Question Number 195704 by sonukgindia last updated on 08/Aug/23 Answered by mr W last updated on 08/Aug/23 $${A}=\left({a}+{b}\right)^{\mathrm{2}} \\ $$$${A}_{\mathrm{1}} =\frac{\left({a}+{b}\right){b}}{\mathrm{2}} \\ $$$${A}_{\mathrm{2}} =\left(\frac{{b}}{\:\sqrt{\left({a}+{b}\right)^{\mathrm{2}} +{b}^{\mathrm{2}}…
Question Number 195707 by sonukgindia last updated on 08/Aug/23 Answered by mr W last updated on 08/Aug/23 $${y}''={y}'\frac{{d}\left({y}'\right)}{{dy}} \\ $$$${p}={y}' \\ $$$${p}\frac{{dp}}{{dy}}=\frac{\mathrm{1}}{{y}^{\mathrm{3}} } \\ $$$${pdp}=\frac{{dy}}{{y}^{\mathrm{3}}…
Question Number 195702 by Humble last updated on 08/Aug/23 Answered by mr W last updated on 08/Aug/23 $$\rho_{\mathrm{1}} {gh}_{\mathrm{1}} =\rho_{\mathrm{2}} {gh}_{\mathrm{2}} \\ $$$$\Rightarrow\rho_{\mathrm{2}} =\frac{{h}_{\mathrm{1}} \rho_{\mathrm{1}}…
Question Number 195697 by sonukgindia last updated on 08/Aug/23 Answered by MM42 last updated on 08/Aug/23 $${if}\:\:{mean}\:\:\:{lim}_{{x}\rightarrow\infty} \:\sqrt[{{x}}]{{x}\:}\:\:{then} \\ $$$${A}={lim}_{{x}\rightarrow\infty} \:\sqrt[{{x}}]{{x}} \\ $$$$\Rightarrow{lnA}={lim}_{{x}\rightarrow\infty} \:\frac{{lnx}}{{x}}\:=\mathrm{0}\Rightarrow{A}=\mathrm{1} \\…
Question Number 195725 by sonukgindia last updated on 08/Aug/23 Commented by mr W last updated on 13/Aug/23 $$\Rightarrow{Q}\mathrm{195931} \\ $$ Terms of Service Privacy Policy…
Question Number 195721 by Humble last updated on 08/Aug/23 Answered by mr W last updated on 08/Aug/23 $${volume}\:{of}\:{copper}\:{V}_{{cu}} =\frac{\mathrm{25}}{\mathrm{9}.\mathrm{8}×\mathrm{8}.\mathrm{93}}=\mathrm{0}.\mathrm{286}\:{ml} \\ $$$${total}\:{volume}\:{V}=\frac{\mathrm{25}−\mathrm{20}}{\mathrm{9}.\mathrm{8}×\mathrm{1}.\mathrm{0}}=\mathrm{0}.\mathrm{510}\:{ml} \\ $$$${volume}\:{of}\:{bubble}\:{V}_{{b}} =\mathrm{0}.\mathrm{510}−\mathrm{0}.\mathrm{286}=\mathrm{0}.\mathrm{224}\:{ml} \\…
Question Number 195674 by Rodier97 last updated on 07/Aug/23 $$\:\:\:\int_{\mathrm{0}} ^{\mathrm{4}} \:\frac{{x}!}{\mathrm{5}!\left({x}−\mathrm{5}\right)!}\:{dx}\:=\:??? \\ $$ Commented by mr W last updated on 07/Aug/23 $${what}\:{do}\:{you}\:{mean}\:{with}\:\begin{pmatrix}{{x}}\\{\mathrm{5}}\end{pmatrix}\:? \\ $$…
Question Number 195681 by sonukgindia last updated on 07/Aug/23 Answered by Frix last updated on 07/Aug/23 $$=\frac{\mathrm{2}×\mathrm{3}×…×\mathrm{98}}{\mathrm{4}×\mathrm{5}×…×\mathrm{100}}=\mathrm{6}×\frac{\mathrm{98}!}{\mathrm{100}!}=\frac{\mathrm{6}}{\mathrm{99}×\mathrm{100}}=\frac{\mathrm{1}}{\mathrm{1650}} \\ $$ Answered by MM42 last updated on…
Question Number 195661 by otchereabdullai@gmail.com last updated on 06/Aug/23 Commented by otchereabdullai@gmail.com last updated on 07/Aug/23 $${thanks}\:{prof} \\ $$ Commented by mr W last updated…
Question Number 195660 by otchereabdullai@gmail.com last updated on 06/Aug/23 Commented by otchereabdullai@gmail.com last updated on 07/Aug/23 $${x} \\ $$ Commented by som(math1967) last updated on…