Question Number 137069 by 0731619177 last updated on 29/Mar/21 Answered by Ñï= last updated on 29/Mar/21 $$\left(\mathrm{1}\right){y}_{{p}} =\frac{\mathrm{1}}{{D}^{\mathrm{2}} +\mathrm{2}{D}+\mathrm{5}}\left(\mathrm{6sin}\:\mathrm{2}{x}+\mathrm{7cos}\:\mathrm{2}{x}\right) \\ $$$$=\frac{\mathrm{1}}{\mathrm{2}{D}+\mathrm{1}}\left(\mathrm{6sin}\:\mathrm{2}{x}+\mathrm{7cos}\:\mathrm{2}{x}\right)=\frac{\left(\mathrm{1}+\mathrm{2}{D}\right)}{\mathrm{9}}\left(\mathrm{6sin}\:\mathrm{2}\boldsymbol{{x}}+\mathrm{7cos}\:\mathrm{2}{x}\right) \\ $$$$=\frac{\mathrm{1}}{\mathrm{9}}\left(\mathrm{31cos}\:\mathrm{2}{x}−\mathrm{22sin}\:\mathrm{2}{x}\right) \\ $$$${y}={e}^{−{x}}…
Question Number 137056 by Ar Brandon last updated on 29/Mar/21 $$\:\:\:\:\mathrm{On}\:\mathrm{this}\:\mathrm{same}\:\mathrm{day}\:\mathrm{last}\:\mathrm{year}\:\mathrm{I}\:\mathrm{made}\:\mathrm{my}\:\mathrm{first}\:\mathrm{on}\:\mathrm{this}\:\mathrm{forum}\:\left(\mathrm{Q86484}\right) \\ $$$$\mathrm{and}\:\mathrm{I}\:\mathrm{was}\:\mathrm{very}\:\mathrm{astonished}\:\mathrm{by}\:\mathrm{the}\:\mathrm{answers}\:\mathrm{which}\:\mathrm{I}\:\mathrm{received}. \\ $$$$\mathrm{I}\:\mathrm{underestimated}\:\mathrm{the}\:\mathrm{place}\:\mathrm{at}\:\mathrm{first}\:\mathrm{before}\:\mathrm{getting}\:\mathrm{to}\:\mathrm{know}\:\mathrm{it} \\ $$$$\mathrm{better}.\:\mathrm{And}\:\mathrm{I}\:\mathrm{realised}\:\mathrm{I}\:\mathrm{knew}\:\mathrm{nothing}.\: \\ $$$$\:\:\:\:\mathrm{I}'\mathrm{m}\:\mathrm{grateful}\:\mathrm{with}\:\mathrm{all}\:\mathrm{the}\:\mathrm{teachings}\:\mathrm{which}\:\mathrm{I}'\mathrm{ve}\:\mathrm{acquired}\:\mathrm{from}\: \\ $$$$\mathrm{you}\:\mathrm{all}.\:\mathrm{You}\:\mathrm{guys}\:\mathrm{are}\:\mathrm{just}\:\mathrm{so}\:\mathrm{amazing}.\:\mathrm{Thank}\:\mathrm{you}\:\mathrm{once}\:\mathrm{more}. \\ $$$$\mathrm{Special}\:\mathrm{thanks}\:\mathrm{to}\:\mathrm{you}\:\mathrm{too}\:\mathrm{Mr}\:\mathrm{Tinku}-\mathrm{Tara}.\: \\ $$😉…
Question Number 137047 by mohammad17 last updated on 29/Mar/21 Commented by mohammad17 last updated on 29/Mar/21 $$????? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 137045 by mohammad17 last updated on 29/Mar/21 Commented by mohammad17 last updated on 29/Mar/21 $${how}\:{can}\:{it}\:{solve}\:{this} \\ $$ Commented by mohammad17 last updated on…
Question Number 5953 by 314159 last updated on 07/Jun/16 Commented by Rasheed Soomro last updated on 07/Jun/16 $$\mathcal{T}{h}\:{a}\:{nk}\mathcal{S}! \\ $$ Commented by Yozzii last updated…
Question Number 137011 by mohammad17 last updated on 28/Mar/21 Commented by mohammad17 last updated on 28/Mar/21 $${help}\:{me}\:{sir}\:{please} \\ $$ Commented by mohammad17 last updated on…
Question Number 137010 by mohammad17 last updated on 28/Mar/21 $${if}\:{f}\left({x},{y}\right)=\left({xy}\right)^{\mathrm{3}} +{e}^{{xy}} +{sec}\left(\frac{{y}}{{x}}\right)\:{find} \\ $$$${f}_{{xx}} \:\:,\:{f}_{{yy}} \:,\:{f}_{{xy}} \:\:,\:\:{f}_{{yx}} \\ $$ Commented by yutytfjh67ihd last updated on…
Question Number 136988 by mohammad17 last updated on 28/Mar/21 $${whats}\:{the}\:{intersiction}\:{of}\:{the}\:{curves}\:{r}=\frac{\mathrm{1}}{\mathrm{1}−{cos}\theta} \\ $$$$ \\ $$$${and}\:{r}=\frac{\mathrm{1}}{\mathrm{1}+{cos}\theta}\:? \\ $$ Answered by Ñï= last updated on 28/Mar/21 $${r}=\frac{\mathrm{1}}{\mathrm{1}−\mathrm{cos}\:\theta} \\…
Question Number 71439 by Mr. K last updated on 15/Oct/19 $${If}\:{a}\:{seller}\:{could}\:{purchase}\:{goods}\:{at}\:{an} \\ $$$$\mathrm{8\%}\:{lower}\:{price}\:{by}\:{keeping}\:{the}\:{selling} \\ $$$${price}\:{fixed},\:{his}\:{profit}\:{over}\:{the}\:{cost} \\ $$$${price}\:{would}\:{increase}\:{from}\:{the}\: \\ $$$${current}\:{x\%}\:{to}\:\left({x}+\mathrm{10}\right)\%.\:{So},\:{what}\:{is} \\ $$$${the}\:{value}\:{of}\:{x}? \\ $$ Commented by…
Question Number 5900 by 314159 last updated on 04/Jun/16 $${Prove}\:{that} \\ $$$${log}\:{n}!\:>\frac{\mathrm{3}{n}}{\mathrm{10}}\left(\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{4}}+…+\frac{\mathrm{1}}{{n}}−\mathrm{1}\right). \\ $$ Answered by Yozzii last updated on 05/Jun/16 $${Let}\:{for}\:{n}\in\mathbb{N},{n}\geqslant\mathrm{2},\: \\ $$$${P}\left({n}\right):\:{logn}!>\frac{\mathrm{3}{n}}{\mathrm{10}}\left(\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{4}}+…+\frac{\mathrm{1}}{{n}}−\mathrm{1}\right). \\…