Question Number 195094 by sonukgindia last updated on 24/Jul/23 Answered by witcher3 last updated on 24/Jul/23 $$\mathrm{no}\:\mathrm{close}\:\mathrm{forme} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 195083 by sciencestudentW last updated on 23/Jul/23 $${x}=\sqrt{\mathrm{5}}−\mathrm{2}\:\:\:\:\: \\ $$$${x}+\frac{\mathrm{1}}{{x}}=? \\ $$ Answered by Rasheed.Sindhi last updated on 23/Jul/23 $${x}=\sqrt{\mathrm{5}}−\mathrm{2}\:\:,\:\:{x}+\frac{\mathrm{1}}{{x}}=? \\ $$$$\frac{\mathrm{1}}{{x}}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{5}}−\mathrm{2}}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{5}}−\mathrm{2}}\centerdot\frac{\sqrt{\mathrm{5}}\:+\mathrm{2}}{\:\sqrt{\mathrm{5}}\:+\mathrm{2}} \\…
Question Number 195079 by sonukgindia last updated on 23/Jul/23 Answered by witcher3 last updated on 24/Jul/23 $$\mathrm{we}\:\mathrm{applie}\:\mathrm{S}_{\mathrm{n}} \:\mathrm{to}\:\mathrm{this}\:\mathrm{sum}\:\mathrm{witch}\:\mathrm{symetric}\:\mathrm{Groupe}\:\mathrm{of} \\ $$$$\mathrm{n}\:\mathrm{element}\:\mathrm{we}\:\mathrm{not}\:\mathrm{this}\:\mathrm{elements}\:\sigma \\ $$$$\mathrm{cardS}_{\mathrm{n}} =\mathrm{n}!;\left\{\mathrm{1}…..\mathrm{n}\right\}\overset{\sigma} {\rightarrow}\left\{\mathrm{1},….,\mathrm{n}\right\} \\…
Question Number 195038 by sciencestudentW last updated on 22/Jul/23 $${prove}\:{that}\:{x}+{y}=\frac{\mathrm{1}}{{x}−{y}} \\ $$ Commented by Frix last updated on 22/Jul/23 $$\mathrm{It}'\mathrm{s}\:\mathrm{wrong},\:\mathrm{i}.\mathrm{e}.\:{x}=\mathrm{2}\wedge{y}=\mathrm{3}\:\Rightarrow\: \\ $$$${x}+{y}=\mathrm{5}\:\mathrm{but}\:\frac{\mathrm{1}}{{x}−{y}}=−\mathrm{1} \\ $$$$ \\…
Question Number 195035 by mathlove last updated on 22/Jul/23 $$\sqrt{{i}}=? \\ $$ Answered by alephzero last updated on 22/Jul/23 $$\sqrt{{i}}\:=\:? \\ $$$$\left(\sqrt{{i}}\right)^{\mathrm{2}} \:=\:{i} \\ $$$${e}^{{i}\pi}…
Question Number 195020 by tri26112004 last updated on 22/Jul/23 $${y}={x}^{{x}^{{x}…} } \\ $$$$=>\:\frac{{dy}}{{dx}}=¿ \\ $$ Answered by Frix last updated on 22/Jul/23 $${y}={x}^{{x}^{{x}…} } \\…
Question Number 195012 by sonukgindia last updated on 22/Jul/23 Answered by a.lgnaoui last updated on 23/Jul/23 Commented by a.lgnaoui last updated on 23/Jul/23 Answered by…
Question Number 195042 by sonukgindia last updated on 22/Jul/23 Answered by MM42 last updated on 22/Jul/23 $$\mathrm{260}=\mathrm{2}^{\mathrm{8}} +\mathrm{2}^{\mathrm{2}} \\ $$$$\Rightarrow\mathrm{2}^{\mathrm{16}^{{sin}^{\mathrm{2}} {x}} } =\mathrm{2}^{\mathrm{8}} \:\:\&\:\:\mathrm{2}^{\mathrm{16}^{{cos}^{\mathrm{2}} {x}}…
Question Number 194971 by kapoorshah last updated on 21/Jul/23 Commented by Frix last updated on 21/Jul/23 $$\mathrm{I}\:\mathrm{think}\:\left({abc}\right)^{\mathrm{2}} =\mathrm{8} \\ $$ Commented by sniper237 last updated…
Question Number 194931 by sonukgindia last updated on 20/Jul/23 Answered by HeferH last updated on 20/Jul/23 Commented by HeferH last updated on 20/Jul/23 $$\mathrm{6}{x}\:=\:\mathrm{2}\left(\mathrm{180}°−\mathrm{7}{x}\right) \\…