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can-a-function-f-be-such-that-for-a-R-f-X-a-R-a-a-X-X-R-R-gt-0-lim-x-a-f-x-lim-x-a-f-x-lt-

Question Number 1093 by 123456 last updated on 12/Jun/15 $$\mathrm{can}\:\mathrm{a}\:\mathrm{function}\:{f}\:\mathrm{be}\:\mathrm{such}\:\mathrm{that}\:\mathrm{for}\:{a}\in\mathbb{R} \\ $$$${f}:\mathrm{X}/\left\{{a}\right\}\rightarrow\mathbb{R},\left({a}−\delta,{a}+\delta\right)\in\mathrm{X},\mathrm{X}\subset\mathbb{R},\delta\in\mathbb{R},\delta>\mathrm{0} \\ $$$$\underset{{x}\rightarrow{a}} {\mathrm{lim}}\:{f}\left({x}\right)=\infty \\ $$$$\underset{{x}\rightarrow{a}} {\mathrm{lim}}\:\mid{f}'\left({x}\right)\mid<\infty \\ $$ Answered by prakash jain last…

Solve-x-2-x-4-1-x-

Question Number 132150 by mohammad17 last updated on 11/Feb/21 $${Solve}:\frac{\mid{x}+\mathrm{2}\mid}{{x}−\mathrm{4}}\leqslant\frac{\mathrm{1}}{\mid{x}\mid} \\ $$ Answered by benjo_mathlover last updated on 11/Feb/21 $$\mathrm{case}\left(\mathrm{1}\right)\:\mathrm{x}>\mathrm{0}\:\Rightarrow\:\frac{\mathrm{x}+\mathrm{2}}{\mathrm{x}−\mathrm{4}}\:−\frac{\mathrm{1}}{\mathrm{x}}\leqslant\mathrm{0} \\ $$$$\:\frac{\mathrm{x}^{\mathrm{2}} +\mathrm{2x}−\mathrm{x}+\mathrm{4}}{\mathrm{x}\left(\mathrm{x}−\mathrm{4}\right)}\leqslant\mathrm{0}\:;\:\frac{\mathrm{x}^{\mathrm{2}} +\mathrm{x}+\mathrm{4}}{\mathrm{x}\left(\mathrm{x}−\mathrm{4}\right)}\leqslant\mathrm{0} \\…

Question-66602

Question Number 66602 by aliesam last updated on 17/Aug/19 Commented by Rio Michael last updated on 17/Aug/19 $$\left.\mathrm{16}\right)\:{let}\:{y}\:=\:{x}^{\mathrm{3}} \\ $$$$\:\:\Rightarrow\:\:\frac{{dy}}{{dx}}\:=\:\mathrm{3}{x}^{\mathrm{2}} \\ $$$$\:\frac{{dy}}{{dx}}\mid_{{x}\:=\:−\mathrm{1}} \:=\:\mathrm{3} \\ $$$${when}\:{x}\:=\:−\mathrm{1}\:\:,\:{y}\:=\:−\mathrm{1}\:\:{hence}\:{pt}\:\:\left(−\mathrm{1},−\mathrm{1}\right)…

Question-66599

Question Number 66599 by aliesam last updated on 17/Aug/19 Commented by kaivan.ahmadi last updated on 17/Aug/19 $$\left({a}−{b}\right)^{\mathrm{2}} ={a}^{\mathrm{2}} −{b}^{\mathrm{2}} \Rightarrow{a}^{\mathrm{2}} −\mathrm{2}{ab}+{b}^{\mathrm{2}} ={a}^{\mathrm{2}} −{b}^{\mathrm{2}} \Rightarrow \\…

y-y-8cos-t-y-0-1-y-0-1-

Question Number 1056 by 123456 last updated on 25/May/15 $${y}''+{y}=\mathrm{8}{cos}\left({t}\right) \\ $$$${y}\left(\mathrm{0}\right)=+\mathrm{1} \\ $$$${y}'\left(\mathrm{0}\right)=−\mathrm{1} \\ $$ Commented by prakash jain last updated on 26/May/15 $$\mathrm{characterstic}\:\mathrm{equation}…

Question-132123

Question Number 132123 by mohammad17 last updated on 11/Feb/21 Answered by liberty last updated on 11/Feb/21 $$\left(\mathrm{1}\right)\mathrm{c}\: \\ $$$$\:\int_{−\mathrm{1}} ^{\:\mathrm{0}} \mathrm{0}.\mathrm{2}\:\mathrm{dy}\:+\:\underset{\mathrm{0}} {\overset{\mathrm{1}} {\int}}\:\left(\mathrm{0}.\mathrm{2}+\mathrm{cy}\right)\mathrm{dy}=\mathrm{1} \\ $$$$\left.\:\left.\mathrm{0}.\mathrm{2y}\:\right]_{−\mathrm{1}}…