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Question Number 66980 by Mr Jor last updated on 21/Aug/19 Commented by Mr Jor last updated on 21/Aug/19 $${The}\:{figure}\:{above}\:{is}\:{a}\:{right}\:{pyramid} \\ $$$${with}\:{a}\:{rectangular}\:{base}\:{ABCD}\:{and} \\ $$$${VO}\:{as}\:{the}\:{height}. \\ $$$${The}\:{vectors}\:\boldsymbol{{AD}}=\boldsymbol{{a}},\boldsymbol{{AB}}=\boldsymbol{{b}}\:{and}\:\boldsymbol{{DV}}=\boldsymbol{{c}}…

Question Number 132514 by mohammad17 last updated on 14/Feb/21 Answered by guyyy last updated on 15/Feb/21 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 1437 by 112358 last updated on 03/Aug/15 $${Let}\:{f}\left({x}\right)\:{be}\:{a}\:{real}\:{valuedfunction} \\ $$$$\forall{x}\in\mathbb{R}.\:{Determine}\:{the}\:{following} \\ $$$${sums}\:: \\ $$$$\left(\mathrm{1}\right)\:{S}_{\mathrm{1}} \left({n}\right)=\underset{{r}=\mathrm{1}} {\overset{{n}} {\sum}}{tan}^{−\mathrm{1}} \left({rf}\left({x}\right)\right) \\ $$$$\left(\mathrm{2}\right)\:{S}_{\mathrm{2}} \left({n}\right)=\underset{{r}=\mathrm{1}} {\overset{{n}} {\sum}}{sin}^{−\mathrm{1}}…

Question Number 132497 by mathocean1 last updated on 14/Feb/21 $${a},\:{b}\:\in\:\mathbb{R}. \\ $$$${Given}\:{a}^{\mathrm{3}} +{b}^{\mathrm{3}} −{ab}+\mathrm{11}=\mathrm{0} \\ $$$${Show}\:{that}\:−\frac{\mathrm{7}}{\mathrm{3}}<{a}+{b}<−\mathrm{2} \\ $$ Answered by MJS_new last updated on 14/Feb/21…

Question Number 132475 by Study last updated on 14/Feb/21 $${prove}\:{that}\:\:{x}_{\mathrm{1}} +{x}_{\mathrm{2}} =−\frac{{b}}{{a}} \\ $$$${x}_{\mathrm{1}} {and}\:{x}_{\mathrm{2}} {are}\:{roots}\:{of}\:{ax}^{\mathrm{2}} +{bx}+{c}=\mathrm{0} \\ $$ Commented by MJS_new last updated on…