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we-consider-that-application-n-1-det-M-n-R-R-A-det-A-1-verify-that-H-M-n-R-and-t-R-if-A-I-n-det-A-tH-1-t-Tr-H-t-2-suppose-that-A-GL-n-R-prouve-that-the-d

Question Number 134008 by AbderrahimMaths last updated on 26/Feb/21 $$\:\:\:\:{we}\:{consider}\:{that}\:{application}\:{n}\geqslant\mathrm{1} \\ $$$$\:\:{det}\::\:{M}_{{n}} \left(\mathbb{R}\right)\rightarrow\mathbb{R} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{A} {det}\left({A}\right) \\ $$$$\mathrm{1}−{verify}\:{that}\:\forall{H}\in{M}_{{n}} \left(\mathbb{R}\right)\:{and}\:{t}\in\mathbb{R} \\ $$$$\:{if}\:{A}={I}_{{n}} \Rightarrow{det}\left({A}+{tH}\right)=\mathrm{1}+{t}.{Tr}\left({H}\right)+\circ\left({t}\right) \\ $$$$\mathrm{2}−{suppose}\:{that}:\:{A}\in{GL}_{{n}} \left(\mathbb{R}\right)…

Question-134006

Question Number 134006 by mohammad17 last updated on 26/Feb/21 Answered by malwan last updated on 26/Feb/21 $$\left(\mathrm{1}\right)\:\underset{{x}\rightarrow\mathrm{4}} {{lim}}\:\frac{\mathrm{2}{x}−\mathrm{5}}{\mathrm{3}}\:=\:\frac{\mathrm{2}×\mathrm{4}−\mathrm{5}}{\mathrm{3}}\:=\:\mathrm{1} \\ $$$$\left(\mathrm{2}\right)\:\underset{{x}\rightarrow−\mathrm{3}^{+} } {{lim}}\:\frac{\sqrt{{x}+\mathrm{4}}\:−\sqrt{−{x}−\mathrm{2}}}{\:\sqrt{{x}+\mathrm{3}}}×\frac{\sqrt{{x}+\mathrm{4}}\:+\:\sqrt{−{x}−\mathrm{2}}}{\:\sqrt{{x}+\mathrm{4}}\:+\:\sqrt{−{x}−\mathrm{2}}} \\ $$$$=\:\underset{{x}\rightarrow−\mathrm{3}^{+} }…

Question-133980

Question Number 133980 by mohammad17 last updated on 26/Feb/21 Answered by mr W last updated on 26/Feb/21 $$\frac{\partial{p}}{\partial{x}}=\frac{{x}}{\:\sqrt{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} }} \\ $$$$\frac{\partial{p}}{\partial{y}}=\frac{{y}}{\:\sqrt{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}}…

Question-133961

Question Number 133961 by Ahmed1hamouda last updated on 25/Feb/21 Answered by mathmax by abdo last updated on 27/Feb/21 $$\mathrm{y}^{'} \:+\mathrm{sinx}\:\mathrm{y}=−\mathrm{x}^{\mathrm{3}} \\ $$$$\mathrm{h}\rightarrow\mathrm{y}^{'} \:+\mathrm{sinxy}=\mathrm{0}\:\Rightarrow\mathrm{y}^{'} \:=−\mathrm{sinxy}\:\Rightarrow\frac{\mathrm{y}^{'} }{\mathrm{y}}=−\mathrm{sinx}\:\Rightarrow\mathrm{ln}\mid\mathrm{y}\mid=\mathrm{cosx}\:+\mathrm{c}\:\Rightarrow…

There-are-a-few-problem-reported-Notification-google-discontinued-Google-Cloud-Messaging-so-notifications-are-not-working-Other-Problems-There-has-been-several-new-phone-models-and-android-versio

Question Number 68405 by Tinku Tara last updated on 10/Sep/19 $$\mathrm{There}\:\mathrm{are}\:\mathrm{a}\:\mathrm{few}\:\mathrm{problem}\:\mathrm{reported}. \\ $$$$\mathrm{Notification}:\:\mathrm{google}\:\mathrm{discontinued} \\ $$$$\mathrm{Google}\:\mathrm{Cloud}\:\mathrm{Messaging}\:\mathrm{so}\:\mathrm{notifications} \\ $$$$\mathrm{are}\:\mathrm{not}\:\mathrm{working}.\: \\ $$$$\mathrm{Other}\:\mathrm{Problems}: \\ $$$$\mathrm{There}\:\mathrm{has}\:\mathrm{been}\:\mathrm{several}\:\mathrm{new}\:\mathrm{phone} \\ $$$$\mathrm{models}\:\mathrm{and}\:\mathrm{android}\:\mathrm{version}\:\mathrm{updates}. \\ $$$$\mathrm{And}\:\mathrm{newer}\:\mathrm{android}\:\mathrm{version}\:\mathrm{or}\:\mathrm{phone}…