Question Number 86240 by Rio Michael last updated on 27/Mar/20 $$\mathrm{use}\:\mathrm{the}\:\mathrm{Chinese}\:\mathrm{Remainder}\:\mathrm{theorem}\:\mathrm{to}\:\mathrm{find} \\ $$$$\:\:{x}\:\mathrm{such}\:\mathrm{that} \\ $$$$\:{x}\:\equiv\:\mathrm{2}\left(\mathrm{mod}\:\mathrm{3}\right) \\ $$$$\mathrm{2}{x}\:\equiv\:\mathrm{3}\left(\mathrm{mod}\:\mathrm{5}\right) \\ $$$$\:\mathrm{3}{x}\equiv\:\mathrm{4}\left(\:\mathrm{mod}\:\mathrm{7}\right) \\ $$ Answered by mr W…
Question Number 151265 by liberty last updated on 19/Aug/21 Commented by Tawa11 last updated on 19/Aug/21 $$\mathrm{Weldone}\:\mathrm{sir}. \\ $$ Commented by liberty last updated on…
Question Number 85668 by Rio Michael last updated on 23/Mar/20 $$\mathrm{z}\:=\:\mathrm{2}\:+\:\mathrm{i}\: \\ $$$$\mathrm{find}\:\mathrm{arg}\left(\mathrm{z}\right) \\ $$ Commented by mathmax by abdo last updated on 24/Mar/20 $$\mid{z}\mid=\sqrt{\mathrm{2}^{\mathrm{2}}…
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Question Number 150965 by EDWIN88 last updated on 17/Aug/21 Answered by john_santu last updated on 17/Aug/21 $$\mathrm{R}=\frac{\mathrm{1}}{\mathrm{2}}\mathrm{log}\:_{\mathrm{10}} \mathrm{x}\:=\:\frac{\mathrm{1}}{\mathrm{2}}\mathrm{P}^{\mathrm{2}} \\ $$$$\mathrm{S}=\frac{\mathrm{1}}{\mathrm{2}}\mathrm{log}\:_{\mathrm{10}} \mathrm{y}=\frac{\mathrm{1}}{\mathrm{2}}\mathrm{Q}^{\mathrm{2}} \\ $$$$\Leftrightarrow\mathrm{P}+\mathrm{Q}+\mathrm{R}+\mathrm{S}\:=\:\mathrm{24}\: \\ $$$$\Leftrightarrow\mathrm{P}+\mathrm{Q}+\frac{\mathrm{1}}{\mathrm{2}}\mathrm{P}^{\mathrm{2}}…
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Question Number 85261 by Umar last updated on 20/Mar/20 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\left(\mathrm{1}+\sqrt{−\mathrm{3}}\right)^{\frac{\mathrm{3}}{\mathrm{4}}} \\ $$$$ \\ $$$$\mathrm{help}\:\mathrm{please} \\ $$ Commented by mathmax by abdo last updated on 20/Mar/20…
Question Number 19631 by Tinkutara last updated on 13/Aug/17 $$\mathrm{Two}\:\mathrm{different}\:\mathrm{prime}\:\mathrm{numbers}\:\mathrm{between} \\ $$$$\mathrm{4}\:\mathrm{and}\:\mathrm{18}\:\mathrm{are}\:\mathrm{chosen}.\:\mathrm{When}\:\mathrm{their}\:\mathrm{sum}\:\mathrm{is} \\ $$$$\mathrm{subtracted}\:\mathrm{from}\:\mathrm{their}\:\mathrm{product}\:\mathrm{then}\:\mathrm{a} \\ $$$$\mathrm{number}\:{x}\:\mathrm{is}\:\mathrm{obtained}\:\mathrm{which}\:\mathrm{is}\:\mathrm{a} \\ $$$$\mathrm{multiple}\:\mathrm{of}\:\mathrm{17}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{digits}\:\mathrm{of} \\ $$$$\mathrm{number}\:{x}. \\ $$ Answered by ajfour…
Question Number 19389 by tawa tawa last updated on 10/Aug/17 $$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{digital}\:\mathrm{root}\:\mathrm{of}\:\:\mathrm{3}^{\mathrm{2017}} \\ $$ Answered by allizzwell23 last updated on 10/Aug/17 $$\:\:\:\mathrm{1}×\mathrm{9}\:=\:\mathrm{9} \\ $$$$\:\:\:\mathrm{2}×\mathrm{9}\:=\:\mathrm{18}\:=\:\mathrm{1}+\mathrm{8}\:=\:\mathrm{9} \\ $$$$\:\:\:\mathrm{3}×\mathrm{9}\:=\:\mathrm{27}\:=\:\mathrm{2}+\mathrm{7}\:=\:\mathrm{9}…
Question Number 19239 by Tinkutara last updated on 07/Aug/17 $$\mathrm{Assume}\:\mathrm{that}\:{a},\:{b},\:{c}\:\mathrm{and}\:{d}\:\mathrm{are}\:\mathrm{positive} \\ $$$$\mathrm{integers}\:\mathrm{such}\:\mathrm{that}\:{a}^{\mathrm{5}} \:=\:{b}^{\mathrm{4}} ,\:{c}^{\mathrm{3}} \:=\:{d}^{\mathrm{2}} \:\mathrm{and} \\ $$$${c}\:−\:{a}\:=\:\mathrm{19}.\:\mathrm{Determine}\:{d}\:−\:{b}. \\ $$ Answered by ajfour last updated…