Question Number 1107 by rpatle69@gmail.com last updated on 14/Jun/15 $${a}\:{square}\:{is}\:{created}\:{inside}\:{the}\: \\ $$$${circle},{which}\:{side}\:{is}\:\mathrm{4}\:{cm}.{Then}\: \\ $$$${find}\:{out}\:{the}\:{area}\:{between}\:{square} \\ $$$${and}\:{circle}. \\ $$$$ \\ $$$$ \\ $$ Answered by prakash…
Question Number 1105 by Yugi last updated on 14/Jun/15 $${Obtain}\:{the}\:{general}\:{term}\:{of}\:{each}\:{of}\:{the}\:{following}\:{sequences}\:\left({if}\:{obtainable}\right) \\ $$$${in}\:{terms}\:{of}\:\Pi\:\left({or}\:{any}\:{other}\:{form}\:{of}\:{notation}\right): \\ $$$$\left.{A}\right)\:\:\:\mathrm{1},\left(\mathrm{1}−{n}\right)\left(\mathrm{1}−\mathrm{2}{n}\right)\:,\:\left(\mathrm{1}−{n}\right)\left(\mathrm{1}−\mathrm{2}{n}\right)\left(\mathrm{1}−\mathrm{3}{n}\right)\left(\mathrm{1}−\mathrm{4}{n}\right)\:,\:\left(\mathrm{1}−{n}\right)\left(\mathrm{1}−\mathrm{2}{n}\right)\left(\mathrm{1}−\mathrm{3}{n}\right)\left(\mathrm{1}−\mathrm{4}{n}\right)\left(\mathrm{1}−\mathrm{5}{n}\right)\left(\mathrm{1}−\mathrm{6}{n}\right),\:… \\ $$$$\left.{B}\right)\:\:\:\mathrm{1},\:\mathrm{1}−{n}\:,\:\left(\mathrm{1}−{n}\right)\left(\mathrm{1}−\mathrm{2}{n}\right)\left(\mathrm{1}−\mathrm{3}{n}\right)\:,\:\left(\mathrm{1}−{n}\right)\left(\mathrm{1}−\mathrm{2}{n}\right)\left(\mathrm{1}−\mathrm{3}{n}\right)\left(\mathrm{1}−\mathrm{4}{n}\right)\left(\mathrm{1}−\mathrm{5}{n}\right),\:… \\ $$ Commented by prakash jain last updated on…
Question Number 66640 by hmamarques1994@gmail.com last updated on 18/Aug/19 $$\: \\ $$$$\:\underset{\boldsymbol{{x}}\rightarrow\mathrm{4}} {\boldsymbol{{lim}}}\:\frac{\sqrt[{\mathrm{3}}]{\mathrm{2}+\boldsymbol{{x}}\sqrt{\boldsymbol{{x}}}}−\mathrm{2}}{\mathrm{8}−\boldsymbol{{x}}\sqrt{\boldsymbol{{x}}}}=? \\ $$$$\: \\ $$ Commented by kaivan.ahmadi last updated on 18/Aug/19 $${x}\rightarrow\mathrm{4}^{+}…
Question Number 1106 by 112358 last updated on 14/Jun/15 $${Find}\:{the}\:{following}\:{sum}\:{if}\:{it}\:{converges}: \\ $$$${S}=\underset{{r}=\mathrm{0}} {\overset{\infty} {\sum}}\begin{pmatrix}{\mathrm{1}/\mathrm{2}}\\{\mathrm{2}{r}}\end{pmatrix}\:\left(−\mathrm{1}\right)^{{r}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 1096 by rpatle69@gmail.com last updated on 13/Jun/15 $${solve}\:{this} \\ $$$$\left({tanA}+{secA}−\mathrm{1}\right)/\left({tanA}−{secA}+\mathrm{1}\right) \\ $$$$=\left(\mathrm{1}+{sinA}\right)/{cosA} \\ $$$$ \\ $$ Answered by prakash jain last updated on…
Question Number 1093 by 123456 last updated on 12/Jun/15 $$\mathrm{can}\:\mathrm{a}\:\mathrm{function}\:{f}\:\mathrm{be}\:\mathrm{such}\:\mathrm{that}\:\mathrm{for}\:{a}\in\mathbb{R} \\ $$$${f}:\mathrm{X}/\left\{{a}\right\}\rightarrow\mathbb{R},\left({a}−\delta,{a}+\delta\right)\in\mathrm{X},\mathrm{X}\subset\mathbb{R},\delta\in\mathbb{R},\delta>\mathrm{0} \\ $$$$\underset{{x}\rightarrow{a}} {\mathrm{lim}}\:{f}\left({x}\right)=\infty \\ $$$$\underset{{x}\rightarrow{a}} {\mathrm{lim}}\:\mid{f}'\left({x}\right)\mid<\infty \\ $$ Answered by prakash jain last…
Question Number 132153 by Ñï= last updated on 11/Feb/21 Commented by Ar Brandon last updated on 11/Feb/21 No username ?! ���� Answered by Olaf last updated on 11/Feb/21…
Question Number 132150 by mohammad17 last updated on 11/Feb/21 $${Solve}:\frac{\mid{x}+\mathrm{2}\mid}{{x}−\mathrm{4}}\leqslant\frac{\mathrm{1}}{\mid{x}\mid} \\ $$ Answered by benjo_mathlover last updated on 11/Feb/21 $$\mathrm{case}\left(\mathrm{1}\right)\:\mathrm{x}>\mathrm{0}\:\Rightarrow\:\frac{\mathrm{x}+\mathrm{2}}{\mathrm{x}−\mathrm{4}}\:−\frac{\mathrm{1}}{\mathrm{x}}\leqslant\mathrm{0} \\ $$$$\:\frac{\mathrm{x}^{\mathrm{2}} +\mathrm{2x}−\mathrm{x}+\mathrm{4}}{\mathrm{x}\left(\mathrm{x}−\mathrm{4}\right)}\leqslant\mathrm{0}\:;\:\frac{\mathrm{x}^{\mathrm{2}} +\mathrm{x}+\mathrm{4}}{\mathrm{x}\left(\mathrm{x}−\mathrm{4}\right)}\leqslant\mathrm{0} \\…
Question Number 1073 by sai dinesh last updated on 04/Jun/15 $${what}\:{r}\:{u}\:{studying}?…{please}\:{Answer}\:{me} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 1067 by Yugi last updated on 30/May/15 $${Let}\: \\ $$$$\:\:\:\:\:\:{S}_{{N}} =\underset{{n}=\mathrm{1}} {\overset{{N}} {\sum}}\left(−\mathrm{1}\right)^{{n}−\mathrm{1}} {n}^{\mathrm{3}} \:. \\ $$$${Find}\:{S}_{\mathrm{2}{N}} \:{in}\:{terms}\:{of}\:{N}.\: \\ $$$$ \\ $$ Answered…