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Question-198302

Question Number 198302 by sonukgindia last updated on 17/Oct/23 Answered by mr W last updated on 17/Oct/23 $${z}_{\mathrm{1}} =\mathrm{1}+{i}\sqrt{\mathrm{3}}=\mathrm{2}{e}^{{i}\left(\frac{\pi}{\mathrm{3}}\right)} \\ $$$${z}_{\mathrm{2}} =\mathrm{2}{e}^{{i}\left(\frac{\pi}{\mathrm{3}}+\frac{\mathrm{2}\pi}{\mathrm{3}}\right)} =\mathrm{2}{e}^{{i}\pi} =−\mathrm{2} \\…

Question-198313

Question Number 198313 by sonukgindia last updated on 17/Oct/23 Commented by AST last updated on 17/Oct/23 $${n}^{\mathrm{2}} \equiv\mathrm{34}\left({mod}\:\mathrm{15}\right)?\Rightarrow{n}^{\mathrm{2}} \equiv\mathrm{4}\left({mod}\:\mathrm{15}\right) \\ $$$$\Rightarrow{n}=\mathrm{2},\mathrm{7},\mathrm{8},\mathrm{13}\left({mod}\:\mathrm{15}\right) \\ $$ Terms of…

Question-198282

Question Number 198282 by MathedUp last updated on 16/Oct/23 Answered by witcher3 last updated on 25/Oct/23 $$\begin{cases}{\mathrm{2cos}\left(\mathrm{t}\right)}\\{\mathrm{2sin}\left(\mathrm{t}\right)}\end{cases},\mathrm{t}\in\left[\mathrm{0},\mathrm{2}\pi\right]\:\mathrm{circle}\:\mathrm{radius}=\mathrm{2}\:\mathrm{origine}\left(\mathrm{0},\mathrm{0}\right) \\ $$$$\int_{\mathrm{C}} \left(−\frac{\mathrm{xy}}{\mathrm{5}}\mathrm{dx}+\mathrm{2ydy}\right)=\int\int_{\mathrm{D}} \left(\partial\frac{\mathrm{2y}}{\partial\mathrm{x}}−\frac{\partial}{\partial\mathrm{y}}\left(−\frac{\mathrm{xy}}{\mathrm{5}}\right)\right)\mathrm{dA} \\ $$$$=\int\int_{\mathrm{D}} \left(\frac{\mathrm{x}}{\mathrm{5}}\right)\mathrm{dA} \\…

Question-198276

Question Number 198276 by essaad last updated on 16/Oct/23 Answered by witcher3 last updated on 16/Oct/23 $$\left(\mathrm{x}=\mathrm{y}\right)\Rightarrow\mathrm{f}\left(\mathrm{2x}\right)+\mathrm{2f}\left(\mathrm{0}\right)=\mathrm{1} \\ $$$$\Leftrightarrow\mathrm{f}\left(\mathrm{2x}\right)=\mathrm{1}−\mathrm{2f}\left(\mathrm{0}\right) \\ $$$$\mathrm{x}\rightarrow\mathrm{2x}\:\mathrm{surjective}\Leftrightarrow\forall\mathrm{t}\in\mathbb{R}\:\mathrm{f}\left(\mathrm{t}\right)=\mathrm{1}−\mathrm{2f}\left(\mathrm{0}\right)\:\mathrm{constant} \\ $$$$ \\ $$…

if-3-sin-x-cosx-3-

Question Number 198237 by liuxinnan last updated on 15/Oct/23 $${if}\:\:−\sqrt{\mathrm{3}}\leqslant{sin}\left({x}+\varphi\right)+{cosx}\leqslant\sqrt{\mathrm{3}} \\ $$$$\varphi=? \\ $$ Answered by mr W last updated on 15/Oct/23 $$\mathrm{sin}\:\left({x}+\varphi\right)+\mathrm{cos}\:{x} \\ $$$$=\mathrm{cos}\:\varphi\:\mathrm{sin}\:{x}+\left(\mathrm{sin}\:\varphi+\mathrm{1}\right)\:\mathrm{cos}\:{x}…

help-i-j-k-est-une-base-orthonormee-A-B-C-et-D-sont-des-points-de-l-espace-tels-que-AB-i-j-k-AC-2i-3j-k-AD-i-2j-2k-Determine-tous-les-poin

Question Number 198260 by maths_plus last updated on 15/Oct/23 $$\mathrm{help}\:! \\ $$$$\left(\overset{\rightarrow} {{i}},\overset{\rightarrow} {{j}},\overset{\rightarrow} {{k}}\right)\:\mathrm{est}\:\mathrm{une}\:\mathrm{base}\:\mathrm{orthonormee}. \\ $$$$\mathrm{A},\:\mathrm{B},\:\mathrm{C}\:\mathrm{et}\:\mathrm{D}\:\mathrm{sont}\:\mathrm{des}\:\mathrm{points}\:\mathrm{de}\:\mathrm{l}'\mathrm{espace} \\ $$$$\mathrm{tels}\:\mathrm{que}\::\: \\ $$$$\overset{\rightarrow} {\mathrm{AB}}=\overset{\rightarrow} {{i}}+\overset{\rightarrow} {{j}}+\overset{\rightarrow} {{k}}…