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Question Number 194654 by sonukgindia last updated on 12/Jul/23 Answered by MM42 last updated on 12/Jul/23 $$\left(\left(\mathrm{3}+\mathrm{2}\sqrt{\mathrm{2}}\right)^{{tanx}} \right)^{{tanx}+\mathrm{2}} ={u} \\ $$$$\Rightarrow{u}+\frac{\mathrm{1}}{{u}}=\mathrm{6}\Rightarrow{u}^{\mathrm{2}} −\mathrm{6}{u}+\mathrm{1}=\mathrm{0} \\ $$$$\Rightarrow{u}=\mathrm{3}\pm\mathrm{2}\sqrt{\mathrm{2}} \\…

Question Number 194662 by SANOGO last updated on 12/Jul/23 $$\int_{\mathrm{0}} ^{\frac{\Pi}{\mathrm{2}}} \sqrt{\mathrm{4}{sin}^{\mathrm{2}} {t}+{cos}^{\mathrm{2}} {t}}\:\:{dt} \\ $$ Commented by Frix last updated on 12/Jul/23 $$\mathrm{Same}\:\mathrm{as}\:\mathrm{before}: \\…

Question Number 194568 by MathedUp last updated on 10/Jul/23 $$\mathrm{Equation}.. \\ $$$${J}_{\boldsymbol{\mu}} ^{\left(\mathrm{1}\right)} \left({z}\right){Y}_{\boldsymbol{\mu}} \left({z}\right)−{J}_{\boldsymbol{\mu}} \left({z}\right){Y}_{\boldsymbol{\mu}} ^{\left(\mathrm{1}\right)} \left({z}\right)=−\frac{\mathrm{2}}{\pi{z}} \\ $$$$\mathrm{plz}……\mathrm{Solve}\:\mathrm{this}\:\mathrm{Equation}……. \\ $$$${J}_{\boldsymbol{\mu}} \left({z}\right)\:\mathrm{is}\:\mathrm{First}\:\mathrm{Kind}\:\mathrm{Bessel}\:\mathrm{Function} \\ $$$${Y}_{\boldsymbol{\mu}}…

Question Number 194593 by pascal889 last updated on 10/Jul/23 Answered by MM42 last updated on 10/Jul/23 $${u}_{{n}} ={u}_{{n}−\mathrm{1}} +{n}+\mathrm{1}\:\:\:;{n}\geqslant\mathrm{2}\:\:,\:\:\:{u}_{\mathrm{1}} =\mathrm{4} \\ $$$${u}_{{n}} ={u}_{{n}−\mathrm{1}} +\left({n}+\mathrm{1}\right) \\…

Question Number 194536 by Kiyanoush last updated on 09/Jul/23 $$\overset{\underline{ }} {\:} \\ $$ Commented by MM42 last updated on 09/Jul/23 $$\: \\ $$ Commented…