Question Number 26508 by gunawan last updated on 26/Dec/17 $$\mathrm{A}=\left\{\frac{{m}}{{n}}+\frac{\mathrm{8}{n}}{{m}}\::\:{m},\:{n}\:\in\:{N}\right\},\:\mathrm{N}=\:\mathrm{Natural}\:\mathrm{numbers} \\ $$$$\mathrm{find}\:\mathrm{sup}\left(\mathrm{A}\right)\:\mathrm{and}\:\mathrm{inf}\left(\mathrm{A}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
If-GCD-a-b-1-and-GCD-c-d-1-a-b-c-d-1-a-lt-b-c-lt-d-is-it-possible-that-a-b-c-d-is-an-integer-number-
Question Number 26410 by Joel578 last updated on 25/Dec/17 $$\mathrm{If}\:\:{GCD}\left({a},{b}\right)\:=\:\mathrm{1}\:\mathrm{and}\:{GCD}\left({c},\:{d}\right)\:=\:\mathrm{1} \\ $$$${a}\:\neq\:{b}\:\neq\:{c}\:\neq\:{d}\:\neq\:\mathrm{1},\:\:{a}\:<\:{b},\:\:{c}\:<\:{d} \\ $$$$\mathrm{is}\:\mathrm{it}\:\mathrm{possible}\:\mathrm{that}\:\:\frac{{a}}{{b}}\:+\:\frac{{c}}{{d}}\:\mathrm{is}\:\mathrm{an}\:\mathrm{integer}\:\mathrm{number}? \\ $$ Answered by mrW1 last updated on 25/Dec/17 $${since}\:{gcd}\left({c},{d}\right)=\mathrm{1},\:\frac{{c}}{{d}}\:{is}\:{already}\:{reduced} \\…
Question Number 157219 by amin96 last updated on 21/Oct/21 $$\underset{\mathrm{0}<\boldsymbol{\mathrm{n}}} {\sum}\frac{\left(−\mathrm{1}\right)^{\boldsymbol{\mathrm{n}}−\mathrm{1}} \boldsymbol{\mathrm{n}}}{\boldsymbol{\mathrm{sinh}}\left(\pi\boldsymbol{\mathrm{n}}\right)}=\frac{\mathrm{1}}{\mathrm{4}\pi}\:\:\:\:{prove} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 91448 by Cynosure last updated on 30/Apr/20 $${prove}\:{that}\:\mathrm{1}+{x}^{\mathrm{111}} +{x}^{\mathrm{222}} +{x}^{\mathrm{333}} +{x}^{\mathrm{444}} \:\:{divides}\:\mathrm{1}+\:{x}^{\mathrm{111}} +{x}^{\mathrm{222}} +{x}^{\mathrm{333}} +…….+{x}^{\mathrm{999}} \\ $$ Commented by Cynosure last updated on…
Question Number 91439 by Cynosure last updated on 30/Apr/20 $${solve}\:\mathrm{2}{x}^{\mathrm{99}} +\mathrm{3}{x}^{\mathrm{98}} +\mathrm{2}{x}^{\mathrm{97}} +\mathrm{3}{x}^{\mathrm{96}} +…..\mathrm{2}{x}+\mathrm{3}=\mathrm{0}\:{in}\:\mathbb{R} \\ $$ Commented by Cynosure last updated on 30/Apr/20 $${pls}\:{i}\:{need}\:{answer} \\…
Question Number 156419 by cortano last updated on 11/Oct/21 $$\mathrm{x}\:\mathrm{is}\:\mathrm{positive}\:\mathrm{integer}\:\mathrm{number}\: \\ $$$$\mathrm{can}\:\mathrm{you}\:\mathrm{check}\:\mathrm{if}\:\mathrm{Q}=\sqrt[{\mathrm{3}}]{\left(\left(\mathrm{x}+\mathrm{2}\right)^{\mathrm{4}} −\mathrm{x}^{\mathrm{4}} \right.} \\ $$$$\mathrm{is}\:\mathrm{a}\:\mathrm{natural}\:\mathrm{number} \\ $$ Commented by mr W last updated on…
Question Number 90698 by jagoll last updated on 25/Apr/20 $${how}\:{many}\:{solution}\:{the}\:{equation} \\ $$$$\lfloor\:{x}\:\rfloor\:+\mathrm{2016}.\:\left\{{x}\right\}\:=\:\mathrm{38}? \\ $$ Commented by mr W last updated on 25/Apr/20 $${in}\:{general} \\ $$$$\lfloor\:{x}\:\rfloor\:+{n}\left\{{x}\right\}\:=\:{m}…
Question Number 25152 by tawa tawa last updated on 05/Dec/17 $$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{real}\:\mathrm{part}\:\mathrm{and}\:\mathrm{imaginary}\:\mathrm{part}\:\mathrm{of}\:\mathrm{the}\:\mathrm{complex}\:\mathrm{number}:\:\:\:\:\mathrm{z}\:=\:\left(\mathrm{1}\:+\:\mathrm{i}\right)^{\mathrm{i}} \\ $$ Commented by tawa tawa last updated on 05/Dec/17 $$\mathrm{please}\:\mathrm{help}. \\ $$ Answered…
Question Number 156201 by VIDDD last updated on 09/Oct/21 $$\:\:{A}=\left[\sqrt[{\mathrm{n}}]{\mathrm{x}^{\mathrm{n}} \sqrt[{\mathrm{n}}]{\mathrm{x}^{\mathrm{n}^{\mathrm{2}} } \sqrt[{\mathrm{n}}]{\mathrm{x}^{\mathrm{n}^{\mathrm{3}} } \centerdot\centerdot\centerdot\centerdot\sqrt[{\mathrm{n}}]{\mathrm{x}^{\mathrm{n}^{\mathrm{n}} } }}}}\right]^{\frac{\mathrm{1}}{\mathrm{n}}} \\ $$ Commented by talminator2856791 last updated on…
Question Number 156126 by VIDDD last updated on 08/Oct/21 $$\:\:\:\mathrm{cos}\frac{\pi}{\mathrm{5}}=…?\:\:\mathrm{with}\:\mathrm{solution}\:\mathrm{pls} \\ $$ Commented by cortano last updated on 08/Oct/21 $$\frac{\pi}{\mathrm{5}}=\mathrm{36}°\:\Rightarrow\mathrm{cos}\:\mathrm{72}°=\mathrm{2cos}\:\mathrm{36}°−\mathrm{1} \\ $$$$\Rightarrow\mathrm{cos}\:\mathrm{36}°=\sqrt{\frac{\mathrm{1}+\mathrm{cos}\:\mathrm{72}°}{\mathrm{2}}}=\sqrt{\frac{\mathrm{1}+\mathrm{sin}\:\mathrm{18}°}{\mathrm{2}}} \\ $$ Answered…