Question Number 2649 by Filup last updated on 24/Nov/15 $$\mathrm{Ok}\:\mathrm{guys}.\:\mathrm{We}\:\mathrm{all}\:\mathscr{LOVE}\:\mathrm{mathematics}. \\ $$$$\mathrm{So},\:\mathrm{I}\:\mathrm{have}\:\mathrm{came}\:\mathrm{up}\:\mathrm{with}\:\mathrm{a}\:\mathrm{simple}\:\mathrm{and} \\ $$$$\mathrm{possibly}\:\mathrm{effect}\:\mathrm{way}\:\mathrm{to}\:\mathrm{not}\:\mathrm{only}\:\mathrm{improve} \\ $$$$\mathrm{our}\:\mathrm{abilities}\:\mathrm{as}\:\mathrm{mathematicians},\:\mathrm{but}\:\mathrm{also} \\ $$$$\mathrm{have}\:\mathrm{some}\:\mathrm{fun},\:\mathrm{too}. \\ $$$$ \\ $$$$\mathrm{We}\:\mathrm{should}\:\mathrm{hold}\:\mathrm{a}\:\mathrm{competition}\:\mathrm{every} \\ $$$$\mathrm{now}\:\mathrm{and}\:\mathrm{again}.\:\mathrm{We}\:\mathrm{can},\:\mathrm{for}\:\mathrm{example} \\…
Question Number 68171 by naka3546 last updated on 06/Sep/19 Commented by mathmax by abdo last updated on 06/Sep/19 $$ \\ $$$$\sqrt{\mathrm{5}−\mathrm{2}\sqrt{{x}}\:}\:{is}\:{not}\:{defined}\:{on}\:+\infty\:! \\ $$ Commented by…
Question Number 133668 by Study last updated on 23/Feb/21 $$\mathrm{2}{x}×−\mathrm{2}\left\{\mathrm{3}{x}−\left(\mathrm{2}+{x}\right)−\mathrm{1}\right\}\boldsymbol{\div}\mathrm{2}=? \\ $$ Commented by Study last updated on 24/Feb/21 $${why}\:{you}\:{not}\:{ans}\:{me}? \\ $$ Terms of Service…
Question Number 133669 by Study last updated on 23/Feb/21 $$\frac{\mathrm{1}}{\mathrm{3}}{y}−\mathrm{5}\left\{−\mathrm{2}\left[\mathrm{6}\left({y}−\frac{\mathrm{1}}{\mathrm{3}}−{y}\right]\right\}\boldsymbol{\div}\mathrm{3}=?\right. \\ $$ Commented by Ar Brandon last updated on 23/Feb/21 ���� Commented by Study last…
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Question Number 133641 by mohammad17 last updated on 23/Feb/21 $${what}\:{is}\:{the}\:{mean}\:{of}\:{Ei}\left({x}\right)\:{and}\:{what}\:{is} \\ $$$${the}\:{folmulla}\:{of}\:{Ei}\left({x}\right)? \\ $$ Answered by Dwaipayan Shikari last updated on 23/Feb/21 $${Ei}\left({x}\right)=\int_{\mathrm{0}} ^{{x}} \frac{{e}^{{x}}…
Question Number 2562 by Tinku Tara last updated on 22/Nov/15 $$\mathrm{App}\:\mathrm{Updates}: \\ $$$$\mathrm{We}\:\mathrm{have}\:\mathrm{updated}\:\mathrm{the}\:\mathrm{app}\:\mathrm{with}\:\mathrm{below}\:\mathrm{changes}: \\ $$$$\bullet\:\boldsymbol{\mathrm{ad}}\:\boldsymbol{\mathrm{banner}}\:\boldsymbol{\mathrm{removed}}\:\boldsymbol{\mathrm{from}}\:\boldsymbol{\mathrm{all}}\:\boldsymbol{\mathrm{screens}} \\ $$$$\:\:\:\:\mathrm{This}\:\mathrm{provides}\:\mathrm{larger}\:\mathrm{screen}\:\mathrm{area}\:\mathrm{for} \\ $$$$\:\:\:\:\:\mathrm{equation}\:\mathrm{writing}\:\mathrm{and}\:\mathrm{avoids}\:\mathrm{distraction}. \\ $$$$\bullet\:\boldsymbol{\mathrm{confirmation}}\:\boldsymbol{\mathrm{on}}\:\boldsymbol{\mathrm{delete}}\:\boldsymbol{\mathrm{posts}}\:\boldsymbol{\mathrm{on}}\:\boldsymbol{\mathrm{Q}}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{A}}\:\boldsymbol{\mathrm{forum}} \\ $$ Commented by…
Question Number 133633 by jahar last updated on 23/Feb/21 $${how}\:{to}\:{back}\:{up} \\ $$ Commented by Tinku Tara last updated on 23/Feb/21 Commented by Tinku Tara last…
Question Number 133628 by Ñï= last updated on 23/Feb/21 $$\underset{{n}=\mathrm{1}} {\overset{\infty} {\prod}}\left(\frac{{n}^{\mathrm{2}} +\mathrm{1}}{{n}^{\mathrm{2}} }\right)=? \\ $$$$\underset{{n}=\mathrm{1}} {\overset{\infty} {\prod}}\left(\frac{\mathrm{4}{n}^{\mathrm{2}} −\mathrm{4}{n}+\mathrm{2}}{\mathrm{4}{n}^{\mathrm{2}} −\mathrm{4}{n}+\mathrm{1}}\right)=? \\ $$ Answered by Dwaipayan…