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Pleas-update-the-app-to-latest-version-New-version-added-image-upload-and-few-extra-characters-hyphen-Only-users-with-latest-version-will-be-able-to-see-post-containg-images-

Question Number 3999 by Tinku Tara last updated on 26/Dec/15 $$\mathrm{Pleas}\:\mathrm{update}\:\mathrm{the}\:\mathrm{app}\:\mathrm{to}\:\mathrm{latest}\:\mathrm{version}. \\ $$$$\mathrm{New}\:\mathrm{version}\:\mathrm{added}\:\mathrm{image}\:\mathrm{upload}\:\mathrm{and}\:\mathrm{few} \\ $$$$\mathrm{extra}\:\mathrm{characters}\:\left(\mathrm{hyphen}\right). \\ $$$$\mathrm{Only}\:\mathrm{users}\:\mathrm{with}\:\mathrm{latest}\:\mathrm{version}\:\mathrm{will}\:\mathrm{be}\:\mathrm{able} \\ $$$$\mathrm{to}\:\mathrm{see}\:\mathrm{post}\:\mathrm{containg}\:\mathrm{images}. \\ $$ Commented by Tinku Tara…

Define-the-sequence-a-n-by-the-recursive-formula-a-n-1-ca-n-nr-n-1-n-Z-n-1-with-a-1-h-and-c-r-h-C-c-r-0-Find-a-n-in-terms-of-n-

Question Number 3974 by Yozzii last updated on 26/Dec/15 $${Define}\:{the}\:{sequence}\:\left\{{a}_{{n}} \right\}\:{by}\:{the} \\ $$$${recursive}\:{formula}\: \\ $$$$\:\:\:{a}_{{n}+\mathrm{1}} ={ca}_{{n}} −{nr}^{{n}−\mathrm{1}} \:\:\:\left({n}\in\mathbb{Z},{n}\geqslant\mathrm{1}\right) \\ $$$${with}\:{a}_{\mathrm{1}} ={h}\:{and}\:{c},{r},{h}\in\mathbb{C},\:{c},{r}\neq\mathrm{0}. \\ $$$${Find}\:{a}_{{n}} \:{in}\:{terms}\:{of}\:{n}. \\…

5-integers-are-selected-randomly-from-Z-what-is-the-probability-that-at-least-one-of-them-is-divisible-by-5-

Question Number 3927 by prakash jain last updated on 24/Dec/15 $$\mathrm{5}\:\mathrm{integers}\:\mathrm{are}\:\mathrm{selected}\:\mathrm{randomly}\:\mathrm{from}\:\mathbb{Z}^{+} \\ $$$$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{probability}\:\mathrm{that}\:\mathrm{at}\:\mathrm{least}\:\mathrm{one} \\ $$$$\mathrm{of}\:\mathrm{them}\:\mathrm{is}\:\mathrm{divisible}\:\mathrm{by}\:\mathrm{5}. \\ $$ Commented by prakash jain last updated on 26/Dec/15…

Question-134987

Question Number 134987 by 0731619177 last updated on 09/Mar/21 Answered by Olaf last updated on 09/Mar/21 $$\mathrm{I}_{\mathrm{2}} \left({k}\right)\:=\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \frac{{x}\mathrm{sin}{x}\mathrm{cos}{x}}{\:\sqrt{\mathrm{1}−{k}^{\mathrm{2}} \mathrm{sin}^{\mathrm{2}} {x}}}\:{dx} \\ $$$$\mathrm{I}_{\mathrm{2}} \left({k}\right)\:=\:−\frac{\mathrm{1}}{{k}^{\mathrm{2}}…

Question-134977

Question Number 134977 by 0731619177 last updated on 09/Mar/21 Answered by Ñï= last updated on 09/Mar/21 $${tanhx}=\frac{{x}}{\mathrm{1}+\frac{{x}^{\mathrm{2}} }{\mathrm{3}+\frac{{x}^{\mathrm{2}} }{\mathrm{5}+\frac{{x}^{\mathrm{2}} }{\mathrm{7}+…}}}} \\ $$$$\int_{{a}} ^{{b}} {tanhxdx}={ln}\left(\mathrm{cosh}\:{x}\right)\mid_{{a}} ^{{b}}…