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Question Number 196007 by sonukgindia last updated on 15/Aug/23 Answered by mr W last updated on 15/Aug/23 $${AC}=\frac{{R}}{\mathrm{tan}\:\frac{\alpha}{\mathrm{2}}} \\ $$$$\overset{\frown} {{BC}}=\left(\pi−\alpha\right){R} \\ $$$$\left(\pi−\alpha\right){R}=\frac{{R}}{\mathrm{tan}\:\frac{\alpha}{\mathrm{2}}} \\ $$$$\left(\pi−\alpha\right)\:\mathrm{tan}\:\frac{\alpha}{\mathrm{2}}=\mathrm{1}…

Question Number 195973 by sonukgindia last updated on 14/Aug/23 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 195954 by sonukgindia last updated on 13/Aug/23 Answered by mahdipoor last updated on 13/Aug/23 $$\frac{\mathrm{1}}{\mathrm{4}}×\frac{\left(\mathrm{4}−{a}\right)−{x}}{{x}+\left({a}−\mathrm{2}\right)}×\frac{\left(\mathrm{4}−{a}\right)+{x}}{−{x}+\left({a}−\mathrm{2}\right)}={c} \\ $$$${c}=\frac{\mathrm{1}}{\mathrm{4}}\:\Rightarrow\:\begin{cases}{\mathrm{4}−{a}=\mathrm{2}−{a}\Rightarrow\nexists}\\{\mathrm{4}−{a}={a}−\mathrm{2}\Rightarrow{a}=\mathrm{3}}\end{cases} \\ $$ Answered by Rasheed.Sindhi last…

Question Number 195900 by Calculusboy last updated on 12/Aug/23 Answered by cortano12 last updated on 13/Aug/23 $$\:\:\:\left[\:\frac{\mathrm{1}}{\mathrm{3}}\mathrm{x}^{\mathrm{3}} +\frac{\mathrm{1}}{\mathrm{2}}\mathrm{x}^{\mathrm{2}} \:\right]_{−\mathrm{2}} ^{\mathrm{b}} =\frac{\mathrm{16}}{\mathrm{3}} \\ $$$$\:\:\:\left[\frac{\mathrm{1}}{\mathrm{2}}\mathrm{x}^{\mathrm{2}} \left(\frac{\mathrm{2}}{\mathrm{3}}\mathrm{x}+\mathrm{1}\right)\:\right]_{−\mathrm{2}} ^{\mathrm{b}}…

Question Number 195883 by Humble last updated on 12/Aug/23 $$\mathrm{The}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{a}\:\mathrm{boat}\:\mathrm{is}\:\mathrm{given}\:\mathrm{by},\:\mathrm{V}=\mathrm{k}\left(\frac{\mathrm{l}}{\mathrm{t}}−\mathrm{at}\right), \\ $$$$\mathrm{where}\:\mathrm{k}\:\mathrm{is}\:\mathrm{the}\:\mathrm{constant}\:\mathrm{and}\:\mathrm{l}\:\mathrm{is}\:\mathrm{the}\:\mathrm{distance} \\ $$$$\mathrm{travel}\:\mathrm{by}\:\mathrm{boat}\:\mathrm{in}\:\mathrm{time}\:\mathrm{t}\:\mathrm{and}\:\mathrm{a}\:\mathrm{is}\:\mathrm{the}\:\mathrm{acceleration}\:\mathrm{of}\:\mathrm{water}.\: \\ $$$$\mathrm{If}\:\mathrm{there}\:\mathrm{is}\:\mathrm{a}\:\mathrm{change}\:\mathrm{in}\:\mathrm{l}\:\mathrm{from}\:\mathrm{2cm}\:\mathrm{to}\:\mathrm{1cm}\:\mathrm{in}\:\mathrm{time}\:\mathrm{2sec}.\:\mathrm{to}\:\mathrm{1sec}.\:\mathrm{If}\:\mathrm{the}\:\mathrm{acceleration} \\ $$$$\mathrm{of}\:\mathrm{water}\:\mathrm{changes}\:\mathrm{from}\:\mathrm{0}.\mathrm{95m}/\mathrm{s}^{\mathrm{2}} \:\mathrm{to}\:\mathrm{2m}/\mathrm{s}^{\mathrm{2}} .\:\mathrm{Find}\:\mathrm{the}\:\mathrm{motion}\:\mathrm{of}\:\mathrm{boat}. \\ $$ Terms of Service…