Question Number 195521 by bbbbbbbb last updated on 04/Aug/23 $$\mathrm{2}^{\boldsymbol{\mathrm{a}}} =\mathrm{50}\:\:\:\:\boldsymbol{\mathrm{find}}\:\mathrm{2}^{\mathrm{2}\boldsymbol{\mathrm{a}}−\mathrm{2}} =? \\ $$$$\boldsymbol{\mathrm{soon}}\:\boldsymbol{\mathrm{as}}\:\boldsymbol{\mathrm{soon}}\:\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{this}}\:\boldsymbol{\mathrm{i}}\:\boldsymbol{\mathrm{need}}\:\boldsymbol{\mathrm{so}} \\ $$ Answered by Calculusboy last updated on 04/Aug/23 $$\mathrm{625} \\…
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Question Number 195491 by sonukgindia last updated on 03/Aug/23 Answered by aleks041103 last updated on 03/Aug/23 $${obviously}\:{x}_{{n}} =\mathrm{1}\:{for}\:\forall{n}\in\mathbb{N} \\ $$$$\Rightarrow{x}_{{n}} \rightarrow\mathrm{1} \\ $$ Terms of…
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Question Number 195490 by 073 last updated on 03/Aug/23 Commented by 073 last updated on 03/Aug/23 $$\mathrm{solution}\:\mathrm{please}???? \\ $$ Commented by TheHoneyCat last updated on…
Question Number 195421 by MathedUp last updated on 02/Aug/23 $$\mathrm{Calculate}.\:\:\int_{\mathrm{0}} ^{\:\infty} \:\:\frac{\mathrm{sin}\left({z}\right)}{{z}\left({z}^{\mathrm{2}} +\mathrm{1}\right)}\mathrm{d}{z} \\ $$$$\mathrm{method}\:\mathrm{1}.\:\mathrm{using}\:\mathrm{Laplace}\:\mathrm{Transform}. \\ $$$$\mathrm{method}\:\mathrm{2}.\:\mathrm{using}\:\mathrm{Contour}\:\mathrm{Integral}. \\ $$$$\mathrm{method}\:\mathrm{3}.\:\mathrm{using}\:\mathrm{Feymann}'\mathrm{s}\:\mathrm{parametirc}\:\mathrm{trick} \\ $$$$\mathrm{HELP}!!!!!!! \\ $$ Answered by…
Question Number 195453 by Rodier97 last updated on 02/Aug/23 $$\:\:\:\:\mathrm{lim}_{{x}\rightarrow+\infty\:\:} \:{x}\:{ln}\left(\frac{{e}^{{x}} +\:\mathrm{1}}{{e}^{{x}} −\mathrm{1}}\right)\:\:? \\ $$ Commented by Frix last updated on 02/Aug/23 $$\mathrm{0} \\ $$…
Question Number 195415 by Calculusboy last updated on 02/Aug/23 Answered by Frix last updated on 02/Aug/23 $$\mathrm{No}\:\mathrm{solution}\:\mathrm{exists}\:\mathrm{for}\:{x}\in\mathbb{C} \\ $$ Commented by Frix last updated on…
Question Number 195446 by sonukgindia last updated on 02/Aug/23 Answered by Frix last updated on 02/Aug/23 $$\sqrt{{a}+{b}\mathrm{i}}=\frac{\sqrt{{a}+\sqrt{{a}^{\mathrm{2}} +{b}^{\mathrm{2}} }}}{\:\sqrt{\mathrm{2}}}+\mathrm{sign}\:{b}\:\frac{\sqrt{−{a}+\sqrt{{a}^{\mathrm{2}} +{b}^{\mathrm{2}} }}}{\:\sqrt{\mathrm{2}}}\mathrm{i} \\ $$$$\sqrt{−\mathrm{110}+\mathrm{66i}}=\sqrt{\mathrm{11}\left(−\mathrm{5}+\sqrt{\mathrm{34}}\right)}+\mathrm{i}\sqrt{\mathrm{11}\left(\mathrm{5}+\sqrt{\mathrm{34}}\right)} \\ $$…
Question Number 195414 by tri26112004 last updated on 02/Aug/23 $${x}^{{n}} +\frac{\mathrm{1}}{{x}^{{n}} }=¿ \\ $$ Answered by Frix last updated on 02/Aug/23 $$=\mathrm{2cosh}\:\left({n}\mathrm{ln}\:{x}\right) \\ $$ Commented…