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Question Number 2481 by Syaka last updated on 21/Nov/15 $$\frac{\mathrm{2014}}{\mathrm{2013}}\:+\:\frac{\mathrm{2014}}{\mathrm{2013}}\:\ast\frac{\mathrm{2012}}{\mathrm{2011}}\:+\:\frac{\mathrm{2014}}{\mathrm{2013}}\:\ast\:\frac{\mathrm{2012}}{\mathrm{2011}}\:\ast\:\frac{\mathrm{2010}}{\mathrm{2009}}\:+\:\centerdot\centerdot\centerdot\centerdot\:+\:\frac{\mathrm{2014}}{\mathrm{2013}}\:\ast\:\frac{\mathrm{2012}}{\mathrm{2011}}\:\ast\:\frac{\mathrm{2010}}{\mathrm{2009}}\:\ast\:\frac{\mathrm{2008}}{\mathrm{2007}\:}\ast\centerdot\centerdot\centerdot\ast\frac{\mathrm{4}}{\mathrm{3}}\ast\frac{\mathrm{2}}{\mathrm{1}}\:−\:\mathrm{1}\:=\:\:\:\:? \\ $$ Answered by Filup last updated on 21/Nov/15 $$\mathrm{if}\:\mathrm{by}\:''\ast''\:\mathrm{you}\:\mathrm{mean}\:''×'' \\ $$$${in}\:{form}\:\left({k}=\mathrm{2014}\right): \\ $$$$ \\…

Question Number 2478 by Syaka last updated on 21/Nov/15 $${limit}\:{x}\:\rightarrow\:\infty \\ $$$$\left(\mathrm{1}\:+\:\frac{\mathrm{1}}{{x}}\right)^{{x}\:+\:\mathrm{2}} \:=\:? \\ $$ Commented by John_Haha last updated on 21/Nov/15 $${e} \\ $$…

Question Number 133518 by Abdoulaye last updated on 22/Feb/21 Answered by mnjuly1970 last updated on 22/Feb/21 $${ans}:\:\frac{\pi^{\mathrm{3}} }{\mathrm{16}} \\ $$ Answered by Dwaipayan Shikari last…

Question Number 67958 by hmamarques1994@gmai.com last updated on 02/Sep/19 $$\: \\ $$$$\:\underset{\boldsymbol{\mathrm{x}}\rightarrow\mathrm{2}} {\boldsymbol{\mathrm{lim}}}\left(\frac{\mathrm{7}^{\sqrt[{\mathrm{3}}]{\boldsymbol{\mathrm{log}}_{\boldsymbol{\mathrm{x}}} \left(\mathrm{256}\right)}} −\mathrm{49}}{\mathrm{2}^{−\sqrt{\mathrm{2}^{\boldsymbol{\mathrm{x}}} }} −\frac{\mathrm{1}}{\mathrm{4}}}\right)\:\approx\:? \\ $$$$\: \\ $$ Terms of Service Privacy…

Question Number 133485 by rydasss last updated on 22/Feb/21 Answered by guyyy last updated on 22/Feb/21 Terms of Service Privacy Policy Contact: info@tinkutara.com