Question Number 191862 by cortano12 last updated on 02/May/23 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{last}\:\mathrm{digit}\:\mathrm{from}\: \\ $$$$\:\left(\mathrm{2}^{\mathrm{400}} −\mathrm{2}^{\mathrm{320}} \right)\left(\mathrm{2}^{\mathrm{200}} +\mathrm{2}^{\mathrm{160}} \right)\left(\mathrm{2}^{\mathrm{200}} −\mathrm{2}^{\mathrm{160}} \right) \\ $$ Commented by BaliramKumar last updated…
Question Number 191846 by malwan last updated on 01/May/23 $${find}\:{the}\:{last}\:{three}\:{digits} \\ $$$${of}\:\mathrm{4}^{\mathrm{2}^{\mathrm{42}} } \\ $$$${Mohammed}\:{Alwan} \\ $$ Answered by AST last updated on 01/May/23 $$\mathrm{4}^{\mathrm{2}^{\mathrm{42}}…
Question Number 126269 by liberty last updated on 19/Dec/20 $${If}\:{n}\:{is}\:{an}\:{odd}\:{integer}\:,\:{show}\:{that}\:\mathrm{32} \\ $$$${divides}\:\left({n}^{\mathrm{2}} +\mathrm{3}\right)\left({n}^{\mathrm{3}} +\mathrm{7}\right)\:?\: \\ $$ Answered by MJS_new last updated on 19/Dec/20 $$\mathrm{not}\:\mathrm{true}\:\mathrm{for}\:{n}=\mathrm{3} \\…
Question Number 191710 by pete last updated on 29/Apr/23 $$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{remainder}\:\mathrm{f}\:\mathrm{149}!\:\mathrm{when}\:\mathrm{divided} \\ $$$$\mathrm{by}\:\mathrm{139}? \\ $$ Commented by Rasheed.Sindhi last updated on 29/Apr/23 $$\mathrm{149}!=\mathrm{1}.\mathrm{2}.\mathrm{3}…\mathrm{138}.\mathrm{139}.\mathrm{140}…\mathrm{148}.\mathrm{149} \\ $$$$\therefore\:\mathrm{149}!\mathrm{mod139}=\mathrm{0} \\…
Question Number 191680 by pete last updated on 28/Apr/23 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{remainder}\:\mathrm{of}\:\mathrm{67}!\:\mathrm{when}\:\mathrm{divided} \\ $$$$\mathrm{by}\:\mathrm{7}! \\ $$ Answered by JDamian last updated on 28/Apr/23 $${zero} \\ $$$$ \\…
Question Number 125959 by bramlexs22 last updated on 15/Dec/20 Answered by liberty last updated on 15/Dec/20 $${Let}\:{q}\:{denote}\:{the}\:{numbers}\:{of}\:{eggs}\:{originally} \\ $$$${in}\:{the}\:{basket}.\:{We}\:{want}\:{to}\:{find}\:{the}\:{least}\:{number} \\ $$$${of}\:{eggs}\:{in}\:{the}\:{basket}.\: \\ $$$$\Leftrightarrow\:{q}\:\equiv\:\mathrm{1}\left({mod}\:\mathrm{2}\right)\:\equiv\:\mathrm{1}\left({mod}\:\mathrm{3}\right)\equiv\:\mathrm{1}\left({mod}\:\mathrm{5}\right)\:\equiv\:\mathrm{0}\:\left({mod}\:\mathrm{7}\right) \\ $$$${the}\:{first}\:{three}\:{congruences}\:{then}…
Question Number 191232 by BaliramKumar last updated on 21/Apr/23 $$\mathrm{If}\:{x}^{\mathrm{2}} \:−\:{y}^{\mathrm{2}} \:=\:\mathrm{2023}^{\mathrm{2023}} \:\mathrm{then}\:\mathrm{how}\:\mathrm{many}\: \\ $$$$\mathrm{pair}\:\mathrm{of}\:{x},{y}\:{where}\:{x},\:{y}\:\in\:\mathrm{N} \\ $$ Answered by mr W last updated on 21/Apr/23…
Question Number 125666 by fajri last updated on 12/Dec/20 $${solution}\:: \\ $$$$ \\ $$$${x}'\:=\:\begin{pmatrix}{−\mathrm{2}\:\:\:\:\:\:\:\:\mathrm{1}}\\{\mathrm{1}\:\:\:\:\:\:\:\:−\mathrm{2}}\end{pmatrix}{x}\:+\:\begin{pmatrix}{\mathrm{2}{e}^{−{m}} }\\{\mathrm{3}{m}}\end{pmatrix} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 125042 by kaivan.ahmadi last updated on 07/Dec/20 $$\mathrm{2}+\mathrm{2}+\mathrm{2}=\mathrm{6} \\ $$$$ \\ $$$$\mathrm{3}×\mathrm{3}−\mathrm{3}=\mathrm{6} \\ $$$$ \\ $$$$\sqrt{\mathrm{4}}+\sqrt{\mathrm{4}}+\sqrt{\mathrm{4}}=\mathrm{6} \\ $$$$ \\ $$$$\mathrm{5}\:+\:\mathrm{5}\:\boldsymbol{\div}\:\mathrm{5}\:=\mathrm{6} \\ $$$$ \\…
Question Number 190569 by cortano12 last updated on 06/Apr/23 $$\:\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{4}−\mathrm{digit}\: \\ $$$$\:\mathrm{numbers}\:\mathrm{that}\:\mathrm{contain}\:\mathrm{the} \\ $$$$\:\mathrm{number}\:\mathrm{6}\:\mathrm{and}\:\mathrm{are}\:\mathrm{divisible}\: \\ $$$$\:\mathrm{by}\:\mathrm{3}\:\mathrm{is}\:\_\_\_ \\ $$ Answered by talminator2856792 last updated on 06/Apr/23…