21 $$\int\:\left(\frac{{e}^{−\mathrm{1}/{x}} }{{x}^{\mathrm{2}} }\right)\:{dx}\:=? \\ $$ Answered by phanphuoc last updated on 21/Apr/21 $$=\int{e}^{\left(−\mathrm{1}/{x}\right)} {d}\left(−\mathrm{1}/{x}\right)={e}^{−\mathrm{1}/{x}} +{c} \\…