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Question Number 7507 by Master Moon last updated on 01/Sep/16 $$\boldsymbol{{Given}}\:\boldsymbol{{r}},\:\boldsymbol{{t}},\:\boldsymbol{{j}}\:>\mathrm{0}\:\boldsymbol{{and}}\:\boldsymbol{{n}}\geqslant\mathrm{1};\:\boldsymbol{{Prove}}\:\boldsymbol{{that}} \\ $$$$\frac{\left[\underset{\boldsymbol{{p}}_{\mathrm{1}} =\mathrm{1}} {\overset{\boldsymbol{{n}}} {\sum}}\left(\boldsymbol{{p}}_{\mathrm{1}} ^{\boldsymbol{{r}}} +\boldsymbol{{r}}\right)+\underset{\boldsymbol{{p}}_{\mathrm{2}} =\mathrm{1}} {\overset{\boldsymbol{{n}}} {\sum}}\left(\boldsymbol{{p}}_{\mathrm{2}} ^{\boldsymbol{{t}}} +\boldsymbol{{t}}\right)\right]^{\mathrm{2}} }{\boldsymbol{{n}}^{\mathrm{2}} \left[\left(\boldsymbol{{n}}!\right)^{\frac{\boldsymbol{{r}}+\boldsymbol{{t}}}{\boldsymbol{{n}}}}…

Question Number 138575 by KwesiDerek last updated on 15/Apr/21 $$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{x}} \\ $$$$\boldsymbol{\mathrm{x}}^{\mathrm{2}} −\mathrm{2}^{\boldsymbol{\mathrm{x}}} =\mathrm{1} \\ $$$$\boldsymbol{\mathrm{Any}}\:\boldsymbol{\mathrm{help}} \\ $$ Commented by soudo last updated on 15/Apr/21…

Question Number 138536 by Tinku Tara last updated on 14/Apr/21 $$\mathrm{This}\:\mathrm{app}\:\mathrm{is}\:\mathrm{now}\:\mathrm{free}\:\mathrm{as}\:\mathrm{several}\:\mathrm{users} \\ $$$$\mathrm{do}\:\mathrm{not}\:\mathrm{have}\:\mathrm{cards}\:\mathrm{and}\:\mathrm{are}\:\mathrm{not}\:\mathrm{able} \\ $$$$\mathrm{to}\:\mathrm{upgrade}.\:\mathrm{Manual}\:\mathrm{entry}\:\mathrm{in}\:\mathrm{backend} \\ $$$$\mathrm{system}\:\mathrm{had}\:\mathrm{put}\:\mathrm{lot}\:\mathrm{of}\:\mathrm{overhead}. \\ $$$$\mathrm{Hence}\:\mathrm{we}\:\mathrm{have}\:\mathrm{decide}\:\mathrm{to}\:\mathrm{make}\:\mathrm{this} \\ $$$$\mathrm{app}\:\mathrm{free}. \\ $$$$\mathrm{We}\:\mathrm{issued}\:\mathrm{several}\:\mathrm{refunds}\:\mathrm{for}\:\mathrm{users} \\ $$$$\mathrm{who}\:\mathrm{had}\:\mathrm{bought}.\:\mathrm{However}\:\mathrm{Google}…

Question Number 72997 by yannickmendes_33 last updated on 05/Nov/19 $${The}\:{area}\:{of}\:{the}\:{equilateral}\:{triangle}\:{is}\:{equal}\:{to}\:\frac{\sqrt{\mathrm{16}}\sqrt{\mathrm{8}}}{\mathrm{3}\sqrt{\pi}} \\ $$$${Calculate}\:{the}\:{area}\:{of}\:{the}\:{circle}\:{inscribed}\:{in}\:{the}\:{triangle}. \\ $$$$\: \\ $$ Answered by Kunal12588 last updated on 05/Nov/19 $${area}\:{of}\:{equilateral}\:\bigtriangleup\:=\:\frac{\sqrt{\mathrm{3}}\:{a}^{\mathrm{2}} }{\mathrm{4}}=\frac{\sqrt{\mathrm{16}}\sqrt{\mathrm{8}}}{\mathrm{3}\sqrt{\pi}}=\frac{\mathrm{8}\sqrt{\mathrm{2}}}{\mathrm{3}\sqrt{\pi}}…

Question Number 138495 by yutytfjh67ihd last updated on 14/Apr/21 Commented by yutytfjh67ihd last updated on 14/Apr/21 $$\mathrm{Some}\:\mathrm{missing}\:\mathrm{unsolved}\:\mathrm{probelm}. \\ $$ Terms of Service Privacy Policy Contact:…