Question Number 7587 by ten last updated on 05/Sep/16 $${cos}\mathrm{4}{xsin}\mathrm{4}{x} \\ $$ Answered by Rasheed Soomro last updated on 05/Sep/16 $${cos}\mathrm{4}{xsin}\mathrm{4}{x} \\ $$$$\mathrm{cos}\:\alpha\:\mathrm{sin}\:\beta=\left(\mathrm{1}/\mathrm{2}\right)\left[\mathrm{sin}\left(\alpha+\beta\right)−\mathrm{sin}\left(\alpha−\beta\right)\right]\:\: \\ $$$$\mathrm{cos}\:\mathrm{4}{x}\:\mathrm{sin}\:\mathrm{4}{x}=\left(\mathrm{1}/\mathrm{2}\right)\left[\mathrm{sin}\left(\mathrm{4}{x}+\mathrm{4}{x}\right)−\mathrm{sin}\left(\mathrm{4}{x}−\mathrm{4}{x}\right)\right]\:\:…
Question Number 7582 by A WLAN last updated on 04/Sep/16 Commented by A WLAN last updated on 04/Sep/16 $${How}\:{to}\:{solve}\:{this}\:{problem}? \\ $$ Answered by Yozzia last…
Question Number 7579 by ajy last updated on 04/Sep/16 $$\mathrm{2}×\mathrm{2} \\ $$ Answered by FilupSmith last updated on 04/Sep/16 $$\mathrm{4} \\ $$ Terms of Service…
Question Number 138631 by physicstutes last updated on 15/Apr/21 Commented by physicstutes last updated on 15/Apr/21 $$\mathrm{From}\:\mathrm{the}\:\mathrm{figure}\:\mathrm{above}\:\mathrm{show}\:\mathrm{completely}\:\mathrm{how}\:\mathrm{the}\:\mathrm{force}\:\mathrm{on}\:\mathrm{the} \\ $$$$\mathrm{pulley}\:\mathrm{can}\:\mathrm{be}\:\mathrm{obtained}. \\ $$ Commented by Dwaipayan Shikari…
Question Number 138628 by mohammad17 last updated on 15/Apr/21 $${find}\:{the}\:{region}\:{in}\:{which}\:{the}\:{function}\: \\ $$$$ \\ $$$${f}\left({z}\right)=\frac{{log}\left({z}−\mathrm{2}{i}\right)}{{z}^{\mathrm{2}} +\mathrm{1}}\:{is}\:{analytic}\:? \\ $$$$ \\ $$$${help}\:{me}\:{sir}\: \\ $$ Commented by mohammad17 last…
Question Number 7562 by Master Moon last updated on 03/Sep/16 $$\left({U}_{{n}} \right)=\:\mathrm{2},\mathrm{3},\mathrm{5},\mathrm{6},\mathrm{7},\mathrm{8},\mathrm{10},\mathrm{11},\mathrm{12},\mathrm{13},\mathrm{14},…. \\ $$$${find}\:{U}_{{n}} \\ $$ Commented by Rasheed Soomro last updated on 03/Sep/16 $${Perfect}\:{square}\:{numbers}\:{have}\:\:{been}\:{excluded}\:{from}…
Question Number 7552 by Master Moon last updated on 03/Sep/16 $$\sqrt{\mathrm{4}}+\mathrm{5}\:= \\ $$ Answered by FilupSmith last updated on 03/Sep/16 $$\sqrt{\mathrm{4}}=\pm\mathrm{2} \\ $$$$\therefore\sqrt{\mathrm{4}}+\mathrm{5}=\mathrm{5}\pm\mathrm{2}=\mathrm{3},\:\mathrm{7} \\ $$…
Question Number 138627 by KwesiDerek last updated on 15/Apr/21 $$\boldsymbol{\mathrm{x}}^{\mathrm{2}} =\mathrm{16}^{\boldsymbol{\mathrm{x}}} \\ $$$$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{x}} \\ $$ Commented by soudo last updated on 15/Apr/21 $$\mathrm{nice} \\ $$…
Question Number 138612 by SOMEDAVONG last updated on 15/Apr/21 $$\mathrm{If}\:\mathrm{z}+\:\frac{\mathrm{1}}{\mathrm{z}}\:=\mathrm{2cos}\beta\:.\mathrm{show}\:\mathrm{that}\:\mathrm{z}^{\mathrm{m}} +\frac{\mathrm{1}}{\mathrm{z}^{\mathrm{m}} }\:=\mathrm{2cosm}\beta. \\ $$ Answered by Ar Brandon last updated on 15/Apr/21 $$\mathrm{z}=\mathrm{e}^{\mathrm{i}\beta} \\ $$$$\mathrm{z}^{\mathrm{m}}…
Question Number 7541 by 314159 last updated on 03/Sep/16 Commented by prakash jain last updated on 03/Sep/16 $${a}\left(\mathrm{1}+{r}+{r}^{\mathrm{2}} +{r}^{\mathrm{3}} +{r}^{\mathrm{4}} \right)=\mathrm{211} \\ $$$${a}\:{and}\:{r}\:{integers} \\ $$$$\mathrm{211}=\mathrm{1}×\mathrm{211}\Rightarrow{a}=\mathrm{1}…