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A-mirror-is-designed-so-that-any-ray-of-light-which-hits-one-side-of-the-mirror-and-which-is-parallel-to-a-certain-fixed-line-L-is-reflected-through-a-fixed-point-O-Prove-that-the-mirror-intersects-

Question Number 2129 by Yozzi last updated on 03/Nov/15 $${A}\:{mirror}\:{is}\:{designed}\:{so}\:{that}\:{any}\:{ray} \\ $$$${of}\:{light}\:{which}\:{hits}\:{one}\:{side}\:{of}\:{the} \\ $$$${mirror}\:{and}\:{which}\:{is}\:{parallel}\:{to}\:{a}\: \\ $$$${certain}\:{fixed}\:{line}\:{L}\:{is}\:{reflected}\:{through} \\ $$$${a}\:{fixed}\:{point}\:{O}.\:{Prove}\:{that}\:{the}\:{mirror} \\ $$$${intersects}\:{any}\:{plane}\:{containing}\:{L}\:{in} \\ $$$${a}\:{parabola}. \\ $$$${I}\:{would}\:{appreciate}\:{a}\:{formal}\:{proof}. \\…

g-x-y-x-4-y-4-2-x-y-2-find-criticals-points-of-g-x-y-and-hers-nature-

Question Number 133191 by pticantor last updated on 19/Feb/21 $$\boldsymbol{{g}}\left(\boldsymbol{{x}},\boldsymbol{{y}}\right)=\boldsymbol{{x}}^{\mathrm{4}} +\boldsymbol{{y}}^{\mathrm{4}} −\mathrm{2}\left(\boldsymbol{{x}}−\boldsymbol{{y}}\right)^{\mathrm{2}} \\ $$$$\boldsymbol{{find}}\:\boldsymbol{{criticals}}\:\boldsymbol{{points}}\:\boldsymbol{{of}}\:\boldsymbol{{g}}\left(\boldsymbol{{x}},\boldsymbol{{y}}\right) \\ $$$$\boldsymbol{{and}}\:\boldsymbol{{hers}}\:\boldsymbol{{nature}} \\ $$ Answered by Olaf last updated on 20/Feb/21…

x-2-1-3-dx-

Question Number 133183 by bounhome last updated on 19/Feb/21 $$\int\sqrt{\left({x}^{\mathrm{2}} +\mathrm{1}\right)^{\mathrm{3}} }{dx}=…? \\ $$ Answered by physicstutes last updated on 19/Feb/21 $$\mathrm{let}\:{x}\:=\:\mathrm{sinh}\:\theta\:\Rightarrow\:{dx}\:=\:\mathrm{cosh}\:\theta\:{d}\theta \\ $$$$\mathrm{now},\:\int\sqrt{\left[\left(\mathrm{sinh}\:\theta\right)^{\mathrm{2}} +\mathrm{1}\right]^{\mathrm{3}}…

1-sin-3-x-dx-

Question Number 133117 by SOMEDAVONG last updated on 19/Feb/21 $$\int\frac{\mathrm{1}}{\mathrm{sin}^{\mathrm{3}} \mathrm{x}}\mathrm{dx}=? \\ $$ Answered by bemath last updated on 19/Feb/21 $$=\:−\frac{\mathrm{1}}{\mathrm{2}}\mathrm{cot}\:\mathrm{x}\:\mathrm{csc}\:\mathrm{x}\:−\frac{\mathrm{1}}{\mathrm{2}}\mathrm{ln}\:\mid\mathrm{sec}\:\mathrm{x}−\mathrm{cot}\:\mathrm{x}\mid\:+\:\mathrm{C} \\ $$ Terms of…

an-object-is-placed-5cm-away-from-a-plane-mirror-the-mirror-is-rotated-tbrough-angle-20-0-about-the-point-of-incidence-calculate-the-shortest-distance-between-the-old-and-the-new-position-of-the-im

Question Number 133115 by aurpeyz last updated on 19/Feb/21 $${an}\:{object}\:{is}\:{placed}\:\mathrm{5}{cm}\:{away}\:{from}\:{a} \\ $$$${plane}\:{mirror}.\:{the}\:{mirror}\:{is}\:{rotated} \\ $$$${tbrough}\:{angle}\:\mathrm{20}^{\mathrm{0}} \:{about}\:{the}\:{point}\:{of} \\ $$$${incidence}.\:{calculate}\:{the}\:{shortest} \\ $$$${distance}\:{between}\:{the}\:{old}\:{and}\:{the}\:{new} \\ $$$${position}\:{of}\:{the}\:{image} \\ $$ Answered by…

Assuming-that-word-population-is-6-billion-and-total-world-trips-is-4-8-billion-a-what-is-the-country-potential-generation-index-CPG-I-of-the-country-b-interprete-your-results-in-a-above-

Question Number 133097 by otchereabdullai@gmail.com last updated on 18/Feb/21 $$\mathrm{Assuming}\:\mathrm{that}\:\mathrm{word}\:\mathrm{population}\:\mathrm{is}\: \\ $$$$\mathrm{6}\:\mathrm{billion}\:\mathrm{and}\:\mathrm{total}\:\mathrm{world}\:\mathrm{trips}\:\mathrm{is}\: \\ $$$$\mathrm{4}.\mathrm{8}\:\mathrm{billion} \\ $$$$\left(\mathrm{a}\right)\:\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{country}\:\mathrm{potential}\: \\ $$$$\mathrm{generation}\:\mathrm{index}\:\left(\mathrm{CPG}\:\mathrm{I}\right)\:\mathrm{of}\:\mathrm{the}\: \\ $$$$\mathrm{country} \\ $$$$\left(\mathrm{b}\right)\:\mathrm{interprete}\:\mathrm{your}\:\mathrm{results}\:\mathrm{in}\:\left(\mathrm{a}\right)\:\mathrm{above}\: \\ $$$$ \\…

Question-67564

Question Number 67564 by azizullah last updated on 28/Aug/19 Commented by mathmax by abdo last updated on 28/Aug/19 $${F}\left(\mathrm{0}\right)=\mathrm{0}\:=\mathrm{1}+\mathrm{1}\:+\mathrm{2}\:+{f}\:\Rightarrow{f}\:=−\mathrm{4}\:\Rightarrow \\ $$$${F}\left({x}\right)\:=−\frac{\mathrm{1}}{{x}−\mathrm{1}}+\frac{\mathrm{1}}{{x}+\mathrm{1}}\:+\frac{\mathrm{2}}{{x}^{\mathrm{2}} \:+\mathrm{1}}−\frac{\mathrm{4}}{\left({x}^{\mathrm{2}} \:+\mathrm{1}\right)^{\mathrm{2}} }\:. \\…

Question-67561

Question Number 67561 by azizullah last updated on 28/Aug/19 Answered by Rasheed.Sindhi last updated on 28/Aug/19 $${Let}\:\frac{\mathrm{2}{x}+\mathrm{1}}{\left({x}^{\mathrm{2}} +\mathrm{1}\right)\left({x}−\mathrm{1}\right)}=\frac{{Ax}+{B}}{{x}^{\mathrm{2}} +\mathrm{1}}+\frac{{C}}{{x}−\mathrm{1}} \\ $$$$\:\:\:\:\:\:\:\:\left({Ax}+{B}\right)\left({x}−\mathrm{1}\right)+{C}\left({x}^{\mathrm{2}} +\mathrm{1}\right)=\mathrm{2}{x}+\mathrm{1} \\ $$$${x}=\mathrm{1}\Rightarrow\mathrm{2}{C}=\mathrm{3}\Rightarrow{C}=\mathrm{3}/\mathrm{2} \\…