Question Number 18135 by Tinkutara last updated on 15/Jul/17 $$\mathrm{Let}\:{x}\:\mathrm{be}\:\mathrm{the}\:\mathrm{LCM}\:\mathrm{of}\:\mathrm{3}^{\mathrm{2002}} \:−\:\mathrm{1}\:\mathrm{and} \\ $$$$\mathrm{3}^{\mathrm{2002}} \:+\:\mathrm{1}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{last}\:\mathrm{digit}\:\mathrm{of}\:{x}. \\ $$ Commented by mrW1 last updated on 15/Jul/17 $$\mathrm{0} \\…
Question Number 148951 by EDWIN88 last updated on 01/Aug/21 $${Let}\:{complex}\:{number}\:{z}=\left({a}+\mathrm{cos}\:\theta\right)+\left(\mathrm{2}{a}−\mathrm{sin}\:\theta\right){i}\:. \\ $$$${If}\:\mid{z}\mid\:\leqslant\mathrm{2}\:{for}\:{any}\:\theta\in{R}\:{then}\:{the} \\ $$$${range}\:{of}\:{real}\:{number}\:{a}\:{is}\:\_\_\_ \\ $$ Answered by iloveisrael last updated on 01/Aug/21 Answered by…
Question Number 83289 by Cmr 237 last updated on 29/Feb/20 $$\:\:{solve} \\ $$$$\boldsymbol{{log}}_{\left(\mathrm{24}\boldsymbol{{sinx}}\right)} \left(\mathrm{24}\boldsymbol{{cosx}}\right)=\frac{\mathrm{3}}{\mathrm{2}} \\ $$ Answered by TANMAY PANACEA last updated on 29/Feb/20 $$\frac{{ln}\mathrm{24}{cosx}}{{ln}\mathrm{24}{sinx}}=\frac{\mathrm{3}}{\mathrm{2}}…
Question Number 17446 by Tinkutara last updated on 05/Jul/17 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{integer}\:\mathrm{closest}\:\mathrm{to} \\ $$$$\mathrm{100}\left(\mathrm{12}\:−\:\sqrt{\mathrm{143}}\right). \\ $$ Commented by ajfour last updated on 06/Jul/17 $$\mathrm{100}\left(\mathrm{12}−\sqrt{\mathrm{143}}\right)=\frac{\mathrm{100}}{\mathrm{12}+\sqrt{\mathrm{143}}} \\ $$$$\:\:\approx\frac{\mathrm{100}}{\mathrm{24}}\:\approx\:\mathrm{4}.\mathrm{2}\: \\…
Question Number 17303 by RasheedSoomro last updated on 03/Jul/17 $$\mathrm{What}\:\mathrm{are}\:\mathrm{next}\:\mathrm{three}\:\mathrm{numbers} \\ $$$$\mathrm{in}\:\mathrm{the}\:\mathrm{following}\:\mathrm{sequence}: \\ $$$$\mathrm{4},\mathrm{6},\mathrm{12},\mathrm{18},\mathrm{30},\mathrm{42},\mathrm{60},… \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 17272 by RasheedSoomro last updated on 03/Jul/17 $$\mathrm{Determine}\:\mathrm{two}\:\mathrm{distinct}\:\mathrm{primes}\:\:\:\mathrm{p}\:\:\:\mathrm{and}\:\:\:\mathrm{q}\: \\ $$$$\mathrm{such}\:\mathrm{that}: \\ $$$$\left(\mathrm{i}\right)\:\mathrm{p}+\mathrm{q}+\mathrm{1},\mathrm{p}+\mathrm{q}−\mathrm{1},\frac{\mathrm{p}+\mathrm{q}}{\mathrm{2}}\:\in\:\mathbb{P}\:\left(\mathrm{All}\:\mathrm{primes}\right)? \\ $$$$\left(\mathrm{ii}\right)\:\mathrm{p}+\mathrm{q}+\mathrm{1},\mathrm{p}+\mathrm{q}−\mathrm{1},\frac{\mathrm{p}+\mathrm{q}}{\mathrm{2}},\frac{\mathrm{p}−\mathrm{q}}{\mathrm{2}}\:\in\:\mathbb{P}\:\left(\mathrm{All}\:\mathrm{primes}\right)? \\ $$ Commented by prakash jain last updated on…
Question Number 17252 by Tinkutara last updated on 02/Jul/17 $$\mathrm{The}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{the}\:\mathrm{digits}\:\mathrm{of}\:\mathrm{the}\:\mathrm{number} \\ $$$$\mathrm{2}^{\mathrm{2000}} \mathrm{5}^{\mathrm{2004}} \:\mathrm{is} \\ $$$$\mathrm{Will}\:\mathrm{it}\:\mathrm{be}\:\mathrm{13}\:\mathrm{or}\:\mathrm{14}? \\ $$ Commented by prakash jain last updated on…
Question Number 148211 by Tawa11 last updated on 26/Jul/21 Answered by Kamel last updated on 26/Jul/21 $${W}_{\mathrm{0}} \left({x}\right),\:\:\mid{x}\mid<\frac{\mathrm{1}}{{e}}. \\ $$ Terms of Service Privacy Policy…
Question Number 17142 by RasheedSoomro last updated on 01/Jul/17 $$\mathrm{Find}\:\mathrm{two}\:\mathrm{primes}\:{a}\:\mathrm{and}\:{b}\:\mathrm{such} \\ $$$$\mathrm{that}\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:{a}−{b}=\mathrm{995} \\ $$ Commented by prakash jain last updated on 01/Jul/17 $$\mathrm{All}\:\mathrm{prime}\:\mathrm{except}\:\mathrm{2}\:\mathrm{are}\:\mathrm{odd}.…
Question Number 82628 by jagoll last updated on 23/Feb/20 $${If}\:{a},{b},\:{c}\:{are}\:{in}\:{Harmonic}\:{progression} \\ $$$${find}\:{the}\:{value}\:{of}\:\frac{{a}+{b}}{{b}−{a}}\:+\:\frac{{b}+{c}}{{b}−{c}}\:.\:? \\ $$ Commented by $@ty@m123 last updated on 23/Feb/20 $$\frac{\mathrm{1}}{{a}},\:\frac{\mathrm{1}}{{b}},\frac{\mathrm{1}}{{c}}\:{are}\:{in}\:{AP} \\ $$$$\Rightarrow\frac{\mathrm{1}}{{b}}−\frac{\mathrm{1}}{{a}}=\frac{\mathrm{1}}{{c}}−\frac{\mathrm{1}}{{b}}=\boldsymbol{{d}},\:{say} \\…