Question Number 111704 by Aina Samuel Temidayo last updated on 04/Sep/20 $$\mathrm{Assuming}\:\mathrm{FLT},\:\mathrm{prove}\:\mathrm{Fermat}−\mathrm{Euler} \\ $$$$\mathrm{theorem}:\:\left(\mathrm{a},\mathrm{n}\right)\:=\mathrm{1},\mathrm{n}\geqslant\mathrm{2}\Rightarrow\mathrm{a}^{\emptyset\left(\mathrm{n}\right)} \equiv\mathrm{1}\left(\mathrm{mod}\right. \\ $$$$\left.\mathrm{n}\right) \\ $$ Answered by Aina Samuel Temidayo last…
Question Number 46157 by Tawa1 last updated on 21/Oct/18 $$\mathrm{Please}\:\mathrm{help}. \\ $$$$\:\:\:\:\:\mathrm{Find}\:\mathrm{all}\:\mathrm{the}\:\mathrm{general}\:\mathrm{solution}\:\mathrm{of}\:\:\:\:\:\:\:\mathrm{6x}\:+\:\mathrm{8y}\:+\:\mathrm{5z}\:=\:\mathrm{101}\:. \\ $$$$ \\ $$$$\mathrm{I}\:\mathrm{got}:\:\:\:\:\:\:\:\:\mathrm{x}\:=\:−\:\mathrm{48}\:+\:\mathrm{45m}\:+\:\mathrm{4n} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{y}\:=\:\:\:\:\:\mathrm{48}\:+\:\mathrm{45m}\:−\:\mathrm{3n} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{z}\:=\:\:\:\:\:\:\:\mathrm{1}\:−\:\mathrm{2m} \\ $$$$ \\ $$$$\mathrm{Please}\:\mathrm{help}.\:\:\mathrm{Am}\:\mathrm{confused}.\: \\…
Question Number 111541 by Aina Samuel Temidayo last updated on 04/Sep/20 $$\mathrm{How}\:\mathrm{many}\:\mathrm{natural}\:\mathrm{numbers}\:\mathrm{less}\:\mathrm{than} \\ $$$$\mathrm{1000}\:\mathrm{have}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{their}\:\mathrm{digits}\:\mathrm{equal} \\ $$$$\mathrm{to}\:\mathrm{5}? \\ $$ Answered by nimnim last updated on 04/Sep/20…
Question Number 111537 by Aina Samuel Temidayo last updated on 04/Sep/20 $$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{minimum}\:\mathrm{value}\:\mathrm{obtained} \\ $$$$\mathrm{when}\:\mathrm{an}\:\mathrm{arbitrary}\:\mathrm{number}\:\mathrm{of}\:\mathrm{three} \\ $$$$\mathrm{different}\:\mathrm{non}−\mathrm{zero}\:\mathrm{digits}\:\mathrm{is}\:\mathrm{divided} \\ $$$$\mathrm{by}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{its}\:\mathrm{digits}? \\ $$$$ \\ $$ Answered by 1549442205PVT…
Question Number 111503 by Aina Samuel Temidayo last updated on 04/Sep/20 $$\mathrm{Find}\:\mathrm{four}\:\mathrm{values}\:\mathrm{of}\:\mathrm{n}\:\mathrm{satisfying} \\ $$$$\mathrm{1}\leqslant\mathrm{n}\leqslant\mathrm{2000}\:\mathrm{and}\:\mathrm{2}^{\mathrm{n}} =\mathrm{n}^{\mathrm{2}} \left(\mathrm{mod}\:\mathrm{1024}\right) \\ $$ Answered by 1549442205PVT last updated on 04/Sep/20…
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Question Number 111159 by Rasheed.Sindhi last updated on 02/Sep/20 $${z}\:{is}\:{a}\:{complex}\:{number}\:{with}\: \\ $$$${Re}\left({z}\right)\:,\:{Im}\left({z}\right)\in\mathbb{N}. \\ $$$${Determine}\:{z}\:\:{if} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{z}.\overset{−} {{z}}=\mathrm{1000} \\ $$ Answered by Sarah85 last updated on…
Question Number 111155 by Aina Samuel Temidayo last updated on 02/Sep/20 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{number}\:\mathrm{of}\:\mathrm{rational}\:\mathrm{numbers} \\ $$$$\mathrm{r},\:\mathrm{0}<\mathrm{r}<\mathrm{1},\:\mathrm{such}\:\mathrm{that}\:\mathrm{when}\:\mathrm{r}\:\mathrm{is}\:\mathrm{written} \\ $$$$\mathrm{as}\:\mathrm{a}\:\mathrm{fraction}\:\mathrm{in}\:\mathrm{lowest}\:\mathrm{term}.\:\mathrm{The} \\ $$$$\mathrm{numerator}\:\mathrm{and}\:\mathrm{the}\:\mathrm{denominator} \\ $$$$\mathrm{have}\:\mathrm{a}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{1000}. \\ $$ Answered by Her_Majesty…
Question Number 110984 by Rasheed.Sindhi last updated on 01/Sep/20 $$\mathrm{GCD}\:{of}\:{two}\:{unequal}\:\:{numbers}\:{can}'{t}\: \\ $$$${exceed}\:{their}\:{absolute} \\ $$$${difference}.\:\:{Prove}. \\ $$ Commented by mr W last updated on 01/Sep/20 $${not}\:{true}\:{if}\:{both}\:{numbers}\:{are}\:{equal}.…
Question Number 45439 by Tawa1 last updated on 12/Oct/18 $$\mathrm{Show}\:\mathrm{that}\:\mathrm{the}\:\mathrm{square}\:\mathrm{of}\:\mathrm{every}\:\mathrm{odd}\:\mathrm{integer}\:\mathrm{is}\:\mathrm{of}\:\mathrm{the}\:\mathrm{form}\:\:\:\mathrm{8m}\:+\:\mathrm{1} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 13/Oct/18 $$\left(\mathrm{2}{k}+\mathrm{1}\right)^{\mathrm{2}} =\mathrm{4}{k}^{\mathrm{2}} +\mathrm{4}{k}+\mathrm{1} \\ $$$$=\mathrm{4}{k}\left({k}+\mathrm{1}\right)+\mathrm{1} \\…