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an-object-placed-20cm-from-a-con-verving-lens-forms-a-mavnified-clear-image-on-the-screen-when-the-lens-is-moved-20cm-towards-the-screen-a-smaller-clear-image-is-formed-on-the-screen-calculate-the-

Question Number 133281 by aurpeyz last updated on 20/Feb/21 $${an}\:{object}\:{placed}\:\mathrm{20}{cm}\:{from}\:{a}\:{con}− \\ $$$${verving}\:{lens}\:{forms}\:{a}\:{mavnified}\:{clear} \\ $$$${image}\:{on}\:{the}\:{screen}.\:{when}\:{the}\:{lens} \\ $$$${is}\:{moved}\:\mathrm{20}{cm}\:{towards}\:{the}\:{screen} \\ $$$${a}\:{smaller}\:{clear}\:{image}\:{is}\:{formed}\:{on} \\ $$$${the}\:{screen}.\:{calculate}\:{the}\:{focal}\:{length} \\ $$$${of}\:{the}\:{lens} \\ $$ Terms…

Question-133242

Question Number 133242 by Kunal12588 last updated on 20/Feb/21 Commented by Kunal12588 last updated on 20/Feb/21 $$\mathrm{book}\:\mathrm{says}\:\mathrm{it}\:\mathrm{is}\:\mathrm{easy}\:\mathrm{to}\:\mathrm{show}\:\mathrm{after}\:\mathrm{that} \\ $$$$\mathrm{but}\:\mathrm{how}?\:\mathrm{also}\:\mathrm{then}\:\mathrm{we}\:\mathrm{can}\:\mathrm{prove}\:\bigtriangleup\mathrm{ADB} \\ $$$$\mathrm{is}\:\mathrm{a}\:\mathrm{36}°-\mathrm{72}°-\mathrm{72}°\:\mathrm{triangle} \\ $$ Terms of…

Give-S-n-n-1-2-n-1-k-1-n-2-k-k-Find-lim-n-S-n-

Question Number 133231 by SOMEDAVONG last updated on 20/Feb/21 $$\mathrm{Give}\:\mathrm{S}_{\mathrm{n}} =\frac{\mathrm{n}+\mathrm{1}}{\mathrm{2}^{\mathrm{n}+\mathrm{1}} }\underset{\mathrm{k}=\mathrm{1}} {\overset{\mathrm{n}} {\sum}}\frac{\mathrm{2}^{\mathrm{k}} }{\mathrm{k}}\:\:.\mathrm{Find}\:\underset{\mathrm{n}\rightarrow+\propto} {\mathrm{lim}S}_{\mathrm{n}} \:. \\ $$ Answered by Ar Brandon last updated…

I-2-x-2-1-x-4-1-dx-

Question Number 133218 by SOMEDAVONG last updated on 20/Feb/21 $$\mathrm{I}=−\int\frac{\mathrm{2}}{\left(\mathrm{x}^{\mathrm{2}} −\mathrm{1}\right)\left(\sqrt{\mathrm{x}^{\mathrm{4}} −\mathrm{1}}\right)}\mathrm{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

A-mirror-is-designed-so-that-any-ray-of-light-which-hits-one-side-of-the-mirror-and-which-is-parallel-to-a-certain-fixed-line-L-is-reflected-through-a-fixed-point-O-Prove-that-the-mirror-intersects-

Question Number 2129 by Yozzi last updated on 03/Nov/15 $${A}\:{mirror}\:{is}\:{designed}\:{so}\:{that}\:{any}\:{ray} \\ $$$${of}\:{light}\:{which}\:{hits}\:{one}\:{side}\:{of}\:{the} \\ $$$${mirror}\:{and}\:{which}\:{is}\:{parallel}\:{to}\:{a}\: \\ $$$${certain}\:{fixed}\:{line}\:{L}\:{is}\:{reflected}\:{through} \\ $$$${a}\:{fixed}\:{point}\:{O}.\:{Prove}\:{that}\:{the}\:{mirror} \\ $$$${intersects}\:{any}\:{plane}\:{containing}\:{L}\:{in} \\ $$$${a}\:{parabola}. \\ $$$${I}\:{would}\:{appreciate}\:{a}\:{formal}\:{proof}. \\…

g-x-y-x-4-y-4-2-x-y-2-find-criticals-points-of-g-x-y-and-hers-nature-

Question Number 133191 by pticantor last updated on 19/Feb/21 $$\boldsymbol{{g}}\left(\boldsymbol{{x}},\boldsymbol{{y}}\right)=\boldsymbol{{x}}^{\mathrm{4}} +\boldsymbol{{y}}^{\mathrm{4}} −\mathrm{2}\left(\boldsymbol{{x}}−\boldsymbol{{y}}\right)^{\mathrm{2}} \\ $$$$\boldsymbol{{find}}\:\boldsymbol{{criticals}}\:\boldsymbol{{points}}\:\boldsymbol{{of}}\:\boldsymbol{{g}}\left(\boldsymbol{{x}},\boldsymbol{{y}}\right) \\ $$$$\boldsymbol{{and}}\:\boldsymbol{{hers}}\:\boldsymbol{{nature}} \\ $$ Answered by Olaf last updated on 20/Feb/21…

x-2-1-3-dx-

Question Number 133183 by bounhome last updated on 19/Feb/21 $$\int\sqrt{\left({x}^{\mathrm{2}} +\mathrm{1}\right)^{\mathrm{3}} }{dx}=…? \\ $$ Answered by physicstutes last updated on 19/Feb/21 $$\mathrm{let}\:{x}\:=\:\mathrm{sinh}\:\theta\:\Rightarrow\:{dx}\:=\:\mathrm{cosh}\:\theta\:{d}\theta \\ $$$$\mathrm{now},\:\int\sqrt{\left[\left(\mathrm{sinh}\:\theta\right)^{\mathrm{2}} +\mathrm{1}\right]^{\mathrm{3}}…

1-sin-3-x-dx-

Question Number 133117 by SOMEDAVONG last updated on 19/Feb/21 $$\int\frac{\mathrm{1}}{\mathrm{sin}^{\mathrm{3}} \mathrm{x}}\mathrm{dx}=? \\ $$ Answered by bemath last updated on 19/Feb/21 $$=\:−\frac{\mathrm{1}}{\mathrm{2}}\mathrm{cot}\:\mathrm{x}\:\mathrm{csc}\:\mathrm{x}\:−\frac{\mathrm{1}}{\mathrm{2}}\mathrm{ln}\:\mid\mathrm{sec}\:\mathrm{x}−\mathrm{cot}\:\mathrm{x}\mid\:+\:\mathrm{C} \\ $$ Terms of…