Question Number 132802 by Algoritm last updated on 16/Feb/21 Commented by MJS_new last updated on 16/Feb/21 $$\mathrm{you}\:\mathrm{must}\:\mathrm{approximate} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 67215 by Learner-123 last updated on 24/Aug/19 Commented by Learner-123 last updated on 24/Aug/19 $$\:\:{help}\:{me}\:{in}\:{Q}.\mathrm{74}. \\ $$ Answered by mr W last updated…
Question Number 132747 by aurpeyz last updated on 16/Feb/21 Commented by mr W last updated on 16/Feb/21 $$\frac{\mathrm{1}}{{s}}+\frac{\mathrm{1}}{{s}'}=\frac{\mathrm{2}}{{R}} \\ $$$$\frac{\mathrm{1}}{{s}}+\frac{\mathrm{1}}{−\mathrm{2}}=\frac{\mathrm{2}}{−\mathrm{12}} \\ $$$$\frac{\mathrm{1}}{{s}}=\frac{\mathrm{1}}{\mathrm{3}} \\ $$$$\Rightarrow{s}=\mathrm{3} \\…
Question Number 132682 by otchereabdullai@gmail.com last updated on 15/Feb/21 $$\mathrm{expand}\:\mathrm{1}−\mathrm{x}^{\mathrm{8}} \\ $$ Answered by MJS_new last updated on 15/Feb/21 $$\mathrm{1}−{x}^{\mathrm{8}} =\left(\mathrm{1}−{x}^{\mathrm{4}} \right)\left(\mathrm{1}+{x}^{\mathrm{4}} \right)=\left(\mathrm{1}−{x}^{\mathrm{2}} \right)\left(\mathrm{1}+{x}^{\mathrm{2}} \right)\left(\mathrm{1}+{x}^{\mathrm{4}}…
Question Number 132683 by otchereabdullai@gmail.com last updated on 15/Feb/21 $$\mathrm{A}\:\mathrm{particle}\:\mathrm{in}\:\mathrm{a}\:\mathrm{straight}\:\mathrm{line}\:\mathrm{with} \\ $$$$\mathrm{uniform}\:\mathrm{deceleration}\:\mathrm{has}\:\mathrm{a}\:\mathrm{velocity}\:\mathrm{of} \\ $$$$\mathrm{40ms}^{−\mathrm{1}} \:\mathrm{at}\:\mathrm{point}\:\mathrm{P}\:,\:\mathrm{20ms}^{−\mathrm{1}} \:\mathrm{at}\:\mathrm{point}\:\mathrm{Q} \\ $$$$\mathrm{and}\:\mathrm{comes}\:\mathrm{to}\:\mathrm{rest}\:\mathrm{at}\:\mathrm{point}\:\mathrm{R}\:\mathrm{where}\: \\ $$$$\mathrm{QR}=\:\mathrm{50m}.\:\mathrm{calculate}\:\mathrm{the} \\ $$$$\left(\mathrm{i}\right)\:\mathrm{Distance}\:\mathrm{PQ} \\ $$$$\left(\mathrm{ii}\right)\mathrm{Time}\:\mathrm{taken}\:\mathrm{to}\:\mathrm{cover}\:\mathrm{PQ} \\…
Question Number 132674 by aurpeyz last updated on 15/Feb/21 $${integral}\:{of}\:{e}^{−\mathrm{2}{ax}^{\mathrm{2}} } \\ $$ Answered by Olaf last updated on 15/Feb/21 $$\mathrm{Let}\:\Omega_{{a}} \left({x}\right)\:=\:\int_{\mathrm{0}} ^{{x}} {e}^{−\mathrm{2}{at}^{\mathrm{2}} }…
Question Number 67122 by sandeepkeshari0797@gmail.com last updated on 23/Aug/19 Answered by Cmr 237 last updated on 23/Aug/19 $$\mathrm{y}_{\mathrm{n}+\mathrm{2}} −\mathrm{2y}_{\mathrm{n}+\mathrm{1}} +\mathrm{y}_{\mathrm{n}} −\mathrm{n}^{\mathrm{2}} \mathrm{2}^{\mathrm{n}} =\mathrm{0} \\ $$$$\mathrm{l}'\mathrm{equation}\:\mathrm{caracteristique}\:\mathrm{est}:…
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Question Number 132655 by mohammad17 last updated on 15/Feb/21 $${write}\:\frac{\left(\mathrm{1}−{i}\right)^{\mathrm{23}} }{\left(\sqrt{\mathrm{3}}−{i}\right)^{\mathrm{13}} }\:{by}\:{re}^{{i}\theta} \:{such}\:{that}\:{r}>\mathrm{0},−\pi\leqslant\theta<\pi \\ $$ Answered by physicstutes last updated on 15/Feb/21 $$\mathrm{1}\:−{i}\:=\:\sqrt{\mathrm{2}}\:{e}^{−\frac{\pi}{\mathrm{4}}{i}} \\ $$$$\Rightarrow\:\left(\mathrm{1}−{i}\right)^{\mathrm{23}}…
Question Number 132645 by aurpeyz last updated on 15/Feb/21 Terms of Service Privacy Policy Contact: info@tinkutara.com