Question Number 138249 by sahnaz last updated on 11/Apr/21 $$\mathrm{li}\underset{\mathrm{n}\rightarrow\mathrm{0}} {\mathrm{m}}\frac{\mathrm{2}^{\mathrm{n}+\mathrm{1}} +\mathrm{3}^{\mathrm{n}+\mathrm{2}} +\mathrm{4}^{\mathrm{n}+\mathrm{3}} }{\mathrm{2}^{\mathrm{n}} +\mathrm{3}^{\mathrm{n}} +\mathrm{4}^{\mathrm{n}} } \\ $$ Answered by mathmax by abdo last…
Question Number 138250 by sahnaz last updated on 11/Apr/21 $$\left(\mathrm{x}^{\mathrm{2}} −\mathrm{10x}+\mathrm{6}\right)^{\mathrm{x}−\mathrm{2}} >\mathrm{1} \\ $$ Answered by bobhans last updated on 11/Apr/21 $$\left({x}^{\mathrm{2}} −\mathrm{10}{x}+\mathrm{6}\right)^{{x}−\mathrm{2}} \:>\:\left({x}^{\mathrm{2}} −\mathrm{10}{x}+\mathrm{6}\right)^{\mathrm{0}}…
Question Number 138236 by mohammad17 last updated on 11/Apr/21 $${prove}\:{that}\: \\ $$$$ \\ $$$$\frac{{e}^{−\mathrm{2}{y}} }{\mathrm{1}+{e}^{−\mathrm{2}{y}} }<\mid{tan}\left({z}\right)\:−\:{i}\mid<\frac{{e}^{−\mathrm{2}{y}} }{\mathrm{1}−{e}^{−\mathrm{2}{y}} }\:\:\:,{y}>\mathrm{0} \\ $$$$ \\ $$$${how}\:{can}\:{solve}\:{this}\:? \\ $$ Commented…
Question Number 7164 by aftab ahmad last updated on 14/Aug/16 Answered by Yozzia last updated on 14/Aug/16 $${By}\:{Power}\:{of}\:{a}\:{Point}\:{theorem}, \\ $$$$\left({AB}\right)\left({AC}\right)=\left({AD}\right)\left({AD}\right)=\left({AD}\right)^{\mathrm{2}} \\ $$$$\Rightarrow{AC}=\frac{\left({AD}\right)^{\mathrm{2}} }{{AB}}=\frac{\mathrm{10}^{\mathrm{2}} }{\mathrm{5}}=\mathrm{20}{cm} \\…
Question Number 7159 by Master Moon last updated on 14/Aug/16 $$\boldsymbol{{log}}_{\mathrm{2}} \underset{\boldsymbol{{x}}=\mathrm{1}} {\overset{\mathrm{2015}} {\prod}}\:\underset{\boldsymbol{{y}}=\mathrm{1}} {\overset{\mathrm{2015}} {\prod}}\left(\mathrm{1}+\boldsymbol{{e}}^{\frac{\mathrm{2}\boldsymbol{\pi{ixy}}}{\mathrm{2015}}} \right)\:=\:? \\ $$ Commented by FilupSmith last updated on…
Question Number 138217 by otchereabdullai@gmail.com last updated on 11/Apr/21 $$\mathrm{A}\:\mathrm{rectangular}\:\mathrm{water}\:\mathrm{tank}\:\mathrm{is}\:\mathrm{being}\:\mathrm{filed} \\ $$$$\mathrm{at}\:\mathrm{the}\:\mathrm{constant}\:\mathrm{rate}\:\mathrm{of}\:\mathrm{70lt}/\mathrm{s}.\:\mathrm{The}\: \\ $$$$\mathrm{base}\:\:\mathrm{of}\:\mathrm{the}\:\mathrm{tank}\:\mathrm{has}\:\mathrm{width}\:\mathrm{w}=\mathrm{9m} \\ $$$$\mathrm{and}\:\mathrm{length}\:\mathrm{length}\:\mathrm{l}=\mathrm{16m}\:\mathrm{if}\:\mathrm{the}\:\mathrm{volume} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{tank}\:\mathrm{is}\:\mathrm{v}=\mathrm{w}×\mathrm{l}×\mathrm{h}\:\mathrm{where}\:\mathrm{h}\:\mathrm{is}\: \\ $$$$\mathrm{the}\:\mathrm{hight}\:\mathrm{of}\:\mathrm{the}\:\mathrm{tank}.\:\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{rate} \\ $$$$\mathrm{of}\:\mathrm{change}\:\mathrm{of}\:\mathrm{the}\:\mathrm{hight}\:\mathrm{of}\:\mathrm{water}\:\mathrm{in}\:\mathrm{the} \\ $$$$\mathrm{tank} \\…
Question Number 7149 by Master Moon last updated on 13/Aug/16 $$\mathrm{Find}\:\mathrm{last}\:\mathrm{digit}\:\mathrm{P} \\ $$$$\:\mathrm{P}=\left(\mathrm{2017}^{\boldsymbol{\mathrm{k}}} +\mathrm{2016}\right)\left(\mathrm{2016}^{\boldsymbol{\mathrm{m}}} +\mathrm{2015}\right)\left(\mathrm{2015}^{\boldsymbol{\mathrm{n}}} +\mathrm{2014}\right) \\ $$$$\mathrm{where}\:\boldsymbol{\mathrm{k}},\boldsymbol{\mathrm{m}},\boldsymbol{\mathrm{n}}\in{N} \\ $$$$\:\:\:\: \\ $$$$\:\:\:\:{Help}\:{me}!!! \\ $$ Terms…
Question Number 7145 by 314159 last updated on 13/Aug/16 Commented by Rasheed Soomro last updated on 13/Aug/16 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 138219 by otchereabdullai@gmail.com last updated on 11/Apr/21 $$\:\mathrm{Consider}\:\mathrm{the}\:\mathrm{function}\:\mathrm{y}=\frac{\mathrm{x}^{\mathrm{2}} +\mathrm{3x}+\mathrm{6}}{\mathrm{3x}−\mathrm{1}} \\ $$$$\left.\mathrm{1}\right)\:\mathrm{Determine}\:\mathrm{the}\:\mathrm{intercept}\:\mathrm{of}\:\mathrm{the}\:\mathrm{function} \\ $$$$\left.\mathrm{2}\right)\:\mathrm{Find}\:\mathrm{the}\:\mathrm{asymptotes}\:\mathrm{if}\:\mathrm{they}\:\mathrm{exist} \\ $$$$\left.\mathrm{3}\right)\:\mathrm{find}\:\mathrm{the}\:\mathrm{turning}\:\mathrm{point}\:\mathrm{and}\: \\ $$$$\mathrm{determine}\:\mathrm{the}\:\mathrm{type}\:\mathrm{of}\:\mathrm{turnin}\:\mathrm{point}\:\mathrm{they} \\ $$$$\mathrm{are}. \\ $$$$\left.\mathrm{4}\right)\:\mathrm{sketch}\:\mathrm{the}\:\mathrm{graph}\:\mathrm{of}\:\mathrm{the}\:\mathrm{function}. \\ $$…
Question Number 7135 by Master Moon last updated on 12/Aug/16 $$\boldsymbol{\mathrm{Prove}}\:\boldsymbol{\mathrm{that}} \\ $$$$\:\frac{\mathrm{3}}{\:\sqrt[{\mathrm{5}}]{\mathrm{2}}+\sqrt[{\mathrm{5}}]{\mathrm{3}}+\sqrt[{\mathrm{5}}]{\mathrm{5}}}\:>\:\frac{\sqrt[{\mathrm{4}}]{\mathrm{2}}+\sqrt[{\mathrm{4}}]{\mathrm{3}}+\sqrt[{\mathrm{4}}]{\mathrm{5}}}{\left(\sqrt{\mathrm{2}}+\sqrt{\mathrm{3}}+\sqrt{\mathrm{5}}\right)\left(\sqrt[{\mathrm{3}}]{\mathrm{2}}+\sqrt[{\mathrm{3}}]{\mathrm{3}}+\sqrt[{\mathrm{3}}]{\mathrm{5}}\right)} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: \\ $$$$\:\:\:{How}\:{to}\:{prove}\:{it}\:? \\ $$ Terms of Service Privacy Policy Contact:…