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Question-68079

Question Number 68079 by azizullah last updated on 04/Sep/19 Answered by Rasheed.Sindhi last updated on 07/Sep/19 $$\begin{pmatrix}{}&{\mathrm{son}'\mathrm{s}\:\mathrm{age}}&{\mathrm{father}'\mathrm{s}\:\mathrm{age}}\\{\mathrm{Now}}&{\:\:\:\:\:\:\:\:\:\:\mathrm{x}}&{\:\:\:\:\:\:\mathrm{x}+\mathrm{36}}\\{\mathrm{10}\:\mathrm{years}\:\mathrm{ago}}&{\:\:\:\:\:\:\mathrm{x}−\mathrm{10}}&{\:\:\:\:\:\:\mathrm{x}+\mathrm{26}}\end{pmatrix}\: \\ $$$$ \\ $$$$\:\:\:\:\mathrm{x}+\mathrm{26}=\mathrm{3}\left(\mathrm{x}−\mathrm{10}\right) \\ $$$$\left.\:\:\:\:\mathrm{x}+\mathrm{26}=\mathrm{3x}−\mathrm{30}\right) \\ $$$$\:\:\:\mathrm{2x}=\mathrm{26}+\mathrm{30}=\mathrm{56}…

Question-133601

Question Number 133601 by help last updated on 23/Feb/21 Answered by benjo_mathlover last updated on 23/Feb/21 $$\:\frac{\mathrm{sin}^{\mathrm{2}} \:\theta}{\mathrm{sin}\:\theta−\mathrm{cos}\:\theta}\:+\:\frac{\mathrm{cos}\:^{\mathrm{2}} \theta}{\mathrm{cos}\:\theta−\mathrm{sin}\:\theta}\:= \\ $$$$\:\frac{\mathrm{cos}\:^{\mathrm{2}} \theta−\mathrm{sin}\:^{\mathrm{2}} \theta}{\mathrm{cos}\:\theta−\mathrm{sin}\:\theta}\:=\:\mathrm{cos}\:\theta+\mathrm{sin}\:\theta \\ $$…

S-n-0-n-2-n-1-n-3-does-S-converge-

Question Number 2497 by 123456 last updated on 21/Nov/15 $$\mathrm{S}=\underset{{n}=\mathrm{0}} {\overset{+\infty} {\sum}}\frac{{n}+\mathrm{2}}{\left({n}+\mathrm{1}\right)\left({n}+\mathrm{3}\right)} \\ $$$$\mathrm{does}\:\mathrm{S}\:\mathrm{converge}? \\ $$ Answered by prakash jain last updated on 21/Nov/15 $$\mathrm{S}=\underset{{n}=\mathrm{0}}…

x-t-cos-t-y-t-sin-t-0-t-pi-If-z-f-x-y-is-a-curtain-with-height-of-1-what-is-the-surface-area-of-the-curtain-

Question Number 2491 by Filup last updated on 21/Nov/15 $${x}\left({t}\right)=\mathrm{cos}\:{t} \\ $$$${y}\left({t}\right)=\:\mathrm{sin}\:{t} \\ $$$$\mathrm{0}\leqslant{t}\leqslant\pi \\ $$$$ \\ $$$$\mathrm{If}:\:\:\:{z}={f}\left({x},\:{y}\right)\:\:\mathrm{is}\:\mathrm{a}\:'{curtain}'\:\mathrm{with}\:\mathrm{height}\: \\ $$$$\mathrm{of}\:\mathrm{1},\:\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{surface}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:'{curtain}'? \\ $$ Commented by Yozzi…

Evaluate-n-1-1-n-1-n-1-1-2-1-3-1-4-

Question Number 2489 by Filup last updated on 21/Nov/15 $$\mathrm{Evaluate}: \\ $$$$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\left(\frac{\left(−\mathrm{1}\right)^{{n}+\mathrm{1}} }{\:\sqrt{{n}}}\right)=\mathrm{1}−\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}+\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}−\frac{\mathrm{1}}{\:\sqrt{\mathrm{4}}}+… \\ $$ Commented by Yozzi last updated on 21/Nov/15 $$\underset{{r}=\mathrm{1}}…