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Question Number 542 by 123456 last updated on 25/Jan/15 $${\int }_0^1\frac{x^2}{\sqrt{x^6+4}}dx$$ Answered by prakash jain last updated on 24/Jan/15 $${x}^{\mathrm{3}}…

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Question Number 131554 by Salman_Abir last updated on 06/Feb/21 Commented by EDWIN88 last updated on 06/Feb/21 $$\mathrm{A}-\mathrm{B}=\left[\begin{array}{c}-211\\ 216\end{array}\right]$$$$\mathrm{A}\times {\mathrm{B}}^{\mathrm{T}}=\left[\begin{array}{c}234\\ 157\end{array}\right]\left[\begin{array}{c}4-1\\ 24\\ 31\end{array}\right]$$$$=\left[\begin{array}{c}8+6+12-2+12+4\\ 4+10+21-1+20+7\end{array}\right]$$ Terms…

Question Number 456 by Karting7442 last updated on 25/Jan/15 $$solveforx:\frac{1}{2}x+6=11$$$$$$ Answered by prakash jain last updated on 09/Jan/15 $$\frac{1}{2}x+6=11$$$$\frac{\mathrm{1}}{\mathrm{2}}{x}=\mathrm{11}−\mathrm{6}…

Question Number 65992 by naka3546 last updated on 07/Aug/19 $$x=\frac{1}{3\cdot 1!}+\frac{1}{4\cdot 2!}+\frac{1}{5\cdot 3!}+\dots +\frac{1}{1002\cdot 1000!}$$$$x\cdot 1000!=?$$ Commented by Prithwish sen last updated on 08/Aug/19 $$\mathrm{last}\mathrm{term}\frac{\mathrm{n}}{(\mathrm{n}+1)!}\mathrm{where}\mathrm{n}=1001$$$$\therefore\:\left[\frac{\mathrm{n}+\mathrm{1}−\mathrm{1}}{\left(\mathrm{n}+\mathrm{1}\right)!}\right]\:=\:\frac{\mathrm{1}}{\mathrm{n}!}\:−\:\frac{\mathrm{1}}{\left(\mathrm{n}+\mathrm{1}\right)!}…