Question Number 196710 by tri26112004 last updated on 30/Aug/23 $${Give}\:{the}\:{function}: \\ $$$${f}\left({x}\right)=\left({x}−\mathrm{1}\right)\left({x}−\mathrm{2}\right)^{\mathrm{2}} \left({x}−\mathrm{3}\right)^{\mathrm{3}} \left({x}−\mathrm{4}\right)^{\mathrm{4}} …\left({x}−\mathrm{2022}\right)^{\mathrm{2022}} \\ $$$${Find}\:{extremes}\:{of}\:{f}\left({x}\right)¿ \\ $$ Commented by mr W last updated…
Question Number 196659 by sonukgindia last updated on 29/Aug/23 Commented by Rasheed.Sindhi last updated on 29/Aug/23 $${Too}\:{many}\:{questions}\:{per}\:{single}\:{post}! \\ $$ Commented by Rasheed.Sindhi last updated on…
Question Number 196682 by sonukgindia last updated on 29/Aug/23 Answered by mr W last updated on 28/Sep/23 $$\mathrm{0}.\mathrm{006}×\mathrm{0}.\mathrm{98}+\mathrm{0}.\mathrm{994}×\mathrm{0}.\mathrm{8}=\mathrm{0}.\mathrm{81\%}\:\checkmark \\ $$ Terms of Service Privacy Policy…
Question Number 196705 by josemate19 last updated on 29/Aug/23 $$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\underset{−\infty} {\overset{\:\:\:\:\infty} {\int}}\frac{{n}!\mathrm{2}^{\mathrm{2}{ncos}\left(\phi\right)} }{\underset{{k}=\mathrm{1}} {\overset{\infty} {\prod}}\left(\mathrm{2}{ne}^{{i}\phi} −{k}\right)}{d}\phi \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 196637 by sonukgindia last updated on 28/Aug/23 Answered by AST last updated on 28/Aug/23 $${a}=\sqrt{\mathrm{12}−\sqrt{{m}}};{b}=\sqrt{\mathrm{12}+\sqrt{{m}}},{a}^{\mathrm{2}} +{b}^{\mathrm{2}} =\mathrm{24} \\ $$$${ab}=\sqrt{\mathrm{144}−{m}};\left({a}+{b}\right)^{\mathrm{2}} =\mathrm{24}+\mathrm{2}\sqrt{\mathrm{144}−{m}} \\ $$$$\Rightarrow{a}+{b}=\sqrt{\mathrm{24}+\mathrm{2}\sqrt{\mathrm{144}−{m}}}={n} \\…
Question Number 196635 by sonukgindia last updated on 28/Aug/23 Answered by sniper237 last updated on 28/Aug/23 $$=\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\left(−\mathrm{1}\right)^{{n}} {f}\left({n}\right)\:;\:{f}\left({z}\right)=\frac{\mathrm{1}}{\left(\mathrm{2}{z}+\mathrm{1}\right)^{\mathrm{3}} } \\ $$$$\overset{{Residu}\:{theo}\:{applicat\%}} {=}\:{Res}\left(\frac{\pi{f}\left({z}\right)}{{sin}\left(\pi{z}\right)};\:−\mathrm{1}/\mathrm{2}\right)\:\:\: \\…
Question Number 196652 by SANOGO last updated on 28/Aug/23 $${solve} \\ $$$$\mathrm{3}{x}^{\frac{\mathrm{3}}{\mathrm{2}}} \:−\mathrm{4}{x}^{\frac{\mathrm{1}}{\mathrm{2}}} \:+\mathrm{1}=\mathrm{0} \\ $$ Answered by BaliramKumar last updated on 28/Aug/23 $$ \\…
Question Number 196648 by sonukgindia last updated on 28/Aug/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 196650 by CrispyXYZ last updated on 28/Aug/23 $$\mathrm{Prove}\:\mathrm{that}\:{x}^{\mathrm{3}} ={y}^{\mathrm{6}} +\mathrm{20}\:\mathrm{has}\:\mathrm{no}\:\mathrm{positive}\:\mathrm{integer}\:\mathrm{solution}. \\ $$ Answered by AST last updated on 28/Aug/23 $${x}^{\mathrm{3}} \equiv\mathrm{1},−\mathrm{1}\:{or}\:\mathrm{0}\left({mod}\:\mathrm{9}\right) \\ $$$${when}\:\left({y},\mathrm{9}\right)=\mathrm{1};{y}^{\mathrm{6}}…
Question Number 196540 by Matica last updated on 27/Aug/23 $$\:\:{using}\:{definition}\:{of}\:{limit},\:{prove}\: \\ $$$$\:\:\:\underset{{x}\rightarrow+\infty} {\mathrm{lim}}\frac{{x}}{{x}+\mathrm{1}}\:=\:\mathrm{1} \\ $$ Answered by ERLY last updated on 27/Aug/23 $${tu}\:{appliques}\:{le}\:{monome}\:{de}\:{plus}\:{haut}\:{degre}\:{tu}\:{aura}\:{lim}\:{x}/{x}\:{ce}\:{qui}\:{donne}\:\mathrm{1}\:\:\:\:\:\:{Erly}\:{rolvinst} \\ $$…