Question Number 347 by 123456 last updated on 23/Dec/14 $$\mathrm{1}−\frac{\mathrm{2}}{\mathrm{3}−\frac{\mathrm{4}}{\mathrm{5}−\ddots}}\overset{?} {=}\mathrm{1} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 348 by 123456 last updated on 23/Dec/14 $${a}_{{n}} =\mathrm{1}−\frac{\mathrm{2}}{\mathrm{3}−\frac{\mathrm{4}}{\mathrm{5}−{n}}},{n}\equiv\mathrm{1}\left(\mathrm{mod}\:\mathrm{2}\right) \\ $$$${a}_{{n}} =\mathrm{1}−\frac{\mathrm{2}}{\mathrm{3}−\frac{\mathrm{4}}{\mathrm{5}−\frac{\mathrm{6}}{{n}}}},{n}\equiv\mathrm{0}\left(\mathrm{mod}\:\mathrm{2}\right) \\ $$$$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\:{a}_{{n}} \overset{?} {=}\mathrm{1} \\ $$ Commented by 123456 last…
Question Number 215 by 123456 last updated on 25/Jan/15 $$\mathrm{evaluate} \\ $$$$\mathrm{1}+\mathrm{2}^{\mathrm{3}} +\mathrm{3}^{\mathrm{4}^{\mathrm{5}} } \left(\mathrm{mod}\:\mathrm{10}\right) \\ $$ Answered by prakash jain last updated on 16/Dec/14…
Question Number 187 by 123456 last updated on 25/Jan/15 $$\mathrm{solve}\:\mathrm{for}\:\mathrm{integer}\:{x},{y} \\ $$$$\mathrm{4}{x}^{\mathrm{2}} −\mathrm{9}{y}^{\mathrm{2}} =\mathrm{6} \\ $$ Answered by ghosea last updated on 16/Dec/14 $$\left(\mathrm{2}{x}−\mathrm{3}{y}\right)\left(\mathrm{2}{x}+\mathrm{3}{y}\right)=\mathrm{2}\centerdot\mathrm{3}\:{or}\:\mathrm{1}.\mathrm{6}\:{or}\:−\mathrm{1},−\mathrm{6}\:{or}−\mathrm{2},−\mathrm{3} \\…
Question Number 190 by 123456 last updated on 25/Jan/15 $$\mathrm{solve}\:\mathrm{30x}\equiv\mathrm{50}\left(\mathrm{mod}\:\mathrm{40}\right) \\ $$ Answered by mreddy last updated on 15/Dec/14 $$\mathrm{30}{x}+\mathrm{40}{y}=\mathrm{50} \\ $$$$\mathrm{3}{x}+\mathrm{4}{y}=\mathrm{5} \\ $$$$\mathrm{general}\:\mathrm{solution} \\…
Question Number 185 by 123456 last updated on 25/Jan/15 $$\mathrm{solve}\:\mathrm{10x}\equiv\mathrm{25}\left(\mathrm{mod}\:\mathrm{15}\right) \\ $$ Answered by mreddy last updated on 14/Dec/14 $$\mathrm{gcd}\left(\mathrm{10},\mathrm{15}\right)=\mathrm{5}\:\mathrm{and}\:\mathrm{5}\:\mathrm{divided}\:\mathrm{25}\:\mathrm{so}\: \\ $$$$\mathrm{there}\:\mathrm{are}\:\mathrm{5}\:\mathrm{solutions} \\ $$$$\mathrm{Solutions}\:\mathrm{are}\:\mathrm{given}\:\mathrm{by}\:\mathrm{equation} \\…
Question Number 176 by 123456 last updated on 25/Jan/15 $$\mathrm{find}\:\mathrm{the}\:\mathrm{integer}\:\mathrm{solution}\:\mathrm{of}\:\mathrm{3x}+\mathrm{4y}=\mathrm{5} \\ $$ Answered by prakash jain last updated on 14/Dec/14 $$\mathrm{gcd}\left(\mathrm{3},\mathrm{4}\right)=\mathrm{1}\:\mathrm{and}\:\mathrm{1}\:\mathrm{divides}\:\mathrm{5}\:\mathrm{so}\:\mathrm{it}\:\mathrm{is}\:\mathrm{solvable}. \\ $$$$\mathrm{Particular}\:\mathrm{solution}\:{x}=\mathrm{3},\:{y}=−\mathrm{1} \\ $$$$\mathrm{General}\:\mathrm{solution}…
Question Number 177 by 123456 last updated on 25/Jan/15 $$\mathrm{solve}\:\mathrm{12x}\equiv\mathrm{34}\left(\mathrm{mod}\:\mathrm{56}\right) \\ $$ Answered by prakash jain last updated on 14/Dec/14 $$\mathrm{gcd}\left(\mathrm{12},\mathrm{56}\right)=\mathrm{4}\: \\ $$$$\mathrm{4}\:\mathrm{does}\:\mathrm{not}\:\mathrm{divide}\:\mathrm{34}\:\mathrm{so}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{has}\:\mathrm{no}\:\mathrm{solutions}. \\ $$…
Question Number 170 by 123456 last updated on 25/Jan/15 $$\mathrm{solve}\:\mathrm{12x}\equiv\mathrm{25}\left(\mathrm{mod}\:\mathrm{69}\right) \\ $$ Answered by prakash jain last updated on 14/Dec/14 $$\mathrm{gcd}\left(\mathrm{12},\mathrm{69}\right)=\mathrm{3} \\ $$$$\mathrm{3}\:\nmid\:\mathrm{25},\:\mathrm{3}\:\mathrm{does}\:\mathrm{not}\:\mathrm{divide}\:\mathrm{25}\:\mathrm{hence}\:\mathrm{there} \\ $$$$\mathrm{is}\:\mathrm{no}\:\mathrm{solution}.…
Question Number 139 by shaleen last updated on 25/Jan/15 $$\boldsymbol{{express}}\:\boldsymbol{{the}}\:\boldsymbol{{folowing}}\:\boldsymbol{{in}}\:\boldsymbol{{the}}\mathrm{0}.\mathrm{6}\left(\boldsymbol{{bar}}\right)= \\ $$$$\boldsymbol{{form}}\:\boldsymbol{{of}}\:\boldsymbol{{p}}/\boldsymbol{{q}}\:;{where}\:{p}\:{and}\:{q} \\ $$$${are}\:{integers}\:{and}\:{q}\:{is}\:{not}\:=\mathrm{0} \\ $$$$\mathrm{0}.\bar {\mathrm{6}} \\ $$ Answered by vkulkarni last updated on…