Question Number 125666 by fajri last updated on 12/Dec/20 $${solution}\:: \\ $$$$ \\ $$$${x}'\:=\:\begin{pmatrix}{−\mathrm{2}\:\:\:\:\:\:\:\:\mathrm{1}}\\{\mathrm{1}\:\:\:\:\:\:\:\:−\mathrm{2}}\end{pmatrix}{x}\:+\:\begin{pmatrix}{\mathrm{2}{e}^{−{m}} }\\{\mathrm{3}{m}}\end{pmatrix} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 125042 by kaivan.ahmadi last updated on 07/Dec/20 $$\mathrm{2}+\mathrm{2}+\mathrm{2}=\mathrm{6} \\ $$$$ \\ $$$$\mathrm{3}×\mathrm{3}−\mathrm{3}=\mathrm{6} \\ $$$$ \\ $$$$\sqrt{\mathrm{4}}+\sqrt{\mathrm{4}}+\sqrt{\mathrm{4}}=\mathrm{6} \\ $$$$ \\ $$$$\mathrm{5}\:+\:\mathrm{5}\:\boldsymbol{\div}\:\mathrm{5}\:=\mathrm{6} \\ $$$$ \\…
Question Number 190569 by cortano12 last updated on 06/Apr/23 $$\:\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{4}−\mathrm{digit}\: \\ $$$$\:\mathrm{numbers}\:\mathrm{that}\:\mathrm{contain}\:\mathrm{the} \\ $$$$\:\mathrm{number}\:\mathrm{6}\:\mathrm{and}\:\mathrm{are}\:\mathrm{divisible}\: \\ $$$$\:\mathrm{by}\:\mathrm{3}\:\mathrm{is}\:\_\_\_ \\ $$ Answered by talminator2856792 last updated on 06/Apr/23…
Question Number 190568 by cortano12 last updated on 06/Apr/23 Commented by Rasheed.Sindhi last updated on 11/Apr/23 $${The}\:{greatest}\:{value}\:{of}\:{n}=\mathrm{169}\:\left({p}=\mathrm{29}\right) \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 190544 by cortano12 last updated on 05/Apr/23 $$\mathrm{Given}\:\mathrm{p},\mathrm{q},\mathrm{r},\mathrm{s}\:\mathrm{sre}\:\mathrm{distinc}\:\mathrm{prime}\:\mathrm{numbers} \\ $$$$\:\mathrm{such}\:\mathrm{that}\:\mathrm{pq}−\mathrm{rs}\:\mathrm{divisible}\:\mathrm{by}\:\mathrm{30}. \\ $$$$\:\mathrm{minimum}\:\mathrm{value}\:\mathrm{of}\:\mathrm{p}+\mathrm{q}+\mathrm{r}+\mathrm{s}\:=? \\ $$ Commented by Frix last updated on 06/Apr/23 $$\mathrm{It}'\mathrm{s}\:\mathrm{just}\:\mathrm{trying}… \\…
Question Number 124944 by udaythool last updated on 07/Dec/20 $$\mathrm{1}.\:\left({a},\:{m}\right)=\left({b},\:{m}\right)=\mathrm{1}\Rightarrow\left({ab},\:{m}\right)=\mathrm{1} \\ $$$$\mathrm{2}.\:{c}\mid{ab}\:\mathrm{and}\:\left({c},\:{a}\right)=\mathrm{1}\Rightarrow{c}\mid{b} \\ $$$$\mathrm{3}.\:\mathrm{If}\:{c}\:\mathrm{is}\:\mathrm{a}\:\mathrm{common}\:\mathrm{multiple}\:\mathrm{of} \\ $$$${a}\:\mathrm{and}\:{b}\:\mathrm{then}\:\left[{a},\:{b}\right]\mid{c} \\ $$$$\mathrm{4}.\:\left[{ma},\:{mb}\right]={m}\left[{a},\:{b}\right]\:\mathrm{for}\:\mathrm{all}\:\mathrm{int}\:{m}>\mathrm{0} \\ $$$$\mathrm{5}.\:\left[{a},\:{b}\right]\left({a},\:{b}\right)=\mid{ab}\mid \\ $$$$\mathrm{6}.\:\mathrm{Let}\:{g}>\mathrm{0},\:{s}\:\mathrm{be}\:\mathrm{integers}.\:\mathrm{Show} \\ $$$$\mathrm{that}\:{g}\mid{s}\:\mathrm{iff}\:\exists\:\mathrm{integers}\:{x},\:{y}\:\mathrm{such} \\…
Question Number 124795 by benjo_mathlover last updated on 06/Dec/20 Answered by mathmax by abdo last updated on 17/Dec/20 $$\mathrm{p}\:\mathrm{prime}\:\Rightarrow\mathrm{Z}/\mathrm{pZ}\:\mathrm{is}\:\mathrm{a}\:\mathrm{corps}\:\:\mathrm{we}\:\mathrm{have}\:\:\mathrm{for}\:\mathrm{alla}_{\mathrm{i}} \:\in\:\mathrm{Z}/\mathrm{pZ} \\ $$$$\left(\mathrm{a}_{\mathrm{1}} +\mathrm{a}_{\mathrm{2}} +…+\mathrm{a}_{\mathrm{n}} \right)^{\mathrm{p}}…
Question Number 190285 by Abdullahrussell last updated on 31/Mar/23 Commented by ARUNG_Brandon_MBU last updated on 31/Mar/23 #include <stdio.h> int main(void) { unsigned int a, b; for (a = 100; a<1000; a++) { for (b = 300; b<1000; b++) { if (1001*a+1 == b*b) goto loopend; } } loopend: printf ("a = %u, b = %u", a, b); return 0; } Commented by ARUNG_Brandon_MBU last updated on 31/Mar/23 Output: a = 183, b = 428…
Question Number 190286 by Abdullahrussell last updated on 31/Mar/23 Answered by talminator2856792 last updated on 31/Mar/23 $$\:\:{b}^{\mathrm{2}} \:−\:\mathrm{1}\:=\:\mathrm{1001}{a} \\ $$$$\:\:\left({b}\:−\:\mathrm{1}\right)\left({b}\:+\:\mathrm{1}\right)\:=\:\mathrm{1001}{a} \\ $$$$\:\:\frac{\left({b}\:−\:\mathrm{1}\right)\left({b}\:+\:\mathrm{1}\right)}{\mathrm{1001}}\:=\:{a} \\ $$$$\:\:\frac{\left({b}\:−\:\mathrm{1}\right)\left({b}\:+\:\mathrm{1}\right)}{\mathrm{7}\:×\:\mathrm{11}\:×\:\mathrm{13}\:}\:=\:{a} \\…
Question Number 124130 by soumyasaha last updated on 01/Dec/20 $$ \\ $$$$\:\:\mathrm{Let}\:\:\mathrm{P}\:=\:\left(\:\mathrm{3}\sqrt{\mathrm{6}}\:+\:\mathrm{7}\:\right)^{\mathrm{89}} \:\mathrm{and}\:\:\:\mathrm{F}\:\mathrm{is}\:\mathrm{fractional} \\ $$$$\:\:\mathrm{part}\:\mathrm{of}\:\:\mathrm{P}. \\ $$$$\:\:\mathrm{Then}\:\mathrm{find}\:\mathrm{the}\:\mathrm{remainder}\:\mathrm{when} \\ $$$$\:\:\:\left(\mathrm{PF}\right)\:+\:\left(\mathrm{PF}\right)^{\mathrm{2}} \:+\:\left(\mathrm{PF}\right)^{\mathrm{3}} \:\mathrm{is}\:\mathrm{divided}\:\mathrm{by}\:\mathrm{31}. \\ $$ Answered by…