Question Number 195627 by Boazmbura last updated on 06/Aug/23 $$\mathrm{2}+\mathrm{2} \\ $$ Commented by Frix last updated on 06/Aug/23 $${x}=\mathrm{2}+\mathrm{2}\:\Rightarrow\:\mathrm{3}.\mathrm{97}<{x}<\mathrm{4}.\mathrm{015} \\ $$ Terms of Service…
Question Number 195608 by Rodier97 last updated on 05/Aug/23 $$ \\ $$$$ \\ $$$$ \\ $$$$\:\:\:{solve}\::\:\:\:\int_{\mathrm{0}} ^{\:\pi} \:\left(\mathrm{sin}\:{x}\right)^{\mathrm{cos}\:{x}} \:{dx} \\ $$$$ \\ $$$$ \\ $$$$…
Question Number 195578 by sonukgindia last updated on 05/Aug/23 Answered by Frix last updated on 05/Aug/23 $$\mathrm{sin}\:\alpha\:+\mathrm{cos}\:\alpha\:=\frac{\sqrt{\mathrm{3}}}{\mathrm{3}} \\ $$$${t}=\mathrm{tan}\:\alpha \\ $$$$\frac{{t}+\mathrm{1}}{\:\sqrt{{t}^{\mathrm{2}} +\mathrm{1}}}=\frac{\sqrt{\mathrm{3}}}{\mathrm{3}} \\ $$$${t}=−\frac{\mathrm{3}−\sqrt{\mathrm{5}}}{\mathrm{2}}\:\Rightarrow \\…
Question Number 195602 by mokys last updated on 05/Aug/23 $${solve}\:\int\:\frac{{dx}}{{sin}^{\mathrm{10}} \left({x}\right)+{cos}^{\mathrm{10}} \left({x}\right)} \\ $$ Answered by Frix last updated on 06/Aug/23 $$\int\frac{{dx}}{\mathrm{sin}^{\mathrm{10}} \:{x}\:+\mathrm{cos}^{\mathrm{10}} \:{x}}= \\…
Question Number 195597 by sonukgindia last updated on 05/Aug/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 195564 by sonukgindia last updated on 05/Aug/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 195515 by sulaymonnorboyev140 last updated on 04/Aug/23 $$\underset{\mathrm{1}} {\overset{\mathrm{5}} {\int}}{x}^{\mathrm{2}} \sqrt{{x}−\mathrm{1}}{dx}=? \\ $$ Answered by tri26112004 last updated on 04/Aug/23 $${Say}\:{t}=\sqrt{{x}−\mathrm{1}}\Rightarrow{t}^{\mathrm{2}} ={x}−\mathrm{1}\Leftrightarrow{x}^{\mathrm{2}} =\left({t}^{\mathrm{2}}…
Question Number 195540 by 073 last updated on 04/Aug/23 Commented by Frix last updated on 04/Aug/23 $$\left.{i}\right)\:\mathrm{1} \\ $$$$\left.{ii}\right)\:\mathrm{1} \\ $$$$\left.{iii}\right)\:\mathrm{1} \\ $$ Commented by…
Question Number 195532 by bbbbbbbb last updated on 04/Aug/23 $$\mathrm{2}^{\boldsymbol{\mathrm{x}}} −\mathrm{2}^{−\boldsymbol{\mathrm{x}}} =\mathrm{5}\:\boldsymbol{\mathrm{find}}\:\mathrm{4}^{\boldsymbol{\mathrm{x}}} +\mathrm{4}^{−\boldsymbol{\mathrm{x}}} =? \\ $$$$\boldsymbol{\mathrm{so}}\:\boldsymbol{\mathrm{soon}}\:\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{it}}\:\boldsymbol{\mathrm{i}}\:\boldsymbol{\mathrm{need}}\:\boldsymbol{\mathrm{i}}\:\boldsymbol{\mathrm{have}}\:\boldsymbol{\mathrm{rxame}}\:\boldsymbol{\mathrm{tomarrow}} \\ $$ Commented by bbbbbbbb last updated on 04/Aug/23…
Question Number 195535 by arkanshh last updated on 04/Aug/23 Answered by AST last updated on 04/Aug/23 $$\frac{{N}={A}×{B}}{{D}}=\frac{\left(\mathrm{3}^{{x}^{\mathrm{2}} } −\mathrm{3}^{{x}+\mathrm{6}} \right)\left(\mathrm{5}^{{x}} −\mathrm{25}\right)}{\mathrm{4}^{{x}^{\mathrm{2}} \left(\mathrm{3}−{x}\right)} −\mathrm{4}^{\mathrm{3}−{x}} }\geqslant\mathrm{0}\left({Equality}\:{at}\:{x}=\mathrm{2},−\mathrm{2}\right) \\…