Question Number 1882 by madscientist last updated on 21/Oct/15 $$\underset{−\infty} {\overset{\infty} {\int}}\underset{−\infty} {\overset{\infty} {\int}}\mid\psi\left({r},{t}\right)\mid\in\mid\phi\left({r},{t}\right)\mid\Rightarrow\lambda\left({x}\right)\: \\ $$$${in}\:{quantum}\:{mechanics}\:{would}\:{this}\:{be} \\ $$$${true},\:{if}\:{so}\:{how}? \\ $$$$ \\ $$$$ \\ $$ Terms…
Question Number 132950 by mohammad17 last updated on 17/Feb/21 $${write}\:\frac{\left(\mathrm{1}−{i}\right)^{\mathrm{23}} }{\left(\sqrt{\mathrm{3}}−{i}\right)^{\mathrm{13}} }\:{in}\left(\:{re}^{{i}\theta} \right) \\ $$ Answered by metamorfose last updated on 17/Feb/21 $${z}=\frac{\left(\mathrm{1}−{i}\right)^{\mathrm{23}} }{\:\left(\sqrt{\mathrm{3}}−{i}\right)^{\mathrm{13}} }=\frac{\mathrm{1}}{\mathrm{2}\sqrt{\mathrm{2}}}\:{e}^{{i}\frac{\mathrm{5}\pi}{\mathrm{12}}}…
Question Number 132937 by mohammad17 last updated on 17/Feb/21 $${solve}\:{the}\:{equation}\:{in}\:{complex}\:{number} \\ $$$${z}^{\mathrm{3}} ={z}_{{o}} \\ $$ Answered by mr W last updated on 17/Feb/21 $${z}_{\mathrm{0}} ={re}^{\theta{i}}…
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Question Number 132923 by mohammad17 last updated on 17/Feb/21 Commented by mohammad17 last updated on 17/Feb/21 $${help}\:{me}\:{sir} \\ $$$$ \\ $$ Terms of Service Privacy…
Question Number 132912 by SEKRET last updated on 17/Feb/21 $$ \\ $$ Commented by mr W last updated on 17/Feb/21 $${a}\:{lot}\:{of}\:{your}\:{posts}\:{are}\:{just}\:{blank}. \\ $$$${accidentally}\:{or}\:{purposely}? \\ $$…
Question Number 132899 by aurpeyz last updated on 17/Feb/21 $${an}\:{object}\:{of}\:\mathrm{12}{cm}\:{long}\:{is}\:{placed}\:{at}\:{the}\: \\ $$$${centre}\:{of}\:{curvature}\:{of}\:{concave}\:{mirror} \\ $$$${whose}\:{focal}\:{length}\:{is}\:\mathrm{40}{cm}.\:{the}\:{location} \\ $$$${of}\:{the}\:{image}\:{formed}\:{is}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 132880 by faysal last updated on 17/Feb/21 $${cot}\left(\mathrm{142}.\mathrm{5}°\right)=? \\ $$ Commented by bramlexs22 last updated on 17/Feb/21 $$\mathrm{285}°=\:\mathrm{2}×\mathrm{142}.\mathrm{5} \\ $$$$\mathrm{285}°=\mathrm{270}°+\mathrm{15}° \\ $$$$\mathrm{cot}\:\mathrm{285}°\:=\:\mathrm{cot}\:\mathrm{285}° \\…
Question Number 1805 by ình Plus 001 last updated on 03/Oct/15 $${WTF} \\ $$ Answered by 123456 last updated on 03/Oct/15 $$\mathrm{Dolphins} \\ $$$$ \\…
Question Number 132878 by aurpeyz last updated on 17/Feb/21 $${is}\:{the}\:{surface}\:{of}\:{a}\:{mirror}\:{refractive} \\ $$$${or}\:{reflective}? \\ $$ Commented by Dwaipayan Shikari last updated on 17/Feb/21 $${Generally}\:{reflective}\:..\:{but}\:{sometimes}\:{refractive}.. \\ $$…